Calculating Gravitational Potential (OCR A Level Physics)

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Calculating Gravitational Potential

Calculating Gravitational Potential

  • Gravitational potential Vg can be calculated at a distance r from a point mass M using the equation: 

V subscript g equals negative fraction numerator G M over denominator r end fraction

  • Where:
    • Vg = gravitational potential (J kg1)
    • G = Newton’s gravitational constant (N m2 kg–2)
    • M = mass of the body causing the gravitational field (kg)
    • r = distance from the centre of mass of M to the point in the field (m)

  • This means that the gravitational potential is negative on the surface of a mass (such as a planet), and increases with distance from that mass (becomes less negative toward zero)
  • Work has to be done against the gravitational pull of the planet to take a unit mass away from the planet
  • The gravitational potential at a point depends on the mass of the object producing the gravitational field and the distance the point is from that mass

Changes in Gravitational Potential

  • Two points at different distances from a mass will have different gravitational potentials
    • This is because the gravitational potential increases with distance from a mass

  • Therefore, there will be a gravitational potential difference between the two points
    • This is represented by the symbol ΔV

  • ΔV can therefore be expressed as the difference between the 'final' gravitational Vf potential and the 'initial' gravitational potential Vi  

ΔV = Vf – Vi

  • Therefore, the change in potential between two points a distance r1 and r2 from some mass M is given by:

capital delta V equals negative fraction numerator G M over denominator r subscript 2 end fraction minus open parentheses negative fraction numerator G M over denominator r subscript 1 end fraction close parentheses

  • This simplifies to:

capital delta V equals G M space open parentheses 1 over r subscript 1 minus 1 over r subscript 2 close parentheses 

  • Where:
    • ΔV = change in potential (J kg–1)
    • G = Newton’s gravitational constant (N m2 kg–2)
    • M = mass causing the gravitational field (kg)
    • r1 = initial distance from mass M (m)
    • r2 = final distance from mass M (m)

Worked example

Calculate gravitational potential at the surface of Mars. 

Radius of Mars = 3400 km

Mass of Mars = 6.4 × 1023 kg

   Step 1: Write the gravitational potential equation

V subscript g equals negative fraction numerator G M over denominator r end fraction

   Step 2: Substitute known quantities

V subscript g equals negative fraction numerator left parenthesis 6.67 cross times 10 to the power of negative 11 end exponent right parenthesis cross times left parenthesis 6.4 cross times 10 to the power of 23 right parenthesis over denominator 3400 cross times 10 cubed end fraction= – 1.3 × 107 J kg–1

Examiner Tip

The equation for gravitational potential in a radial field looks very similar to the equation for gravitational field strength in a radial field, but there is a very important difference! Remember, for gravitational potential: 

V subscript g equals negative fraction numerator G M over denominator r end fraction so V subscript g proportional to negative 1 over r

However, for gravitational field strength: 

g equals negative fraction numerator G M over denominator r squared end fraction so g proportional to negative 1 over r squared

Additionally, remember that both Vg and g are measured from the centre of the mass M causing the field! 

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Katie M

Author: Katie M

Expertise: Physics

Katie has always been passionate about the sciences, and completed a degree in Astrophysics at Sheffield University. She decided that she wanted to inspire other young people, so moved to Bristol to complete a PGCE in Secondary Science. She particularly loves creating fun and absorbing materials to help students achieve their exam potential.