Hardy-Weinberg Equilibrium (College Board AP® Biology): Study Guide

Ruth Brindle

Written by: Ruth Brindle

Reviewed by: Cara Head

Updated on

Conditions for Hardy-Weinberg equilibrium

  • The Hardy-Weinberg principle states that, if certain conditions are met,then the allele frequencies of a gene within a population will not change from one generation to the next

  • The Hardy-Weinberg equation allows for the calculation of allele and genotype frequencies within populations

  • It also allows for predictions to be made about how these frequencies will change in future generations

  • Conditions that must be met for the Hardy-Weinberg principle to hold true include:

    • a large population size

    • no migration into or out of the population

    • no mutations give rise to new alleles

    • mating is random

    • natural selection is not acting on the population

  • The assumptions listed are very rarely, if ever, all present in nature

  • Despite this, the Hardy-Weinberg equilibrium concept can provide a useful null hypothesis when evaluating the effects of genetic changes

The Hardy-Weinberg equation

  • If the phenotype of a trait in a population is determined by a single gene with only two alleles (we will use B / b as examples throughout this section), then the population will consist of individuals with three possible genotypes:

    • Homozygous dominant (BB)

    • Heterozygous (Bb)

    • Homozygous recessive (bb)

  •  When using the Hardy-Weinberg equation, the frequency of a genotype is represented as a proportion of the population

    • For example, the BB genotype could be 0.40

    • Whole population = 1

    • The letter p represents the frequency of the dominant allele (B)

    • The letter q represents the frequency of the recessive allele (b)

    • As there are only two alleles at a single gene locus for this phenotypic trait in the population:

p + q = 1

  • The chance of an individual being homozygous dominant is p2

    • In this instance, the offspring would inherit dominant alleles from both parents ( x p = p2 )

  •  The chance of an individual being heterozygous is 2pq

    • Offspring could inherit a dominant allele from the father and a recessive allele from the mother ( p x q ) or offspring could inherit a dominant allele from the mother and a recessive allele from the father ( p x q ) = 2pq

  • The chance of an individual being homozygous recessive is q2 

    •  In this instance, the offspring would inherit recessive alleles from both parents ( x q = q2 )

  • As these are all the possible genotypes of individuals in the population, the following equation can be constructed:

p2 + q2 + 2pq = 1

Worked Example

In a population of birds, 10% of the individuals exhibit the recessive phenotype of white feathers.

Calculate the frequencies of all genotypes.

Answer:

  • We will use F / f to represent dominant and recessive alleles for feather color

  • Those with the recessive phenotype must have the homozygous recessive genotype, ff

  • Therefore q2 = 0.10 (as 10% of the individuals have the recessive phenotype and q2 represents this)

To calculate the frequencies of the homozygous dominant ( p2 ) and heterozygous ( 2pq ):

Step 1: Find q

straight q equals square root of straight q squared end root equals square root of 0.1 end root equals 0.32

Step 2: Find p (the frequency of the dominant allele F). If q = 0.32, and p + q = 1

p + q = 1

p = 1 - 0.32

p = 0.68

Step 3: Find p2 (the frequency of homozygous dominant genotype)

0.682 = 0.46

p2 = 0.46

Step 4: Find 2pq = 2 x (p) x (q)

2 x (0.68) x (0.32) = 0.44

Step 5: Check calculations by substituting the values for the three frequencies into the equation; they should add up to 1

p2 + 2pq + q2 = 1

0.46 + 0.44 + 0.10 = 1.0

In summary:

  • Allele frequencies:

    • p = F = 0.68

    • q = f = 0.32

  • Genotype frequencies:

    • p2 = FF = 0.46

    • q2 = ff = 0.10

    • 2pq = Ff = 0.44

Examiner Tips and Tricks

When you are using Hardy-Weinberg equations you must always start your calculations by determining the proportion of individuals that display the recessive phenotype; this is the only phenotype from which you can immediately work out its genotype as it will always be homozygous recessive (the dominant phenotype is seen in both homozygous dominant and heterozygous individuals). 

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Ruth Brindle

Author: Ruth Brindle

Expertise: Biology

Ruth graduated from Sheffield University with a degree in Biology and went on to teach Science in London whilst also completing an MA in innovation in Education. With 10 years of teaching experience across the 3 key science disciplines, Ruth decided to set up a tutoring business to support students in her local area. Ruth has worked with several exam boards and loves to use her experience to produce educational materials which make the mark schemes accessible to all students.

Cara Head

Author: Cara Head

Expertise: Biology Content Creator

Cara graduated from the University of Exeter in 2005 with a degree in Biological Sciences. She has fifteen years of experience teaching the Sciences at KS3 to KS5, and Psychology at A-Level. Cara has taught in a range of secondary schools across the South West of England before joining the team at SME. Cara is passionate about Biology and creating resources that bring the subject alive and deepen students' understanding