Two capacitors, X and Y, of capacitance 25 μF and 88.5 μF respectively, are connected in parallel to a battery of emf 6.0 V, as shown in Fig. 1.1
Fig. 1.1
The plates of both capacitor X and capacitor Y are separated by a vacuum.
Complete Table 1.1 for this circuit.
Table 1.1
capacitor | capacitance / μF | p.d. / V | charge / μC |
X | 25.0 |
|
|
Y | 88.5 |
|
|
The total capacitance for two capacitors and connected in parallel is given by the equation:
Using the equation given, calculate the total capacitance of the circuit shown in Fig. 1.1 in Farads, F.
A dielectric material is inserted into the space between the plates of capacitor Y in Fig. 1.1.
State how the capacitance of capacitor Y changes with an added dielectric material.
The graph in Fig. 1.2 represents the equation Q = CV.
Fig. 1.2
State the quantities represented by each axis.
Did this page help you?