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First teaching 2023

First exams 2025

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Electric Field Between Parallel Plates (CIE A Level Physics)

Revision Note

Ann H

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Ann H

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Electric field between parallel plates

  • When two points in an electric field are at different potentials, there is a potential difference between them
    • To move a charge across that potential difference, work needs to be done on the charge
    • Two charged parallel plates with a potential difference of V between them create a uniform electric field
  • The magnitude of the uniform electric field strength between two charged parallel plates is defined by the equation:

E space equals space fraction numerator increment V over denominator increment d end fraction

  • Where:
    • E = electric field strength (V m1)
    • ΔV = potential difference between the plates (V)
    • Δd = distance between the plates (m)
  • Note: both units for electric field strength, V m−1 and N C−1, are equivalent 
  • The equation shows:
    • the greater the potential difference between the plates, the stronger the field
    • the greater the separation between the plates, the weaker the field
  • This equation cannot be used to find the electric field strength around a point charge
    • This is because the field around a point charge is radial
  • The electric field between two plates is directed:
    • from the positive plate (i.e. the one connected to the positive terminal)
    • to the negative plate (i.e. the one connected to the negative terminal)

Uniform electric field between two parallel plates

Electric field between two plates, downloadable AS & A Level Physics revision notes

The electric field strength between two charged parallel plates is the ratio of the potential difference and distance between the plates

Derivation of electric field strength between two parallel plates

  • When a charge q moves from one plate to the other, the work done on the charge by the field is

W space equals space F d

  • Where:
    • W = work done on charge (J)
    • F = force on the charge (N)
    • d = distance between plates (m)
  • The work done in moving a charge q through a potential difference V between parallel plates is given by:

W space equals space q V

  • Equating the two expressions:

F d space equals space q V

  • The electric field strength between the plates is therefore given by:

E space equals space F over q space equals space V over d

Parallel Plates Work Done, downloadable AS & A Level Physics revision notes

The work done on a charge in an electric field depends on the force and the distance between the plates

Worked example

Two parallel metal plates separated by 3.5 cm have a potential difference of 7.9 kV between them.

Calculate the electric force acting on a stationary point charge of 2.6 × 10−15 C when placed between the plates.

Answer:

Step 1: List the known quantities

  • Potential difference between plates, V = 7.9 kV = 7900 V
  • Distance between plates, d = 3.5 cm = 0.035 m
  • Charge, q = 2.6 × 10−15 C

Step 2: Equate the equations for electric field strength 

E field between parallel plates:  E space equals space V over d

E field on a point charge:  E space equals space F over q

E space equals space F over q space equals space V over d

Step 3: Rearrange the expression for electric force F

F space equals space fraction numerator q V over denominator d end fraction

Step 4: Substitute values to calculate the force on the point charge

F space equals space fraction numerator open parentheses 2.6 cross times 10 to the power of negative 15 end exponent close parentheses cross times 7900 over denominator 0.035 end fraction space equals space 5.9 cross times 10 to the power of negative 10 end exponent N (2 s.f.)

Examiner Tip

Remember the equation for electric field strength with V and d is only valid for parallel plates, and not for point charges 

However, when a point charge moves between two parallel plates, the two equations for electric field strength can be equated:

E space equals space F over Q space equals space V over d

Top tip: if one of the parallel plates is earthed, it has a voltage of 0 V

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Ann H

Author: Ann H

Expertise: Physics

Ann obtained her Maths and Physics degree from the University of Bath before completing her PGCE in Science and Maths teaching. She spent ten years teaching Maths and Physics to wonderful students from all around the world whilst living in China, Ethiopia and Nepal. Now based in beautiful Devon she is thrilled to be creating awesome Physics resources to make Physics more accessible and understandable for all students no matter their schooling or background.