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Calculating Centripetal Force (CIE A Level Physics)

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Katie M

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Calculating Centripetal Force

  • An object moving in a circle is not in equilibrium, it has a resultant force acting upon it
    • This is known as the centripetal force and is what keeps the object moving in a circle

  • The centripetal force (F) is defined as:

The resultant force towards the centre of the circle required to keep a body in uniform circular motion. It is always directed towards the centre of the body's rotation.

  •  Centripetal force can be calculated using:

Calculating Centripetal Force equation 1

Centripetal force diagram, downloadable AS & A Level Physics revision notes

Centripetal force is always perpendicular to the direction of travel

  • Where:
    • F = centripetal force (N)
    • v = linear velocity (m s-1)
    • ⍵ = angular speed (rad s-1)
    • r = radius of the orbit (m)

  • Note: centripetal force and centripetal acceleration act in the same direction
    • This is due to Newton’s Second Law

  • The centripetal force is not a separate force of its own
    • It can be any type of force, depending on the situation, which keeps an object moving in a circular path

Examples of centripetal forceTable showing examples of centripetal force, downloadable AS & A Level Physics revision notes

  • When solving circular motion problems involving one of these forces, the equation for centripetal force can be equated to the relevant force equation
  • For example, for a mass orbiting a planet in a circular path, the centripetal force is provided by the gravitational force

  • When an object travels in circular motion, there is no work done
    • This is because there is no change in kinetic energy

Worked example

A 300 g ball is made to travel in a circle of radius 0.8 m on the end of a string. If the maximum force the ball can withstand before breaking is 60 N, what is the maximum speed of the ball?

Answer:

Step 1: List the known quantities

  • Mass, m = 300 g = 300 × 10-3 kg
  • Radius, r = 0.8 m
  • Resultant force, F = 60 N

Step 2: Rearrange the centripetal force equation for v

F subscript m a x end subscript space equals fraction numerator space m v squared subscript m a x end subscript over denominator r end fraction

v subscript m a x end subscript space equals square root of fraction numerator r F subscript m a x end subscript over denominator m end fraction end root

Step 3: Substitute in the values

v subscript m a x end subscript equals space square root of fraction numerator 0.8 space cross times space 60 over denominator 300 space cross times space 10 to the power of negative 3 end exponent end fraction end root space equals space12.6 m s–1

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Katie M

Author: Katie M

Expertise: Physics

Katie has always been passionate about the sciences, and completed a degree in Astrophysics at Sheffield University. She decided that she wanted to inspire other young people, so moved to Bristol to complete a PGCE in Secondary Science. She particularly loves creating fun and absorbing materials to help students achieve their exam potential.