Lenses & Ray Diagrams for Telescopes (AQA A Level Physics): Revision Note

Exam code: 7408

Katie M

Written by: Katie M

Reviewed by: Timothy Sit

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Lenses & ray diagrams for telescopes

  • A lens is a piece of equipment that forms an image by refracting light

  • There are two types of lenses: 

    • a convex, or converging lens

    • a concave, or diverging lens

  • Note: in the Astrophysics module, only converging lenses will be discussed

  • In a converging lens, parallel rays of light are brought to a focus along the principal axis

    • This point is called the focal point

  • The distance from the centre of the lens to the focal point is called the focal length

    • This length depends on how curved, or how thick, the lens is

    • The more curved (thicker) the lens, the shorter the focal length

    • The shorter the focal length, the more powerful the lens

The thinner converging lens has a longer focal length and is less powerful, while the thicker, more curved lens has a shorter focal length and is more powerful. Parallel rays converge at each focal point.
The focal length is shorter in a lens that is thicker and more curved. This makes for a more powerful lens

Real and virtual images

  • Images produced by lenses can be either real or virtual

Real image

Virtual image

Light converges towards a focal point

Light diverges away from a focal point

Always inverted

Always upright

Can be projected onto a screen

Cannot be projected onto a screen

Intersection of two solid lines

Intersection of two dashed lines (or a dashed and a solid line)

A projector refracts light to form a real image on a screen. The inverted landscape image is labelled “real image”.
Example: image from a projector onto a screen
Illustration of a person viewing an upright reflection in a mirror. The reflected image is labelled “virtual image”.
Example: image in a mirror

Constructing ray diagrams

  • When constructing ray diagrams of refractors, it is generally assumed that the lenses used are very thin

    • This simplifies the situation by reducing the amount the incident rays of light refract

  • As a result, the three main rules for constructing ray diagrams are as follows:

1. Rays passing through the principal axis will pass through the optical centre of the lens undeviated

A red ray travels in a straight line through the converging lens’s optical centre without deviating. The horizontal dashed principal axis has focal points labelled f on both sides.
A ray passing directly through the optical center of a converging lens is undeviated

2. Rays that are parallel to the principal axis will be refracted and pass through the focal point f

A red ray travelling parallel to the principal axis of a converging lens is refracted by the lens and passes through the focal point, labelled f, on the right. Focal points are marked on both sides.
A ray traveling parallel to the principal axis will refract towards the focal point of the converging lens

3. Rays passing through the focal point f will emerge parallel to the principal axis

A red ray passing through the left focal point of a converging lens emerges parallel to the principal axis. The lens, principal axis and focal points are labelled.
A ray passing through the focal point of a converging lens will refract parallel to the principal axis

Image formation by a converging lens

  • Images formed by lenses can be described by their:

    • nature: Real or virtual

    • orientation: Inverted or upright (compared to the object)

    • size: Magnified (larger), diminished (smaller), or the same size (compared to the object)

Drawing ray diagrams of real images

  • For an object placed at a distance greater than two focal lengths...

An upright object lies beyond 2f to the left of a converging lens. A parallel ray passes through the right-hand focal point and a central ray continues undeviated, forming a real image between f and 2f.
An object beyond 2f produces a real, inverted, diminished image between f and 2f
  • The image that forms will have the following properties:

The image forms...

between f and 2f

The nature of the image is...

real

The orientation of the image is...

inverted

The size of the image is...

diminished

  • For an object placed at a distance equal to two focal lengths...

