Alpha & Beta Decay (AQA A Level Physics): Revision Note

Exam code: 7408

Katie M

Written by: Katie M

Reviewed by: Tim

Updated on

α & β decay equations

  • When nuclei are unstable, they can become more stable through the process of radioactive decay

  • Three of the most common decay mechanisms are:

    • Alpha decay

    • Beta-minus decay

    • Beta-plus decay

Alpha decay

  • Alpha decay is common in large, unstable nuclei with too many nucleons (protons and neutrons)

  • The decay involves a nucleus emitting an alpha particle and decaying into a different nucleus

  • An alpha particle consists of 2 protons and 2 neutrons

    • This is equivalent to a helium nucleus

A parent nucleus containing blue neutrons and pink protons emits an alpha particle, shown as helium-4 with two protons and two neutrons, leaving a smaller daughter nucleus.
During alpha decay, a parent nucleus becomes a daughter nucleus by emitting an alpha particle (helium nucleus)
  • When an unstable nucleus (the parent nucleus) emits radiation, the constitution of its nucleus changes

  • As a result, the isotope will change into a different element (the daughter nucleus)

  • Alpha decay can be represented by the following radioactive decay equation:

XZA → YZ−2A−4 + α24

e.g. Po84212 → Pb82208 + α24

  • When an alpha particle is emitted from a nucleus:

    • The nucleus loses 2 protons: proton number decreases by 2

    • The nucleus loses 4 nucleons: nucleon number decreases by 4

Beta-minus decay

  • A beta-minus, β-, particle is a high energy electron emitted from the nucleus

  • β- decay is when a neutron turns into a proton emitting an electron and an anti-electron neutrino

A neutron becomes a proton, emitting an electron (beta particle) and an anti-electron neutrino; equation shown is “n → p + e− + anti-ν_e”.
During beta-minus decay, a neutron in a parent nucleus becomes a proton in a daughter nucleus by emitting a beta-minus particle (an electron) and an anti-electron neutrino
  • When a β- particle is emitted from a nucleus:

    • The number of protons increases by 1: proton number increases by 1

    • The total number of nucleons stays the same: nucleon number remains the same

XZA → YZ+1A + β−10 + ν¯e00

e.g. C614 → N714 + β−10 + ν¯e00

  • The new nucleus formed from the decay is called the 'daughter' nucleus (nitrogen in the example above)

Beta-plus decay

  • A beta-plus, β+, particle is a high energy positron emitted from the nucleus

  • β+ decay is when a proton turns into a neutron emitting a positron (anti-electron) and an electron neutrino

A proton changes into a neutron, emitting a positron (beta particle) and an electron neutrino; equation shown is “p → n + e⁺ + νₑ”.
During beta-plus decay, a proton in a parent nucleus becomes a neutron in a daughter nucleus by emitting a beta-plus particle (a positron) and an electron neutrino
  • When a β+ particle is emitted from a nucleus:

    • The number of protons decreases by 1: proton number decreases by 1

    • The total number of nucleons stays the same: nucleon number remains the same

XZA → YZ−1A + β+10 + νe00

e.g. C610 → B510 + β+10 + νe00

Worked Example

The radioactive nucleus Rn86222 undergoes alpha decay into a daughter nucleus Po.

Grid showing proton number against neutron number. A is at (132 neutrons, 86 protons); B is at (132 neutrons, 84 protons); C is at (134 neutrons, 84 protons); and D is at (136 neutrons, 84 protons).

(a) Which letter in the diagram represents the daughter product? [1]

(b) What is the nucleon number and proton number of Po? [2]

Answer:

Part (a) 

  • The number of neutrons in Rn86222 is 222 − 86 = 136

  • In alpha decay, the parent nucleus loses a helium nucleus (2 protons, 2 neutrons)

    • Proton number: 86 decreases to 84

    • Neutron number: 136 decreases to 134

Grid showing proton number against neutron number. A is at (132 neutrons, 86 protons); B is at (132 neutrons, 84 protons); C is at (134 neutrons, 84 protons); and D is at (136 neutrons, 84 protons). Alpha decay occurs from Rn at (136 neutrons, 86 protons) to Po at (134 neutrons, 84 protons); the daughter is point C.
  • Therefore, the correct answer is C [1 mark]

