Motion of a charged particle in a uniform magnetic field
- When a charged particle enters a uniform magnetic field, it travels in a circular path
- This is because the direction of the magnetic force F will always be
- perpendicular to the particle's velocity v
- directed towards the centre of the path, resulting in circular motion
Circular motion of a charge in a magnetic field
In a magnetic field, a charged particle travels in a circular path as the force, velocity and field are all perpendicular
- The magnetic force F provides the centripetal force on the particle
- The equation for centripetal force is:
- Equating this to the magnetic force on a moving charged particle gives the expression:
- Rearranging for the radius r gives an expression for the radius of the path of a charged particle in a perpendicular magnetic field:
- Where:
- r = radius of the path (m)
- m = mass of the particle (kg)
- v = linear velocity of the particle (m s−1)
- B = magnetic field strength (T)
- Q = charge of the particle (C)
- This equation shows that:
- Faster moving particles with speed v move in larger circles (larger r):
- Particles with greater mass m move in larger circles:
- Particles with greater charge q move in smaller circles:
- Particles moving in a strong magnetic field B move in smaller circles:
- The centripetal acceleration is in the same direction as the magnetic (centripetal) force
- This can be found using Newton's second law:
Worked example
An electron travels at right angles to a uniform magnetic field of flux density 6.2 mT. The speed of the electron is 3.0 × 106 m s-1 and its charge-to-mass ratio is 1.8 × 1011 C kg-1.
Calculate the radius of the circular path of the electron.
Answer:
Step 1: Write down the known quantities
- Charge-to-mass ratio:
- Magnetic flux density, B = 6.2 mT
- Electron speed, v = 3.0 × 106 m s-1
Step 2: Write down the equation for the radius of a charged particle in a perpendicular magnetic field
Step 3: Substitute in values