Potential Divider Circuits (AQA A Level Physics)
Revision Note
Potential Divider Circuit
When two resistors are connected in series, through Kirchhoff’s Second Law, the potential difference across the power source is divided between them
Potential dividers are circuits which produce an output voltage as a fraction of its input voltage
Potential dividers have three main purposes:
To provide a variable potential difference
To enable a specific potential difference to be chosen
To split the potential difference of a power source between two or more components
Potential dividers are used widely in volume controls and sensory circuits using LDRs and thermistors
Potential divider circuits are based on the ratio of voltage between components. This is equal to the ratio of the resistances of the resistors in the diagram below, giving the following equation:
Potential divider diagram and equation
Where:
R2 is the numerator and the resistance of the resistor over Vout
R1 is the other resistance in series
Vout is the output potential difference
Vin is the input potential difference
The potential divider equation can also be written:
Where this time:
R1 is the numerator and the resistance of the resistor over Vout
R2 is the other resistance in series
Whichever notation you use you will obtain the same answer
The numerator has to be the resistance of the resistor over Vout
In the circuit shown above:
The input voltage Vin is applied to the top and bottom of the series resistors
The output voltage Vout is measured from the centre to the bottom of resistor R2
The potential difference V across each resistor depends upon its resistance R:
The resistor with the largest resistance will have a greater potential difference than the other one from V = IR
If the resistance of one of the resistors is increased, it will get a greater share of the potential difference, whilst the other resistor will get a smaller share
In potential divider circuits, the p.d across a component is proportional to its resistance from V = IR
Worked Example
The circuit is designed to light up a lamp when the input voltage exceed a preset value.
It does this by comparing Vout with a fixed reference voltage of 5.3 V.
Vout is equal to 5.3
Calculate the input voltage Vin.
Answer:
Examiner Tips and Tricks
Always make sure the correct resistance is in the numerator of the potential divider equation. This will be the resistance of the component you want to find the output voltage of.
Variable Resistance Components
Variable and sensory resistors are used in potential dividers to vary the output voltage
This could cause an external component to switch on or off e.g. a heater switching off automatically when its surroundings are at room temperature
Sensory resistors used are Light Dependent Resistors (LDRs) and thermistors
LDR and thermistor in a potential divider circuit with a fixed resistor R
The voltmeter in both circuits is measuring Vout
Recall that the resistance of an LDR varies with light intensity
The higher the light intensity, the lower the resistance and vice versa
An LDR circuit is often used for street and security lights
The resistance of a thermistor varies with temperature
The hotter the thermistor, the lower the resistance and vice versa
A thermistor circuit is used in fire alarms, ovens and digital thermometers
From Ohm’s law V = IR, the potential difference Vout from a resistor in a potential divider circuit is proportional to its resistance
If an LDR or thermistor's resistance decreases, the potential difference through it also decreases
If an LDR or thermistor's resistance increases, the potential difference through it also increases
Since the total p.d of the components must be equal to Vin, if the p.d of the sensory resistor decreases then the p.d of the other resistor in the circuit must increase and vice versa
Worked Example
A potential divider consists of a fixed resistor R and a thermistor.
What happens to the p.d through resistor R and the thermistor when the temperature of the thermistor decreases?
Answer: D
Due to Ohm’s Law (V = IR), both the resistor and thermistor are connected in series and have the same current I
If resistance R increases, the potential difference across the thermistor also increases
In series, the potential difference is shared equally amongst the components. Their sum equals the e.m.f of the supply (Kirchhoff’s second law)
If the potential difference across the thermistor increases, the potential difference across the resistance R must decreases, to keep the same overall total e.m.f
This is row D
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