Hardy-Weinberg Equilibrium (College Board AP® Biology): Study Guide
Conditions for Hardy-Weinberg equilibrium
The Hardy-Weinberg principle states that, if certain conditions are met,then the allele frequencies of a gene within a population will not change from one generation to the next
The Hardy-Weinberg equation allows for the calculation of allele and genotype frequencies within populations
It also allows for predictions to be made about how these frequencies will change in future generations
Conditions that must be met for the Hardy-Weinberg principle to hold true include:
a large population size
no migration into or out of the population
no mutations give rise to new alleles
mating is random
natural selection is not acting on the population
The assumptions listed are very rarely, if ever, all present in nature
Despite this, the Hardy-Weinberg equilibrium concept can provide a useful null hypothesis when evaluating the effects of genetic changes
The Hardy-Weinberg equation
If the phenotype of a trait in a population is determined by a single gene with only two alleles (we will use B / b as examples throughout this section), then the population will consist of individuals with three possible genotypes:
Homozygous dominant (BB)
Heterozygous (Bb)
Homozygous recessive (bb)
When using the Hardy-Weinberg equation, the frequency of a genotype is represented as a proportion of the population
For example, the BB genotype could be 0.40
Whole population = 1
The letter p represents the frequency of the dominant allele (B)
The letter q represents the frequency of the recessive allele (b)
As there are only two alleles at a single gene locus for this phenotypic trait in the population:
p + q = 1
The chance of an individual being homozygous dominant is p2
In this instance, the offspring would inherit dominant alleles from both parents ( p x p = p2 )
The chance of an individual being heterozygous is 2pq
Offspring could inherit a dominant allele from the father and a recessive allele from the mother ( p x q ) or offspring could inherit a dominant allele from the mother and a recessive allele from the father ( p x q ) = 2pq
The chance of an individual being homozygous recessive is q2
In this instance, the offspring would inherit recessive alleles from both parents ( q x q = q2 )
As these are all the possible genotypes of individuals in the population, the following equation can be constructed:
p2 + q2 + 2pq = 1
Worked Example
In a population of birds, 10% of the individuals exhibit the recessive phenotype of white feathers.
Calculate the frequencies of all genotypes.
Answer:
We will use F / f to represent dominant and recessive alleles for feather color
Those with the recessive phenotype must have the homozygous recessive genotype, ff
Therefore q2 = 0.10 (as 10% of the individuals have the recessive phenotype and q2 represents this)
To calculate the frequencies of the homozygous dominant ( p2 ) and heterozygous ( 2pq ):
Step 1: Find q
Step 2: Find p (the frequency of the dominant allele F). If q = 0.32, and p + q = 1
p + q = 1
p = 1 - 0.32
p = 0.68
Step 3: Find p2 (the frequency of homozygous dominant genotype)
0.682 = 0.46
p2 = 0.46
Step 4: Find 2pq = 2 x (p) x (q)
2 x (0.68) x (0.32) = 0.44
Step 5: Check calculations by substituting the values for the three frequencies into the equation; they should add up to 1
p2 + 2pq + q2 = 1
0.46 + 0.44 + 0.10 = 1.0
In summary:
Allele frequencies:
p = F = 0.68
q = f = 0.32
Genotype frequencies:
p2 = FF = 0.46
q2 = ff = 0.10
2pq = Ff = 0.44
Examiner Tips and Tricks
When you are using Hardy-Weinberg equations you must always start your calculations by determining the proportion of individuals that display the recessive phenotype; this is the only phenotype from which you can immediately work out its genotype as it will always be homozygous recessive (the dominant phenotype is seen in both homozygous dominant and heterozygous individuals).
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