Part (b)

  • The equation for alpha decay is as follows:

XZA → YZ−2A−4 + α24

Rn86222 → Po84218 + α24

  • Hence the daughter nucleus Po has:

    • Nucleon number = 222 − 4 = 218 [1 mark]

    • Proton number = 86 − 2 = 84 [1 mark]

Worked Example

A radioactive substance with a nucleon number of 212 and a proton number of 82 decays by β-plus emission into a daughter product which further decays by β-plus emission into a granddaughter product.

Grid showing proton number against neutron number. A is at (132 neutrons, 80 protons); B is at (130 neutrons, 80 protons); C is at (130 neutrons, 84 protons); and D is at (128 neutrons, 84 protons).

Which letter in the diagram represents the granddaughter product?

[1]

Answer:

  • The number of neutrons in the parent nucleus is 212 − 82 = 130

  • In beta-plus decay, a proton turns into a neutron

    • Proton number: 82 decreases to 80

    • Neutron number: 130 increases to 132

Grid showing proton number against neutron number. A is at (132 neutrons, 80 protons); B is at (130 neutrons, 80 protons); C is at (130 neutrons, 84 protons); and D is at (128 neutrons, 84 protons).  Two β-plus decays occur from (130 neutrons, 82 protons) to (131 neutrons, 81 protons), then to point A at (132 neutrons, 80 protons).
  • Therefore, the correct answer is A [1 mark]

Examiner Tips and Tricks

Remember to avoid the common mistake of confusing the number of neutrons with the nucleon number. In alpha decay, the nucleon (protons and neutrons) number decreases by 4 but the number of neutrons only decreases by 2.

Neutrino emission

  • An electron neutrino is a type of subatomic particle with no charge and negligible mass which is also emitted from the nucleus

  • The anti-neutrino is the antiparticle of a neutrino

    • Electron anti-neutrinos are produced during β– decay

    • Electron neutrinos are produced during β+ decay

The electron neutrino is represented with a blue circle labelled as ν sub e, and the anti-electron neutrino is represented with a blue circle labelled as barred ν sub e.
Beta-minus decay releases an anti-neutrino, while beta-plus decay releases a neutrino
  • Although the neutrino has no charge and negligible mass, its existence was hypothesised to account for the conservation of energy in beta decay

  • When the number of α particles is plotted against kinetic energy, there are clear spikes that appear on the graph

  • This demonstrates that α-particles have discrete energies (only certain values)

Two graphs plot number of α or β particles against kinetic energy in eV: α particles show discrete spikes and constant energy values, whereas β particles show a continuous curve and a range of energy values.
Alpha particles have discrete energy levels whilst beta particles have a continuous range of energies
  • When the number of β particles is plotted against kinetic energy, the graph shows a curve

  • This demonstrates that beta particles (electrons or positrons) have a continuous range of energies

  • This is because the energy released in beta decay is shared between the beta particles (electrons or positrons) and neutrinos (or anti-neutrinos)

  • This was one of the first clues of the neutrino’s existence

  • The principle of conservation of momentum and energy applies in both alpha and beta emission

Examiner Tips and Tricks

One way to remember which particle decays into which depends on the type of beta emission, think of beta ‘plus’ as the ‘proton’ that turns into the neutron (plus an electron neutrino)

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Katie M

Author: Katie M

Expertise: Curriculum Expert

Katie has always been passionate about the sciences, and completed a degree in Astrophysics at Sheffield University. She decided that she wanted to inspire other young people, so moved to Bristol to complete a PGCE in Secondary Science. She particularly loves creating fun and absorbing materials to help students achieve their exam potential.

Tim

Reviewer: Tim

Expertise: Content Creator

Timothy graduated with a first class degree in Mathematics and Physics from the University of Warwick. After working as a postgraduate researcher, Timothy has worked as a content creator for various online revision platforms, creating physics resources for a range of levels and exam boards.