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Specific Heat Capacity (CIE A Level Physics)

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Katie M

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Defining specific heat capacity

  • The specific heat capacity of a substance is defined as:

The amount of thermal energy required to raise the temperature of 1 kg of a substance by 1 °C

  • This quantity determines the amount of energy needed to change the temperature of a substance
  • The specific heat capacity is measured in units of Joules per kilogram per Kelvin (J kg-1 K-1) or Joules per kilogram per Celsius (J kg-1 °C-1) and has the symbol c
    • Different substances have different specific heat capacities
    • Specific heat capacity is mainly used in liquids and solids

Specific heat capacity of different materialsSpecific heat examples, downloadable AS & A Level Physics revision notes

Low v high specific heat capacity.

  • From the definition of specific heat capacity, it follows that:
    • The heavier the material, the more thermal energy that will be required to raise its temperature
    • The larger the change in temperature, the higher the thermal energy will be required to achieve this change

Calculating specific heat capacity

  • The amount of thermal energy Q needed to raise the temperature by Δθ for a mass m with specific heat capacity c is equal to:

ΔQ = mcΔθ

  • Where:
    • ΔQ = change in thermal energy (J)
    • m = mass of the substance you are heating up (kg)
    • c = specific heat capacity of the substance (J kg-1K-1or J kg-1 °C-1)
    • Δθ = change in temperature (K or °C)

  • If a substance has a low specific heat capacity, it heats up and cools down quickly
  • If a substance has a high specific heat capacity, it heats up and cools down slowly
  • The specific heat capacity of different substances determines how useful they would be for a specific purpose eg. choosing the best material for kitchen appliances

Table of values of specific heat capacity for various substances

 Substance Specific heat capacity / J kg-1K-1 
Aluminium 910
Copper 390
Lead 126
Glass 500 - 680
Water 4200
Mercury 140

  • Good electrical conductors, such as copper and lead, are also excellent conductors of heat due to their low specific heat capacity

Worked example

A kettle is rated at 1.7 kW. A mass of 650 g of a liquid at 25°C is poured into a kettle.When the kettle is switched on, it takes 3.5 minutes to start boiling.

Calculate the specific heat capacity of the liquid.

Step 1:            Calculate the Energy from the power and time

Energy = Power × Time

Power = 1.7 kW = 1.7 × 103 W

Time = 3.5 minutes = 3.5 × 60 = 210 s

Energy = 1.7 × 103 × 210 = 3.57 × 105 J

Step 2:            Thermal energy equation

ΔQ = mcΔθ

Step 3:            Rearrange for specific heat capacity

bold italic c bold space bold equals bold space fraction numerator bold increment bold Q over denominator bold m bold increment bold theta end fraction

Step 4:            Substitute in values

m = 650 g = 650 × 10-3 kg

Δθ = 100 - 25 = 75oC

bold italic c bold space bold equals bold space fraction numerator bold 3 bold. bold 57 bold space bold cross times bold space bold 10 to the power of bold 5 over denominator bold 650 bold space bold cross times bold 10 to the power of bold minus bold 3 end exponent bold cross times bold 75 bold space end fraction = 7323.07... = 7300 J kg-1 oC-1 (2 s.f)

Examiner Tip

The difference in temperature Δθ will be exactly the same whether the temperature is given in Celsius or Kelvin. Therefore, there is no need to convert between the two since the difference in temperature will be the same for both units.

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Katie M

Author: Katie M

Expertise: Physics

Katie has always been passionate about the sciences, and completed a degree in Astrophysics at Sheffield University. She decided that she wanted to inspire other young people, so moved to Bristol to complete a PGCE in Secondary Science. She particularly loves creating fun and absorbing materials to help students achieve their exam potential.