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Force on a Current-Carrying Conductor (CIE A Level Physics)

Revision Note

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Calculating magnetic force on a current-carrying conductor

  • The force F on a conductor carrying current I at an angle θ to a magnetic field with flux density B is defined by the equation

F space equals space B I L space sin space theta

  • Where:
    • F = force on a current-carrying conductor in a B field (N)
    • B = magnetic flux density of applied B field (T)
    • I = current in the conductor (A)
    • L = length of the conductor (m)
    • θ = angle between the conductor and applied B field (degrees)
  • This equation shows that the force on the conductor can be increased by:
    • increasing the strength of the magnetic field
    • increasing the current flowing through the conductor
    • increasing the length of the conductor in the field
  • Note: The length L represents the length of the conductor that is within the field

Magnetic force on a current-carrying conductor

Force on conductor (1), downloadable AS & A Level Physics revision notes

Force on conductor (2), downloadable AS & A Level Physics revision notes

The magnitude of the force on a current-carrying conductor depends on the angle of the conductor to the external B field

  • A current-carrying conductor (e.g. a wire) will experience the maximum magnetic force if the current through it is perpendicular to the direction of the magnetic field lines
    • It experiences no force if it is parallel to magnetic field lines
  • The maximum force occurs when sin θ = 1
    • This means θ = 90° and the conductor is perpendicular to the B field
  • The equation for the magnetic force becomes:

F space equals space B I L

  • The minimum force, i.e. F = 0 N, is when sin θ = 0°
    • This means θ = 0° and the conductor is parallel to the B field
  • It is important to note that a current-carrying conductor will experience no force if the current in the conductor is parallel to the field
    • This is because the F, B and must be perpendicular to each other

Worked example

A current of 0.87 A flows in a wire of length 1.4 m placed at 30° to a magnetic field of flux density 80 mT.

Calculate the magnitude of the force on the wire.

Answer:

Step 1: Write down the known quantities

  • Magnetic flux density, B = 80 mT = 80 × 10-3 T
  • Current, I = 0.87 A
  • Length of wire, L = 1.4 m
  • Angle between the wire and the magnetic field, θ = 30°

Step 2: Write down the equation for force on a current-carrying conductor

F space equals space B I L sin open parentheses theta close parentheses

Step 3: Substitute in values and calculate

F space equals space open parentheses 80 space cross times space 10 to the power of negative 3 end exponent close parentheses space cross times space 0.87 space cross times space 1.4 space cross times space sin open parentheses 30 close parentheses space equals space 0.049 space straight N space open parentheses 2 space straight s. straight f. close parentheses

Examiner Tip

Remember that the direction of current flow is the flow of positive charge (positive to negative), and this is in the opposite direction to the flow of electrons

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Ashika

Author: Ashika

Expertise: Physics Project Lead

Ashika graduated with a first-class Physics degree from Manchester University and, having worked as a software engineer, focused on Physics education, creating engaging content to help students across all levels. Now an experienced GCSE and A Level Physics and Maths tutor, Ashika helps to grow and improve our Physics resources.