Particles, Antiparticles & Photons (AQA A Level Physics) : Revision Note

Katie M

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Katie M

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Antimatter

  • The Universe consists of matter in the form of particles i.e. protons, neutrons, electrons, etc.

  • All particles of matter have an antimatter counterpart

  • Antimatter particles are identical to their matter counterpart but have an opposite charge

    • This means if a particle is positive, its antimatter particle is negative, and vice versa

  • Common matter-antimatter pairs are shown in the table below:

Matter-Antimatter Table

2.1.5Antimatter-Table
  • Apart from electrons, the corresponding antiparticle has

    • The same name with the prefix ‘anti-’

    • A line above its corresponding matter particle symbol

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Properties of Antiparticles

  • Corresponding matter and antimatter particles have 

    • Opposite charges 

    • The same mass

    • The same rest mass-energy

  • The rest mass-energy of a particle is the energy equivalent to the mass of the particle when it is at rest

  • Some values of common particle masses and rest mass-energies are shown in the table below:

Mass & Rest Mass Energy Table

Properties of Antiparticles_ Mass & Rest Mass Energy Table, downloadable AS & A Level Physics revision notes

Examiner Tips and Tricks

In the exam, don't forget that the datasheet provides masses in kg and rest-mass energies in MeV for a proton, neutron, electron and neutrino

The Photon Model

  • Photons are fundamental particles which make up all forms of electromagnetic radiation

  • A photon is defined as:

A massless “packet” or a “quantum” of electromagnetic energy

  • This means that energy is not transferred continuously but as discrete packets of energy

  • In other words, each photon carries a specific amount of energy, or "quanta", and transfers it all in one go, rather than supplying it consistently

Calculating Photon Energy

  • The energy of a photon can be calculated using the formula:

E space equals space h f

  • Using the wave equation, photon energy can also be written:

E space equals space fraction numerator h c over denominator lambda end fraction

  • Where:

    • E = energy of the photon (J)

    • h = Planck's constant (J s)

    • c = the speed of light (m s-1)

    • f = frequency (Hz)

    • λ = wavelength (m)

  • This equation tells us:

    • The higher the frequency of EM radiation, the higher the energy of the photon

    • The energy of a photon is inversely proportional to the wavelength

    • A long-wavelength photon of light has a lower energy than a shorter-wavelength photon

Photon Energy

The energy of a photon is linked to the frequency of the light wave by the Planck constant, h

Worked Example

Light of wavelength 490 nm is incident normally on a surface, as shown in the diagram.

The power of the light is 3.6 mW. The light is completely absorbed by the surface.

Calculate the number of photons incident on the surface in 2.0 s.

Answer:

Step 1: Write down the known quantities

  • Wavelength, lambda space equals space 490 space nm space equals space 490 cross times 10 to the power of negative 9 end exponent space straight m

  • Power, P space equals space 3.6 space mW space equals space 3.6 cross times 10 to the power of negative 3 end exponent space straight W

  • Time, t space equals space 2.0 space straight s

Step 2: Write down the equations for wave speed and photon energy

Wave speed: c space equals space f lambda space space space rightwards arrow space space space f space equals space c over lambda

Photon energy: E space equals space h f space space space rightwards arrow space space space E space equals space fraction numerator h c over denominator lambda end fraction

Step 3: Calculate the energy of one photon

E space equals space fraction numerator h c over denominator lambda end fraction space equals space fraction numerator open parentheses 6.63 cross times 10 to the power of negative 34 end exponent close parentheses open parentheses 3.0 cross times 10 to the power of 8 close parentheses over denominator 490 cross times 10 to the power of negative 9 end exponent end fraction space equals space 4.06 cross times 10 to the power of negative 19 end exponent space straight J

Step 4: Calculate the number of photons hitting the surface each second

fraction numerator power space of space light space source over denominator energy space of space one space photon end fraction space equals space fraction numerator 3.6 cross times 10 to the power of negative 3 end exponent over denominator 4.06 cross times 10 to the power of negative 19 end exponent end fraction space equals space 8.9 cross times 10 to the power of 15 space straight s to the power of negative 1 end exponent

Step 5: Calculate the number of photons that hit the surface in 2.0 s

open parentheses 8.9 cross times 10 to the power of 15 close parentheses cross times 2 space equals space 1.8 cross times 10 to the power of 16

Examiner Tips and Tricks

Make sure you learn the definition for a photon: discrete quantity / packet / quantum of electromagnetic energy are all acceptable definitions. The values of Planck’s constant and the speed of light will always be available on the datasheet, however, it helps to memorise them to speed up calculation questions!

