Syllabus Edition
First teaching 2023
First exams 2025
Magnetic Flux Linkage (Cambridge (CIE) A Level Physics)
Revision Note
Magnetic flux linkage
The magnetic flux linkage is a quantity commonly used for solenoids which are made of N turns of wire
Magnetic flux linkage is defined as:
The product of the magnetic flux and the number of turns
It is calculated using the equation:
Where:
Φ = magnetic flux (Wb)
N = number of turns of the coil
B = magnetic flux density (T)
A = cross-sectional area (m2)
The flux linkage NΦ has the units of Weber turns (Wb turns)
As with magnetic flux, if the field lines are not completely perpendicular to the plane of the area they are passing through
Therefore, the component of the flux density which is perpendicular is equal to:
Where:
θ = angle between magnetic field lines and the line perpendicular to the plane of the area (degrees)
Worked Example
A solenoid of circular cross-sectional radius of 0.40 m and 300 turns is positioned perpendicular to a magnetic field with a magnetic flux density of 5.1 mT.
Determine the magnetic flux linkage for this solenoid.
Answer:
Step 1: Write out the known quantities
Cross-sectional area, A = πr2 = π(0.4)2 = 0.503 m2
Magnetic flux density, B = 5.1 mT = 5.1 × 10−3 T
Number of turns of the coil, N = 300 turns
Step 2: Write down the equation for the magnetic flux linkage
Step 3: Substitute in values and calculate
Wb turns (2 s.f.)
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