Mean Power
- In mains electricity, current and voltage are varying all the time
- This also means the power varies constantly, recall the equations for power:
- Where:
- I = direct current (A)
- V = direct voltage (V)
- R = resistance (Ω)
- The r.m.s values means equations used for direct current and voltage can now be applied to alternating current and voltage
- These are also used to determine an average current or voltage for alternating supplies
- Recall the equation for peak current:
- The peak (maximum) power and the mean (average) power are given by:
- Peak power can be written in terms of r.m.s current as
- Therefore, peak power is related to mean power by:
- Therefore, it can be concluded that:
The mean power in a resistive load is half the maximum power for a sinusoidal alternating current or voltage
Mean power is exactly half the maximum power
Worked example
An alternating voltage supplied across a resistor of 40 Ω has a peak voltage V0 of 240 V.Calculate the mean power of this supply.
Step 1: Write down the known quantities
Resistance, R = 40 Ω
Peak voltage, V0 = 240 V
Step 2: Write out the equation for the peak power and calculate
Step 3: Calculate the mean power
- The mean power is half of the maximum (peak) power
Mean power = 1440 / 2 = 720 W