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The First Law of Thermodynamics (CIE A Level Physics)

Revision Note

Katie M

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Katie M

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The First Law of Thermodynamics

  • The first law of thermodynamics is based on the principle of conservation of energy
  • When energy is put into a gas by heating it or doing work on it, its internal energy must increase:

The increase in internal energy = Energy supplied by heating + Work done on the system

  • The first law of thermodynamics is therefore defined as:

ΔU = q + W

  • Where:
    • ΔU = increase in internal energy (J)
    • q = energy supplied to the system by heating (J)
    • W = work done on the system (J)

  • The first law of thermodynamics applies to all situations, not just for gases
    • There is an important sign convention used for this equation

  • A positive value for internal energy (+ΔU) means:
    • The internal energy ΔU of the system increases
    • Heat q is added to the system
    • Work W is done on the system

  • A negative value for internal energy (−ΔU) means:
    • The internal energy ΔU of the system decreases
    • Heat q is removed from the system
    • Work W is done by the system

  • This is important when thinking about the expansion or compression of a gas
  • When the gas expands, it transfers some energy (does work) to its surroundings
  • This decreases the overall energy of the gas
  • Therefore, when the gas expands, work is done by the gas (−W)

When a gas expands, work done W is negative

  • When the gas is compressed, work is done on the gas (+W)

When a gas is compressed, work done W is positive

Positive and negative work done

Positive or negative work done depends on whether the gas is compressed or expanded

Graphs of Constant Pressure & Volume

  • Graphs of pressure p against volume V can provide information about the work done and internal energy of the gas
    • The work done is represented by the area under the line

  • A constant pressure process is represented as a horizontal line
    • If the volume is increasing (expansion), work is done by the gas (on the surroundings) and internal energy decreases (ΔqW)
    • If the arrow is reversed and the volume is decreasing (compression), work is done on the gas and internal energy increases (ΔqW)
    • The volume of the gas is made smaller, so more collisions between the molecules of the gas and the walls of the container occur. This creates a higher pressure. 

  • A constant volume process is represented as a vertical line
    • In a process with constant volume, the area under the curve is zero
    • Therefore, no work is done when the volume stays the same

Work is only done when the volume of a gas changes

Worked example

The volume occupied by 1.00 mol of a liquid at 50 oC is 2.4 × 10-5 m3. When the liquid is vaporised at an atmospheric pressure of 1.03 × 105 Pa, the vapour has a volume of 5.9 × 10-2  m3.The latent heat to vaporise 1.00 mol of this liquid at 50 oC at atmospheric pressure is 3.48 × 104 J.Determine for this change of state the increase in internal energy ΔU of the system.

Step 1: Write down the first law of thermodynamics

ΔU = q + W

Step 2: Write the value of heating q of the system

This is the latent heat, the heat required to vaporise the liquid = 3.48 × 104 J

Step 3: Calculate the work done W

W = pΔV

ΔV = final volume − initial volume = 5.9 × 10-2 − 2.4 × 10-5 = 0.058976 m3

p = atmospheric pressure  = 1.03 × 105 Pa

W = (1.03 × 105) × 0.058976 = 6074.528 = 6.07 × 103 J

Since the gas is expanding, this work done is negative

W = −6.07 × 103 J

Step 4: Substitute the values into first law of thermodynamics

ΔU = 3.48 × 104  + (−6.07 × 103) = 28 730 = 29 000 J (2 s.f.)

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Katie M

Author: Katie M

Expertise: Physics

Katie has always been passionate about the sciences, and completed a degree in Astrophysics at Sheffield University. She decided that she wanted to inspire other young people, so moved to Bristol to complete a PGCE in Secondary Science. She particularly loves creating fun and absorbing materials to help students achieve their exam potential.