Positron Emission Tomography (PET) Scanning
- Positron Emission Tomography (PET) is defined as:
A type of nuclear medical procedure that images tissues and organs by measuring the metabolic activity of the cells of body tissues
- In PET scanning, a beta-plus emitting radioactive tracer is used in order to stimulate positron-electron annihilation to produce gamma photons
- These are then detected using a ring of gamma cameras
Principles of PET Scanning
Before the scan
- The patient is injected with a beta-plus emitting isotope, usually fluorine-18 (F-18)
During the scan
- The part of the body being studied is surrounded by a ring of gamma cameras
- The positrons from the F-18 nuclei annihilate with electrons in the patient
- The annihilation of a positron and an electron produces two identical gamma photons travelling in opposite directions
- The delay time between these two gamma ray photons is used to determine the location of the annihilation due to the F-18 tracer
- Photons that do not arrive within a nanosecond of each other are ignored, since they cannot have come from the same point
After the scan
- Computer connected to the gamma cameras detect the signal and an image is formed by the computer
Detecting gamma rays with a PET scanner
Annihilation
- When a positron is emitted from a tracer in the body, it travels less than a millimetre before it collides with an electron
- The positron and the electron will annihilate, and their mass becomes pure energy in the form of two gamma rays which move apart in opposite directions
- Annihilation doesn’t just happen with electrons and positrons, annihilation is defined as:
When a particle meets its equivalent antiparticle they are both destroyed and their mass is converted into energy
- As with all collisions, the mass, energy and momentum are conserved
Annihilation of a positron and electron to form two gamma-ray photons
- The gamma-ray photons produced have an energy and frequency that is determined solely by the mass-energy of the positron-electron pair
- The energy E of the photon is given by
E = hf = mec2
- The momentum p of the photon is given by
- Where:
- me = mass of the electron or positron (kg)
- h = Planck's constant (J s)
- f = frequency of the photon (Hz)
- c = the speed of light in a vacuum (m s–1)
Worked example
Fluorine-18 decays by β+ emission. The positron emitted collides with an electron and annihilates producing two γ-rays.
(a) Calculate the energy released when a positron and an electron annihilate.
(b) Calculate the frequency of the γ-rays emitted.
(c) Calculate the momentum of one of the γ-rays.
Part (a)
Step 1: Write down the known quantities
-
- Mass of an electron = mass of a positron, me = 9.11 × 10–31 kg
- Total mass is equal to the mass of the electron and positron = 2me
Step 2: Write out the equation for mass-energy equivalence
E = mec2
Step 3: Substitute in values and calculate energy E
E = 2 × (9.11 × 10-31) × (3.0 × 108)2 = 1.6 × 10–13 J
Part (b)
Step 1: Determine the energy of one photon
-
- Planck's constant, h = 6.63 × 10−34 J s
- Two photons are produced, so, the energy of one photon is equal to half of the total energy from part (a):
Step 2: Write out the equation for the energy of a photon
E = hf
Step 3: Rearrange for frequency f, and calculate
Part (c)
Step 1: Write out the equation for the momentum of a photon
Step 2: Substitute in values and calculate momentum, p