Tonicity & Osmoregulation (College Board AP® Biology): Study Guide
Tonicity & cells
Compared to the cell contents, the external environment can be described as:
hypotonic
hypertonic
isotonic
Tonicity is relative, so the tonicity of a cell's external environment is always described in relation to the cell contents, e.g. when a cell is placed in:
a hypotonic solution, the surrounding solution has a lower solute concentration than the cell cytoplasm
a hypertonic solution, the solution has a higher solute concentration than the cell cytoplasm
an isotonic solution, the solution and the cell contents have an equal solute concentration
The external environment of a cell can also be described in terms of:
water potential: the tendency of water molecules to move from one place to another
osmolarity: the number of solute particles per liter of a solution
Tonicity & osmosis
Osmosis can be defined as:
the movement of water molecules from areas of high water potential/low osmolarity/low solute concentration to areas of low water potential/high osmolarity/high solute concentration
The tonicity of a cell's external environment will determine whether water moves into or out of the cell by osmosis:
Water will move into a cell placed in a hypotonic solution, as this solution has:
higher water potential
lower osmolarity
lower solute concentration
Water will move out of a cell placed in a hypertonic solution, as this solution has:
lower water potential
higher osmolarity
higher solute concentration

Determining the water potential of a solution
The water potential (Ψ) of a solution is influenced by:
solute potential
pressure potential
Solute potential (Ψs) is the effect that solutes in a solution have on water potential:
Pure water with no dissolved solutes has a solute potential of zero
As solutes are added to a solution its solute potential decreases and becomes more negative
Provided that pressure potential (see below) remains constant, a decrease in solute potential will cause a decrease in water potential
Solute molecules bind to water molecules via hydrogen bonds as they dissolve, reducing water potential
Pressure potential (Ψp) is the hydrostatic pressure to which water is subjected
Most biological systems are at the same pressure as the surrounding atmosphere, and so will have a pressure potential of zero
In this situation the water potential will be determined by the solute potential alone
Pressure potential may deviate from zero in some situations, e.g.:
pressure potential inside plant cells is usually positive as the cytoplasm exerts pressure on the inside of the cell wall
negative pressure potential can occur in xylem vessels where water and dissolved minerals are transported under tension
The relationship between water potential, solute potential and pressure potential is represented in the equation:
Ψ = Ψp + Ψs
Determining solute potential
Solute potential can be calculated using the formula:
Ψs = -iCRT
Solute potential depends on:
i = the number of molecules that a solute dissociates into when it dissolves in a solution, e.g.:
Sodium chloride, or NaCl, dissociates into Na+ and Cl-, so has an i value of 2
Glucose does not separate in solution, so has an i value of 1
C = the molar concentration of the solute
R = pressure constant; this is 0.0831 liter-bars/mole-K
T = temperature in Kelvin (°C + 273)
Worked Example
A 0.5 molar NaCl solution is in a beaker at atmospheric pressure and a temperature of 20 °C.
Use the formulae provided to calculate the water potential of the solution. Give your answer in bars.
Ψ = Ψp + Ψs
Ψs = -iCRT
Pressure constant = 0.0831 liter-bars / mole-K
Answer:
Step 1: determine the pressure potential of the solution
The solution is at atmospheric pressure
Ψp = 0
Step 2: determine i
NaCl dissociates into 2 ions; Na+ and Cl-
i = 2
Step 3: determine the temperature in Kelvin
Kelvin = °C + 273
20 °C + 273 = 293 K
Step 4: determine solute potential
Ψs = -iCRT
Ψs = -2 x 0.5 x 0.0831 x 293
Ψs = -24.3 bars
Step 5: determine water potential
Ψ = Ψp + Ψs
Ψ = 0 + -24.3
Ψ = -24.3 bars
Examiner Tips and Tricks
You do not need to memorize formulae and the pressure constant for the exam; this information will be provided.
Osmoregulation
Osmoregulation is an example of homeostasis in living organisms; it maintains the internal water balance, e.g. between red blood cells and the blood plasma
Failure to control internal osmolarity can result in harm to an organism:
Red blood cells may take on too much water and burst if the water potential of the blood plasma increases
Plant cells may lose water during a period of drought, causing a decrease in pressure potential; this can result in wilting, and may kill the plant over time
Example: contractile vacuoles in paramecium
Paramecium are protists; single-celled eukaryotes
Paramecium live in freshwater environments, meaning that their surroundings are hypotonic to their cytoplasm and they take in water by osmosis
The water taken in by Paramecium is stored inside a specialized vacuole known as a contractile vacuole
The contractile vacuole pumps excess water out of the cell
Example: central vacuoles in plant cells
The central vacuole in plant cells plays a role in cell homeostasis, with functions including:
water storage; a full vacuole maintains pressure potential and provides structural support to the cell
regulation of ion concentration in the the cytoplasm; ion channels in the vacuole membrane can open and close to allow movement of ions into or out of the cytoplasm
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