1a
3 marks
3 marksThe power P dissipated in a resistor of resistance R is measured for a range of values of the potential difference V across it.
The results are shown in the table in Fig. 1.1.
| V / | V 2 / | P / |
| 1.00 | 1.0 | 0.214 |
| 1.71 | 2.9 |
0.58 |
| 2.25 |
1.011 |
|
| 2.67 |
1.43 |
|
| 3.00 | 9.0 |
1.80 |
| 3.27 | 10.7 |
2.176 |
| 3.50 | 12.3 |
2.43 |
Fig. 1.1.
For the table in Fig. 1.1
i)
Add the correct units.
[1]
ii)
Complete the missing data.
[1]
iii)
Identify errors in the recorded the data and correct them.
[1]
1b7 marks
7 marksComplete the graph of the data on Fig. 1.2. below.
Fig. 1.2.
i)
Plot the two missing points and complete the graph.
[3]
ii)
Determine the gradient of the graph.
[3]
iii)
Use the gradient of the graph to obtain a value for R.
[1]
1c7 marks
7 marksThe rest of this question is based on the data in the table Fig. 1.1 in part (a).
i)
Determine the value of R when V = 3.50 V.
[1]
ii)
The uncertainty in V is ± 0.01 V.
The uncertainty in P is ± 0.05 W.
Calculate the percentage uncertainty in the value of R calculated in part (i).
[3]
iii)
Hence calculate the uncertainty in the value of R.
[1]
iv)
State and explain whether the value of R you calculated in part (i) is consistent with the value of R you determined from the gradient in part (b).
[2]
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