Capacitor Charge & Discharge Equations (OCR A Level Physics)

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The Time Constant

  • The time constant of a capacitor discharging through a resistor is a measure of how long it takes for the capacitor to discharge
  • The definition of the time constant is:

The time taken for the charge, current or voltage of a discharging capacitor to decrease to 37% of its original value

  • Alternatively, for a charging capacitor:

The time taken for the charge or voltage of a charging capacitor to rise to 63% of its maximum value

  • 37% is 0.37 or 1 over e (where e is the exponential function) multiplied by the original value (I0, Q0 or V0)
    • This is represented by the Greek letter tau, straight tau, and measured in units of seconds (s)
  • The time constant provides an easy way to compare the rate of change of similar quantities eg. charge, current and p.d.
  • It is defined by the equation:

bold tau = RC

  • Where:
    • straight tau = time constant (s)
    • R = resistance of the resistor (Ω)
    • C = capacitance of the capacitor (F)

  • The time to half, t1/2 (half-life) for a discharging capacitor is:

The time taken for the charge, current or voltage of a discharging capacitor to reach half of its initial value

  • This can also be written in terms of the time constant, τ:

t1/2 = ln(2) bold tau ≈ 0.69 bold tau = 0.69RC

Worked example

A capacitor of 7 nF is discharged through a resistor of resistance, R. The time constant of the discharge is 5.6 × 10−3 s.

Calculate the value of R.

Time Constant Worked Example

Examiner Tip

Note that the time constant is not the same as half-life. Half-life is how long it takes for the current, charge or voltage to halve whilst the time constant is to 37% of its original value (not 50%).

Although the time constant is given on the datasheet, you will be expected to remember the half-life equation t1/2 = 0.69RC

Charging & Discharging Equations

  • The time constant is used in the exponential decay equations for the current, charge or potential difference (p.d.) for a capacitor charging, or discharging, through a resistor
  • These equations can be used to determine:
    • The amount of current, charge or p.d. gained after a certain amount of time for a charging capacitor
    • The amount of current, charge or p.d. remaining after a certain amount of time for a discharging capacitor

Capacitor Discharge Equations

  • This exponential decay means that no matter how much charge is initially on the plates, the amount of time it takes for that charge to halve is the same
  • The exponential decay of current on a discharging capacitor is defined by the equation:

Current Discharge Equation_3

  • Where:
    • I = current (A)
    • I0 = initial current before discharge (A)
    • e = the exponential function
    • t = time (s)
    • RC = resistance (Ω) × capacitance (F) = the time constant τ (s)

  • This equation shows that the smaller the time constant τ, the quicker the exponential decay of the current when discharging
  • Also, how big the initial current is affects the rate of discharge
    • If I0 is large, the capacitor will take longer to discharge

  • Note: during capacitor discharge, I0 is always larger than I, as the current I will always be decreasing

Capacitor Discharge Graph and Equation, downloadable AS & A Level Physics revision notes

Values of the capacitor discharge equation on a graph and circuit

  • The current at any time is directly proportional to the p.d. across the capacitor and the charge across the parallel plates
  • Therefore, this equation also describes the charge on the capacitor after a certain amount of time:

Charge Discharge Equation_2

  • Where:
    • Q = charge on the capacitor plates (C)
    • Q0 = initial charge on the capacitor plates (C)

  • As well as the p.d. after a certain amount of time:

Voltage Discharge Equation_2

  • Where:
    • V = p.d. across the capacitor (C)
    • V0 = initial p.d. across the capacitor (C)

Worked example

The initial current through a circuit with a capacitor of 620 µF is 0.6 A. The capacitor is connected across the terminals of a 450 Ω resistor.

Calculate the time taken for the current to fall to 0.4 A.

Current Discharge Equation Worked Example


Capacitor Charge Equations

  • When a capacitor is charging, the way the charge Q and potential difference V increases stills shows exponential decay
    • Over time, they continue to increase but at a slower rate
  • This means the equation for Q for a charging capacitor is:

Charge Charging Equation

  • Where:
    • Q = charge on the capacitor plates (C)
    • Q0 = maximum charge stored on capacitor when fully charged (C)
    • e = the exponential function
    • t = time (s)
    • RC = resistance (Ω) × capacitance (F) = the time constant τ (s)
  • Similarly, for V:

Voltage Charging Equation

  • Where:
    • V = p.d. across the capacitor (V)
    • V0 = maximum potential difference across the capacitor when fully charged (V)
  • The charging equation for the current I is the same as its discharging equation since the current still decreases exponentially
  • The key difference with the charging equations is that Q0 and V0 are now the final (or maximum) values of Q and V that will be on the plates, rather than the initial values

Worked example

A capacitor is to be charged to a maximum potential difference of 12 V between its plate.

Calculate how long it takes to reach a potential difference 10 V given that it has a time constant of 0.5 s.

Capacitor Charging Worked Example (1)Capacitor Charging Worked Example (2)

Examiner Tip

Knowledge of the exponential constant, a number which is approximately equal to e = 2.718..., is crucial for mastering charge and discharge equations, so make sure you know how to use it:

  • On a calculator, it is shown by the button ex
  • The inverse function of ex is ln(y), known as the natural logarithmic function
    • This is because, if ex = y, then x = ln (y)

The 0.37 in the definition of the time constant arises as a result of the exponential constant, so make sure you know that the true definition is:

Time constant = The time taken for the charge of a capacitor to decrease to 1 over eof its original value

Where 1 over e= 0.3678

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Katie M

Author: Katie M

Expertise: Physics

Katie has always been passionate about the sciences, and completed a degree in Astrophysics at Sheffield University. She decided that she wanted to inspire other young people, so moved to Bristol to complete a PGCE in Secondary Science. She particularly loves creating fun and absorbing materials to help students achieve their exam potential.