An upright object lies at 2f to the left of a converging lens. A parallel ray passes through the right-hand focal point and a central ray continues undeviated, forming a real image at the right 2f.
An object at 2f produces a real, inverted, same size image at 2f
  • The image that forms will have the following properties:

The image forms...

at 2f

The nature of the image is...

real

The orientation of the image is...

inverted

The size of the image is...

the same

  • For an object placed at a distance between one and two focal lengths

An upright object lies between f and 2f to the left of a converging lens. A parallel ray passes through the right-hand focal point and a central ray continues undeviated, forming a real image beyond 2f.
An object between f and 2f produces a real, inverted, magnified image beyond 2f
  • The image that forms will have the following properties:

The image forms...

beyond 2f

The nature of the image is...

real

The orientation of the image is...

inverted

The size of the image is...

magnified

Drawing ray diagrams of virtual images

  • For an object placed at a distance less than the focal length (i.e. a magnifying glass):

Ray diagram for an object closer than f to a converging lens. Refracted rays diverge, with dashed virtual rays meeting at an upright, magnified virtual image at 2f on the object’s side. Labels show f, 2f, object and virtual rays.
An object inside f produces a virtual, upright, magnified image at 2f
  • The image that forms will have the following properties:

The image forms...

at 2f (on the same side as the object)

The nature of the image is...

virtual

The orientation of the image is...

upright

The size of the image is...

magnified

Worked Example

Draw a ray diagram to show how a converging lens can be used to form a diminished image of a real object.

Label the object, image and principal foci of the lens on your diagram.

[3]

Answer:

Step 1: Start by drawing and labelling a principal axis and the lens as a line or a very thin ellipse

A converging lens shown by a vertical double arrow crossing a horizontal line labelled principal axis.

Step 2: Mark and label the focal points on each side of the lens

A converging lens shown by a vertical double arrow crossing a horizontal line labelled principal axis and focal points F marked symmetrically on either side of the lens.

Step 3: Draw and label the object at a distance greater than the focal length on the left side of the lens

A converging lens shown by a vertical double arrow crossing a horizontal line labelled principal axis and focal points F marked symmetrically on either side of the lens. An upright object is placed at a distance at least 2F away from the centre of the lens.
  • Tip: the object should be placed a distance of at least 2F away from the lens

Step 4: Draw a ray through the optical centre of the lens 

A converging lens shown by a vertical double arrow crossing a horizontal line labelled principal axis and focal points F marked symmetrically on either side of the lens. An upright object is placed at a distance at least 2F away from the centre of the lens. A ray is drawn from the top of the object towards the optical centre of the lens.

[1 mark]

Step 5: Draw a second ray from the object to the lens which is parallel to the principal axis

A converging lens shown by a vertical double arrow crossing a horizontal line labelled principal axis and focal points F marked symmetrically on either side of the lens. An upright object is placed at a distance at least 2F away from the centre of the lens. A ray is drawn from the top of the object towards the optical centre of the lens. A ray parallel to the principal axis is drawn towards the lens.

Step 6: Draw the continuation of the ray passing through the focal point on the right side of the lens

A converging lens shown by a vertical double arrow crossing a horizontal line labelled principal axis and focal points F marked symmetrically on either side of the lens. An upright object is placed at a distance at least 2F away from the centre of the lens. A ray is drawn from the top of the object towards the optical centre of the lens. A ray parallel to the principal axis is drawn towards the lens. The parallel ray is refracted and passes through the focal point on the far side.

[1 mark]

Step 7: Draw and label the image at the point where the rays meet

A converging lens shown by a vertical double arrow crossing a horizontal line labelled principal axis and focal points F marked symmetrically on either side of the lens. An upright object is placed at a distance at least 2F away from the centre of the lens. A ray is drawn from the top of the object towards the optical centre of the lens. A ray parallel to the principal axis is drawn towards the lens. The parallel ray is refracted and passes through the focal point on the far side. The image is drawn at the point where the two rays meet.

Step 8: Check your final image and make sure everything is included to gain the marks

A converging lens shown by a vertical double arrow crossing a horizontal line labelled principal axis and focal points F marked symmetrically on either side of the lens. An upright object is placed at a distance at least 2F away from the centre of the lens. A ray is drawn from the top of the object towards the optical centre of the lens. A ray parallel to the principal axis is drawn towards the lens. The parallel ray is refracted and passes through the focal point on the far side. The image is drawn at the point where the two rays meet.

