Magnetic Flux Linkage (AQA A Level Physics)

Revision Note

Katie M

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Katie M

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Magnetic Flux Linkage

  • More coils in a wire mean a larger e.m.f is induced

  • The magnetic flux linkage is a quantity commonly used for solenoids which are made of N turns of wire

  • The flux linkage is defined as:

    The product of the magnetic flux and the number of turns of the coil

  • It is calculated using the equation:

Magnetic flux linkage = ΦN = BAN

  • Where:

    • Φ = magnetic flux (Wb)

    • N = number of turns of the coil

    • B = magnetic flux density (T)

    • A = cross-sectional area (m2)

 

  • The flux linkage ΦN has the units of Weber turns (Wb turns)

Flux Linkage in a Rotating Rectangular Coil

  • When the magnet field lines are not completely perpendicular to the area A, then the component of magnetic flux density B is perpendicular to the area is taken

  • The equation then becomes:

Φ = BA cos(θ)

  • Where:

    • Φ = magnetic flux (Wb)

    • B = magnetic flux density (T)

    • A = cross-sectional area (m2)

    • θ = angle between magnetic field lines and the line perpendicular to the plane of the area (often called the normal line) (degrees)

  • This means the magnetic flux is:

    • Maximum = BA when cos(θ) =1 therefore θ = 0o. The magnetic field lines are perpendicular to the plane of the area

    • Minimum = 0 when cos(θ) = 0 therefore θ = 90o. The magnetic fields lines are parallel to the plane of the area

  • An e.m.f is induced in a circuit when the magnetic flux linkage changes with respect to time

  • This means an e.m.f is induced when there is:

    • A changing magnetic flux density B

    • A changing cross-sectional area A

    • A change in angle θ

Flux Linkage, downloadable AS & A Level Physics revision notes

The magnetic flux through a rectangular coil decreases as the angle between the field lines and plane decrease

  • Magnetic field lines may not be completely perpendicular to the plane of the area that they pass through

  • Therefore, the component of the flux density which is perpendicular is equal to:

ΦN = BAN cos(θ)

  • Where:

    • N = number of turns of the coil

Worked Example

A solenoid of circular cross-sectional radius 0.40 m and 300 turns is placed perpendicular to a magnetic field with a magnetic flux density of 5.1 mT. Determine the magnetic flux linkage for this solenoid.

Answer:

Step 1: Write out the known quantities

  • Cross-sectional area, A = πr2 = π(0.4)2 = 0.503 m2

    • Magnetic flux density, B = 5.1 mT

    • Number of turns of the coil, N = 300 turns

Step 2: Write down the equation for the magnetic flux linkage

ΦN = BAN

Step 3: Substitute in values and calculate

ΦN = (5.1 × 10-3) × 0.503 × 300 = 0.7691 = 0.77 Wb turns (2 s.f)

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Katie M

Author: Katie M

Expertise: Physics

Katie has always been passionate about the sciences, and completed a degree in Astrophysics at Sheffield University. She decided that she wanted to inspire other young people, so moved to Bristol to complete a PGCE in Secondary Science. She particularly loves creating fun and absorbing materials to help students achieve their exam potential.