Annihilation & Pair Production

  • Two important interactions involving particles, antiparticles and photons are:

    • Annihilation 

    • Pair production

Annihilation

  • When a particle meets its corresponding antiparticle, the two will annihilate

  • Annihilation is defined as:

The destruction of a particle-antiparticle pair when they collide and convert their mass into two gamma-ray photons

  • The two most common particle-antiparticle pairs that are seen are:

    • Proton-antiproton annihilation

    • Electron-positron annihilation

2.1.5Annihilation

When an electron and positron collide, their mass is converted into energy in the form of two photons emitted in opposite directions

  • The minimum energy of one photon after annihilation is the total rest mass energy of one of the particles:

E subscript m i n end subscript space equals space h f subscript m i n end subscript space equals space E

  • Where:

    • E subscript m i n end subscript = minimum energy of one of the photons produced (J)

    • h = Planck's Constant (J s)

    • f subscript m i n end subscript = minimum frequency of one of the photons produced (Hz)

    • E = rest mass energy of one of the particles (J)

  • To conserve momentum, the two photons will move apart in opposite directions

  • As with all collisions, the mass and energy is still conserved

Pair Production

  • Pair production is the opposite of annihilation, it is defined as:

The creation of a particle-antiparticle pair when a high-energy photon spontaneously converts its energy into mass

  • To achieve pair production, a single photon must have enough energy to create both particles

2.2.5 Pair Production

When a photon with enough energy interacts with a nucleus it can produce an electron-positron pair

  • The minimum energy required for a photon to undergo pair production is equal to the total rest mass energy of the particles produced:

E subscript m i n end subscript space equals space h f subscript m i n end subscript space equals space 2 E

  • Where:

    • E subscript m i n end subscript = minimum energy of the incident photon (J)

    • h = Planck's Constant (J s)

    • f subscript m i n end subscript = minimum frequency of the photon (Hz)

    • E = rest mass energy of one of the particles (J)

  • To conserve momentum, the particle and the antiparticle move apart in opposite directions

Worked Example

Calculate the maximum wavelength of one of the photons produced when a proton and antiproton annihilate each other.

Answer:

Step 1: Write down the known quantities

  • Rest mass of a proton (and antiproton) = 938.257 space MeV

  • 1 space MeV space equals space 1.60 cross times 10 to the power of negative 13 end exponent space straight J

Step 2: Write down the equation for minimum photon energy

E subscript m i n end subscript space equals space h f subscript m i n end subscript space equals space fraction numerator h c over denominator lambda subscript m a x end subscript end fraction

Step 3: Rearrange for the maximum photon wavelength

lambda subscript m a x end subscript space equals space fraction numerator h c over denominator E subscript m i n end subscript end fraction

Step 4: Calculate the maximum photon wavelength

lambda subscript m a x end subscript space equals space fraction numerator open parentheses 6.63 cross times 10 to the power of negative 34 end exponent close parentheses open parentheses 3.0 cross times 10 to the power of 8 close parentheses over denominator open parentheses 938.257 close parentheses open parentheses 1.60 cross times 10 to the power of negative 13 end exponent close parentheses end fraction space equals space 1.32 cross times 10 to the power of negative 15 end exponent space straight m

Examiner Tips and Tricks

Since the Planck constant is in Joules (J) remember to always convert the rest mass-energy from MeV to J.

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Katie M

Author: Katie M

Expertise: Physics Content Creator

Katie has always been passionate about the sciences, and completed a degree in Astrophysics at Sheffield University. She decided that she wanted to inspire other young people, so moved to Bristol to complete a PGCE in Secondary Science. She particularly loves creating fun and absorbing materials to help students achieve their exam potential.