[1 mark]

  • For a three-mark question, examiners will be looking for:

    • one ray drawn through the optical centre of the lens

    • a second ray drawn which produces a diminished (smaller) image (which must pass through a labelled focal point)

    • both the object and the image must be drawn and labelled correctly

Examiner Tips and Tricks

When drawing ray diagrams, convex (converging) and concave (diverging) lenses can be simplified using the following symbols:

A convex (converging) lens is shown as a double-arrow symbol and oval lens, while a concave (diverging) lens is shown as an inward-pointing double-arrow symbol and thinner-centred lens.

The lens equation & magnification

The lens equation

  • The lens equation relates the focal length of a lens to the distances between the lens and the image and the object

1f = 1u + 1v

  • Where:

    • f = focal length (m)

    • v = distance of the image from lens (m)

    • u = distance of the object from lens (m)

Lens equation for a real image

An upright object at distance u from a converging lens forms an inverted real image at distance v. Focal length f is marked. Distances are positive. Lens equation: one over f equals one over u plus one over v.
All values are positive for a real image
  • This equation only works for thin converging (or diverging) lenses

    • If the image is real, the value of v is positive 

    • If the image is virtual, the value of v is negative

Lens equation for a virtual image

An upright object inside the focal length of a converging lens produces diverging rays and a virtual upright image on the object’s side. The image distance v is negative. Lens equation is one over f equals one over u minus one over v.
A virtual image forms on the same side as the object making the value of v negative

Magnification as a ratio of heights

  • Magnification, M, is the ratio of the image height to the object height

M = hiho

  • Where:

    • M = magnification

    • hi = image height (m)

    • ho = object height (m)

Magnification as a ratio of distances

  • A diagram of an object and its real image will produce similar triangles

  • Therefore, magnification can be determined by comparing the distances from the lens to the object and the image

Magnification ray diagram for a real image

Ray diagram of a real image formed by a converging lens. An upright object of height hₒ at distance u forms an inverted image of height hᵢ at distance v. Red rays show similar triangles used to derive magnification.
Magnification for a real image can be derived using similar triangles
  • This also works for virtual images

Magnification ray diagram for a virtual image

Ray diagram for magnification of a virtual image. An upright object of height hₒ lies a distance u from a converging lens. Diverging rays are extended backwards to form an upright magnified virtual image hᵢ, at a distance v from the lens.
Magnification for a virtual image can also be derived using similar triangles
  • As magnification can be described using the ratio of the two opposite sides hi and ho, the same ratio must apply to the two adjacent sides v and u

  • Therefore, magnification can also be written as:

 M = vu

  • Where:

    • M = magnification

    • v = distance from lens to image (m)

    • u = distance from lens to object (m)

  • Since magnification is a ratio, it has no units

Worked Example

A magnifying glass has a focal length of 15 cm. It is held 5 cm away from a component which is being examined. 

Determine the magnification of the image.

[2]

Answer:

Step 1: Write the known values

  • Focal length, f = 15 cm

  • Distance between object and lens, u = 5 cm

Step 2: Use the lens formula and rearrange to make v the subject

1f = 1u + 1v

v = (1f − 1u)−1

v = (115 − 15)−1 = −7.5 cm [1 mark]

  • The negative sign indicates a virtual image is formed (expected for a magnifying glass) and can be ignored for the next step

Step 3: Use the magnification formula to find the magnification of the image

M = vu = 7.5 5 = 1.5 [1 mark]

Examiner Tips and Tricks

Some of the equations on this page may seem different from the equations on the specification for the Astrophysics module - don't worry, these are covered in the next revision note. These notes are here if you need to refresh your knowledge of lenses and ray diagrams from GCSE.

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Katie M

Author: Katie M

Expertise: Curriculum Expert

Katie has always been passionate about the sciences, and completed a degree in Astrophysics at Sheffield University. She decided that she wanted to inspire other young people, so moved to Bristol to complete a PGCE in Secondary Science. She particularly loves creating fun and absorbing materials to help students achieve their exam potential.

Timothy Sit

Reviewer: Timothy Sit

Expertise: Content Creator

Timothy graduated with a first class degree in Mathematics and Physics from the University of Warwick. After working as a postgraduate researcher, Timothy has worked as a content creator for various online revision platforms, creating physics resources for a range of levels and exam boards.