Radial Electric Field (AQA A Level Physics)

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Electric Field of a Point Charge

  • The strength of an electric field due to a point charge decreases with the square of the distance
    • This is an inverse square law, similar to Coulomb's law
  • Using Coulomb's law and the electric field strength equation this can be written as

E space equals space F over q space equals space fraction numerator Q over denominator 4 straight pi epsilon subscript 0 r squared end fraction

  • Where:
    • Q = the point charge producing the radial electric field (C)
    • r = distance from the centre of the charge (m)
    • ε0 = permittivity of free space (F m−1)
  • Here, q represents the magnitude of a small positive test charge
  • This equation shows that in a radial electric field, the electric field strength E:
    • is not constant
    • follows an inverse square law with distance r

Graph of field strength against distance for a positive charge

4-2-6-electric-field-around-charged-sphere

Electric field strength is zero inside a charged sphere and decreases with distance outside the sphere according to an inverse square law

Combining Electric Fields

  • Both electric force and field strength are vector quantities
    • If the charge is negative, the E field strength is negative and points towards the centre of the charge
    • If the charge is positive, the E field strength is positive and points away from the centre of the charge
  • Therefore, to find the electric force or field strength at a point due to multiple charges, each field can be combined by vector addition

Vector addition of electric field along the same line

vector-addition-of-electric-field-strength

For charges along the same line, the resultant field is the vector addition of the field due to both charges at a particular point

  • For a point on the same line as two charges q1 and q2, with field strengths E1 and E2 respectively, the magnitude of the resultant field will be:
    • The sum of the fields, E1 + E2, if they are both in the same direction
    • The difference between the fields, E1E2, if they are in opposite directions
  • The direction of the resultant field depends on:
    • The types of charge (positive or negative)
    • The magnitude of the charges
  • For a point which makes a right-angled triangle with the charges, the resultant field can be determined using Pythagoras theorem

Vector addition of electric field components

4-2-5-vector-addition-of-electric-field-strength-with-pythagoras

For charges which make a right-angle triangle with point X, the resultant field is the vector addition of the field due to both charges using Pythagoras theorem

Worked example

A metal sphere of diameter 15 cm is negatively charged. The electric field strength at the surface of the sphere is 1.5 × 105 V m−1.

Determine the total surface charge of the sphere.

Answer:

Step 1: List the known quantities

  • Electric field strength, E = 1.5 × 105 V m−1
  • Radius of sphere, r = 15 / 2 = 7.5 cm = 7.5 × 102 m
  • Permittivity of free space, ε0 = 8.85 × 1012 F m−1

Step 2: Write down the equation for electric field strength

E space equals space fraction numerator Q over denominator 4 straight pi epsilon subscript 0 r squared end fraction

Step 3: Rearrange for charge Q

  • Recall that, for an external observer, a charged sphere can be considered as a point charge
  • The field strength at the surface of the sphere is equal to the field strength 15 cm away from a point charge with the same total charge as the sphere

Q space equals space 4 straight pi epsilon subscript 0 E r squared

Step 4: Substitute in the values and calculate:

Q = (4π × 8.85 × 1012) × (1.5 × 105) × (7.5 × 102)2 = 9.38 × 108 C

  • The particle has a charge of 9.4 × 10−8 C or 94 nC

Examiner Tip

When combining electric fields from multiple charges, remember that the point (e.g. point X in the examples above) represents a positive test charge, so the direction of the electric force or field will correspond to the signs of the charges; the direction of the force or field points away from a positive charge and towards a negative charge.

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Katie M

Author: Katie M

Expertise: Physics

Katie has always been passionate about the sciences, and completed a degree in Astrophysics at Sheffield University. She decided that she wanted to inspire other young people, so moved to Bristol to complete a PGCE in Secondary Science. She particularly loves creating fun and absorbing materials to help students achieve their exam potential.