Stefan's Law (AQA A Level Physics)

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Katie M

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Katie M

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Stefan's Law

  • The total power P radiated by a perfect black body depends on two factors:

    • It's absolute temperature

    • It's surface area

  • The relationship between these is known as Stefan's Law or the Stefan-Boltzmann Law, which states:

    The total energy emitted by a black body per unit area per second is proportional to the fourth power of the absolute temperature of the body

  • The Stefan-Boltzmann Law can be calculated using:

P space equals space sigma A T to the power of 4

  • Where:

    • P = total power emitted across all wavelengths (W)

    • σ = the Stefan-Boltzmann constant

    • A = surface area of the body (m)

    • T = absolute temperature of the body (K)

  • The Stefan-Boltzmann law is often used to calculate the luminosity of celestial objects, such as stars

  • The surface area of a star (or other spherical object) is equal to A = r2

    • Where r = radius of the star

  • The Stefan-Boltzmann equation then becomes:

L space equals space 4 straight pi r squared sigma T to the power of 4

  • Where:

    • L = luminosity of the star (W)

    • r = radius of the star (m)

    • σ = the Stefan-Boltzmann constant

    • T = surface temperature of the star (K)

Worked Example

The surface temperature of Proxima Centauri, the nearest star to Earth, is 3000 K and its luminosity is 6.506 × 1023 W.

Calculate the radius of Proxima Centauri in solar radii and show your working clearly. 

Solar radius R = 6.96 × 108 m

Answer:

Step 1: List the known quantities: 

  • Surface temperature, T = 3000 K

  • Luminosity, = 6.506 × 1023 W

  • Stefan's constant, σ = 5.67 × 10−8 W m−2 K−4

  • Radius of the Sun, R = 6.96 × 108 m

Step 2: Write down the Stefan-Boltzmann equation and rearrange for radius r

L space equals space 4 straight pi R squared sigma T to the power of 4

R space equals space square root of fraction numerator L over denominator 4 straight pi sigma T to the power of 4 end fraction end root

Step 3: Substitute the values into the equation 

R space equals space square root of fraction numerator 6.506 cross times 10 to the power of 23 over denominator 4 straight pi cross times left parenthesis 5.67 cross times 10 to the power of negative 8 end exponent right parenthesis cross times 3000 to the power of 4 end fraction end root

Radius of Proxima Centauri:  R = 1.061 × 108 m

Step 4: Find the ratio of the radii of Proxima Centauri and the Sun

R over R subscript ☉ space equals space fraction numerator 1.061 space cross times space 10 to the power of 8 over denominator 6.96 space cross times space 10 to the power of 8 end fraction space equals space 0.152 space R subscript ☉

  • Proxima Centauri has a radius which is about 0.152 times smaller than the Sun

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Katie M

Author: Katie M

Expertise: Physics

Katie has always been passionate about the sciences, and completed a degree in Astrophysics at Sheffield University. She decided that she wanted to inspire other young people, so moved to Bristol to complete a PGCE in Secondary Science. She particularly loves creating fun and absorbing materials to help students achieve their exam potential.