Syllabus Edition
First teaching 2023
First exams 2025
Intensity Reflection Coefficient (Cambridge (CIE) A Level Physics): Revision Note
Intensity reflection coefficient
The intensity reflection coefficient α is defined as:
The ratio of the intensity of the reflected wave relative to the incident (transmitted) wave
This can be calculated using the fraction:
Where:
α = intensity reflection coefficient
IR = intensity of the reflected wave (W m-2)
I0 = intensity of the incident wave (W m-2)
Z1 = acoustic impedance of one material (kg m-2 s-1)
Z2 = acoustic impedance of a second material (kg m-2 s-1)
This equation will be provided on the datasheet for your exam
This ratio shows:
If there is a large difference between the impedance of the two materials, then most of the energy will be reflected
If the impedance is the same, then there will be no reflection
Coupling medium
When ultrasound is used in medical imaging, a coupler is needed between the transducer and the body
The soft tissues of the body are much denser than air
If air is present between the transducer and the body, then almost all the ultrasound energy will be reflected
The coupling gel is placed between the transducer and the body, as skin and the coupling gel have a similar density, so little ultrasound is reflected
This is an example of impedance matching
Worked Example
A beam of ultrasound is incident at right angles to a boundary between two materials as shown in the diagram.
![WE - Intensity reflection coefficient question image, downloadable AS & A Level Physics revision notes](https://cdn.savemyexams.com/cdn-cgi/image/f=auto,width=3840/https://cdn.savemyexams.com/uploads/2021/05/24.1-WE-Intensity-reflection-coefficient-question-image.png)
The materials have acoustic impedances of Z1 and Z2. The intensity of the transmitted ultrasound beam is IT, and the reflected intensity is IR.
(a) What is the relationship between I, IT and IR?
(b) Use the data from the table to determine the reflection coefficient α for a boundary between
(i) gel and soft tissue
(ii) air and soft tissue
(c) Explain why gel is usually put on the skin during medical diagnosis using ultrasound.
medium | speed of ultrasound / m s–1 | acoustic impedance / kg m–2 s–1 |
air | 330 | 4.3 × 102 |
gel | 1500 | 1.5 × 106 |
soft tisuse | 1600 | 1.6 × 106 |
bone | 4100 | 7.0 × 106 |
Answer:
Part (a)
State the relationship between I, IT and IR:
Incident intensity = Transmitted intensity + Reflected intensity
Part (b)(i)
Step 1: Write down the equation for intensity reflection coefficient α
Step 2: Write down the acoustic impedances for gel and soft tissue
Gel, Z1 = 1.5 × 106 kg m-2 s-1
Soft tissue, Z2 = 1.6 × 106 kg m-2 s-1
Step 3: Calculate the intensity reflection coefficient
This result means that only 0.1% of the incident intensity will be reflected, with the remaining being transmitted
Part (b)(ii)
Step 1: Write down the acoustic impedances for air and soft tissue
Air, Z1 = 4.3 × 102 kg m-2 s-1
Soft tissue, Z2 = 1.6 × 106 kg m-2 s-1
Step 2: Calculate the intensity reflection coefficient
This result means that 100% of the incident intensity will be reflected, with none being transmitted
Part (c)
At the air-soft tissue boundary, the intensity reflection coefficient is α ≈ 1
Therefore, without gel, there is almost complete reflection, no ultrasound is transmitted through the skin
Therefore, the gel enables almost complete transmission of the ultrasound through the skin, with very little reflection
At the gel-soft tissue boundary, the intensity reflection coefficient is α = 0.001
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