Syllabus Edition

First teaching 2020

Last exams 2024

|

Root-Mean-Square Current & Voltage (CIE A Level Physics)

Revision Note

Test yourself
Katie M

Author

Katie M

Last updated

Root-Mean-Square Current & Voltage

  • Root-mean-square (r.m.s) values of current, or voltage, are a useful way of comparing a.c current, or voltage, to its equivalent direct current, or voltage
  • The r.m.s values represent the d.c current, or voltage, values that will produce the same heating effect, or power dissipation, as the alternating current, or voltage
  • The r.m.s value of an alternating current is defined as:

The value of a constant current that produces the same power in a resistor as the alternating current

  • The r.m.s current Ir.m.s is defined by the equation:

Root-Mean-Square Current & Voltage equation 1

  • So, r.m.s current is equal to 0.707 × I0, which is about 70% of the peak current I0
  • The r.m.s value of an alternating voltage is defined as:

The value of a constant voltage that produces the same power in a resistor as the alternating voltage

  • The r.m.s voltage Vr.m.s is defined by the equation:

Root-Mean-Square Current & Voltage equation 2

  • Where:
    • I0 = peak current (A)
    • V0 = peak voltage (V)

  • The r.m.s value is therefore defined as:

The steady direct current, or voltage, that delivers the same average power in a resistor as the alternating current, or voltage

  •  A resistive load is any electrical component with resistance eg. a lamp

RMS v Peak grap, downloadable AS & A Level Physics revision notes

Vr.m.s and peak voltage. The r.m.s voltage is about 70% of the peak voltage

Worked example

An alternating current is I is represented by the equation

I = 410 sin(100πt)

where I is measured in amperes and t is in seconds.For this alternating current, determine the r.m.s current.

Step 1: Write out the equation for r.m.s current

Root-Mean-Square Current & Voltage equation 1

Step 2: Determine the peak voltage I0

        • The alternating current equation is in the form: I = I0 sin(⍵t)
        • Comparing this to I = 410 sin(100πt) means the peak current is I0 = 410 A

Step 3: Substitute into the Ir.m.s equation

Root-Mean-Square Current & Voltage Worked Example equation 2

You've read 0 of your 10 free revision notes

Unlock more, it's free!

Join the 100,000+ Students that ❤️ Save My Exams

the (exam) results speak for themselves:

Did this page help you?

Katie M

Author: Katie M

Expertise: Physics

Katie has always been passionate about the sciences, and completed a degree in Astrophysics at Sheffield University. She decided that she wanted to inspire other young people, so moved to Bristol to complete a PGCE in Secondary Science. She particularly loves creating fun and absorbing materials to help students achieve their exam potential.