Motion of Charged Particles in a B Field (OCR A Level Physics)
Revision Note
Motion of a Charged Particle in a Magnetic Field
A charged particle in uniform magnetic field which is perpendicular to its direction of motion travels in a circular path
This is because the magnetic force F will always be perpendicular to its velocity v
F will always be directed towards the centre of the path in circular motion
A charged particle moves travels in a circular path in a magnetic field
The magnetic force F provides the centripetal force on the particle
The equation for centripetal force is:
Where:
F = centripetal force (N)
m = mass of the particle (kg)
v = linear velocity of the particle (m s−1)
r = radius of the orbit (m)
Equating this to the magnetic force on a moving charged particle gives the equation:
Rearranging for the radius r obtains the equation for the radius of the orbit of a charged particle in a perpendicular magnetic field:
This equation shows that:
Faster moving particles with speed v move in larger circles (larger r): r ∝ v
Particles with greater mass m move in larger circles: r ∝ m
Particles with greater charge q move in smaller circles: r ∝ 1 / q
Particles moving in a strong magnetic field B move in smaller circles: r ∝ 1 / B
The centripetal acceleration is in the same direction as the centripetal (and magnetic) force
This can be found using Newton's second law:
F = ma
Worked Example
An electron with a charge-to-mass ratio of 1.8 × 1011 C kg−1 is travelling at right angles to a uniform magnetic field of flux density 6.2 mT. The speed of the electron is 3.0 × 106 m s−1.
Calculate the radius of the circular path of the electron.
Answer:
Examiner Tips and Tricks
Make sure you're comfortable with deriving the equation for the radius of the path of a particle travelling in a magnetic field, as this is a common exam question.
Similar to orbits in a gravitational field, any object moving in circular motion will obey the equations of circular motion. Make sure to refresh your knowledge of these equations.
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