Calculating Energy Released in Nuclear Reactions
- The binding energy is equal to the amount of energy released in forming the nucleus, and can be calculated using:
E = (Δm)c2
- Where:
- E = Binding energy released (J)
- Δm = mass defect (kg)
- c = speed of light (m s-1)
- The daughter nuclei produced as a result of both fission and fusion have a higher binding energy per nucleon than the parent nuclei
- Therefore, energy is released as a result of the mass difference between the parent nuclei and the daughter nuclei
Worked example
Part (a)
Step 1: Balance the number of protons on each side (bottom number)
92 = (2 × 46) + xnp (where np is the number of protons in c)
xnp = 92 – 92 = 0
Therefore, c must be a neutron
Step 2: Balance the number of nucleons on each side
235 + 1 = (2 × 116) + x
x = 235 + 1 – 232 = 4
Therefore, 4 neutrons are generated in the reaction
Part (b)
Step 1: Find the binding energy of each nucleus
Total binding energy of each nucleus = Binding energy per nucleon × Mass number
Binding energy of 95Sr = 8.74 × 95 = 830.3 MeV
Binding energy of 139Xe = 8.39 × 139 = 1166.21 MeV
Binding energy of 235U = 7.60 × 235 = 1786 MeV
Step 2: Calculate the difference in energy between the products and reactants
Energy released in reaction 1 = ESr + EXe – EU
Energy released in reaction 1 = 830.3 + 1166.21 – 1786
Energy released in reaction 1 = 210.5 MeV
Part (c)
-
- Since reaction 1 releases more energy than reaction 2, its end products will have a higher binding energy per nucleon
- Hence they will be more stable
- This is because the more energy is released, the further it moves up the graph of binding energy per nucleon against nucleon number (A)
- Since at high values of A, binding energy per nucleon gradually decreases with A
- Nuclear reactions will tend to favour the more stable route, therefore, reaction 1 is more likely to happen
- Since reaction 1 releases more energy than reaction 2, its end products will have a higher binding energy per nucleon