Calculating Gravitational Potential (AQA A Level Physics)

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Katie M

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Katie M

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Calculating Gravitational Potential

  • The equation for gravitational potential V is defined by the mass M and distance r:

Gravitational Potential Equation_2
  • Where:

    • V = gravitational potential (J kg-1)

    • G = Newton’s gravitational constant

    • M = mass of the body producing the gravitational field (kg)

    • r = distance from the centre of the mass to the point mass (m)

  • The gravitational potential always is negative near an isolated mass, such as a planet, because:

    • The potential when r is at infinity (∞) is defined as 0

    • Work must be done to move a mass away from a planet (V becomes less negative)

  • It is also a scalar quantity, unlike the gravitational field strength which is a vector quantity

 

  • Gravitational forces are always attractive, this means as r decreases, positive work is done by the mass when moving from infinity to that point

    • When a mass is closer to a planet, its gravitational potential becomes smaller (more negative)

    • As a mass moves away from a planet, its gravitational potential becomes larger (less negative) until it reaches 0 at infinity

  • This means when the distance (r) becomes very large, the gravitational force tends rapidly towards 0 at a point further away from a planet

Gravitational potential diagram, downloadable AS & A Level Physics revision notes

Gravitational potential increases and decreases depending on whether the object is travelling towards or against the field lines from infinity

Worked Example

A planet has a diameter of 7600 km and a mass of 3.5 × 1023 kg. A rock of mass 528 kg accelerates towards the planet from infinity. At a distance of 400 km above the planet's surface, calculate the gravitational potential of the rock.

Answer:

Step 1: Write the gravitational potential equation

Gravitational Potential Equation_2

Step 2: Determine the value of r

  • r is the distance from the centre of the planet

Radius of the planet = planet diameter ÷ 2 = 7600 ÷ 2  = 3800 km

r = 3800 + 400 = 4200 km = 4.2 × 106 m

Step 3: Substitute in values

Gravitational Potential Worked Example Step 3_2

Examiner Tips and Tricks

Remember to keep the negative sign in your solution for the gravitational potential at a point. However, if you’re asked for the ‘change in’ gravitational potential, no negative sign needs to be included since you are finding a difference in values and just the magnitude is normally required. Remember to also calculate r as the distance from the centre of the planet, and not just the distance above the planet's surface

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Katie M

Author: Katie M

Expertise: Physics

Katie has always been passionate about the sciences, and completed a degree in Astrophysics at Sheffield University. She decided that she wanted to inspire other young people, so moved to Bristol to complete a PGCE in Secondary Science. She particularly loves creating fun and absorbing materials to help students achieve their exam potential.