The Doppler Effect (OCR A Level Physics)

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Katie M

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Katie M

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The Doppler Effect

  • If a wave source is stationary, the wavefronts spread out symmetrically

  • If the wave source is moving, the waves can become squashed together or stretched out

    • If the wave source is moving towards an observer the wavefronts will appear squashed

    • If the wavefront is moving away from an observer the wavefronts will appear stretched out

  • Therefore, when a wave source moves relative to an observer there will be a change in the observed frequency and wavelength

doppler-effect, IGCSE & GCSE Physics revision notes

Wavefronts are even in a stationary object but are squashed in the direction of the moving wave source

  • A moving object will cause the wavelength, λ, (and frequency) of the waves to change:

    • The wavelength of the waves in front of the source decreases (λ – Δλ) and the frequency increases

    • The wavelength behind the source increases (λ + Δλ) and the frequency decreases

  • Note: Δλ means 'change in wavelength'

    • The actual wavelength emitted by the source remains the same

    • It is only the wavelength that is received by the observer that appears to have changed

  • This effect is known as the Doppler effect or Doppler shift

  • The Doppler effect is defined as:

     The apparent shift in wavelength occurring when the source of the waves is moving

  • The Doppler effect, or Doppler shift, can be observed using any form of electromagnetic radiation

  • It can be observed by comparing the light spectrum produced from a close object, such as our Sun, with that of a distant galaxy

    • The light from the distant galaxy is shifted towards the red end of the spectrum (There are more spectral lines in the red end)

    • This provides evidence that the universe is expanding

Comparing the light spectrum produced from the Sun and a distant galaxy, downloadable IGCSE & GCSE Physics revision notes

Comparing the light spectrum produced from the Sun and a distant galaxy

The Doppler Equation

  • Doppler shift (Doppler effect) describes how the wavelength (or frequency) of waves change when the source of the waves and observer are moving relative to each other

  • If the relative speed between the source of the waves and the observer, ∆v, is small compared to the speed at which the wave is travelling, c, then the Doppler wavelength shift, ∆λ, and frequency shift, ∆f, is given by:

fraction numerator increment lambda over denominator lambda end fraction space almost equal to space fraction numerator increment f over denominator f end fraction space almost equal to fraction numerator increment v over denominator c end fraction

  • Where: 

    • Δv = relative speed between source and observer (m s–1)

    • c = speed of the wave (m s–1)

    • Δf = observed change in frequency between moving source and stationary source of wave (Hz)

    • f = unshifted frequency of the wave emitted (Hz)

    • Δλ = observed change in wavelength between moving source and stationary source of wave (m)

    • λ = unshifted wavelength of the wave emitted (m)

 

  • The relative speed between source and observer along the line joining them is give by:

v = vs vo

  • Where:

    • vs = velocity of electromagnetic waves source

    • vo = velocity of observer

  • Usually, we are calculating the speed of the source of electromagnetic waves relative to an observer which we assume to be stationary

    • Therefore vo = 0, hence ∆v = vs = v

    • Where v is the velocity at which the source of the electromagnetic waves is moving from the observer

 

  • Hence, the Doppler shift equation can therefore be written as:

fraction numerator increment lambda over denominator lambda end fraction space almost equal to space fraction numerator increment f over denominator f end fraction space almost equal to v over c

Worked Example

A stationary source of light is found to have a spectral line of wavelength 438 nm.  The same line from a distant star that is moving away from us has a wavelength of 608 nm.

Calculate the speed at which the star is travelling away from Earth.

Answer:

   Step 1: List the known quantities

  • Unshifted wavelength = λ = 438 nm = 438 × 10–9 m

  • Shifted wavelength = 608 nm = 608 × 10–9 m

  • Change in wavelength = ∆λ = (608 – 438) × 10–9 = 170 × 10–9

  • Speed of light = c = 3.00 × 108 m s–1

   Step 2: State the Doppler shift equation

fraction numerator increment lambda over denominator lambda end fraction space almost equal to fraction numerator increment v over denominator c end fraction

   

   Step 3: Substitute values to calculate v

   v = fraction numerator c increment lambda over denominator lambda end fractionfraction numerator left parenthesis 3.00 blank cross times blank 10 to the power of 8 right parenthesis left parenthesis 170 blank cross times blank 10 to the power of negative 9 end exponent right parenthesis over denominator 438 blank cross times blank 10 to the power of negative 9 end exponent end fraction = 1.16 × 108 m s–1

Examiner Tips and Tricks

You need to know that in the visible light spectrum red light has the longest wavelength and the smallest frequency compared to blue light which has a shorter wavelength and higher frequency.

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Katie M

Author: Katie M

Expertise: Physics

Katie has always been passionate about the sciences, and completed a degree in Astrophysics at Sheffield University. She decided that she wanted to inspire other young people, so moved to Bristol to complete a PGCE in Secondary Science. She particularly loves creating fun and absorbing materials to help students achieve their exam potential.