Fizeau's Speed of Light Experiment (AQA A Level Physics)
Revision Note
Fizeau's Determination of the Speed of Light
Scientists used to believe that light covered distance instantaneously and travelled at infinite speed
Some astronomical observations seemed to contradict this, however
Following this, Hippolyte Fizeau measured a finite speed for light
How did Fizeau measure the speed of light?
Fizeau shone a beam of light at a mirror several kilometres away
In the path of the light, he placed a "toothed wheel" which was spinning at a very high speed
The toothed wheel was positioned so the teeth of the wheel and the gaps between them periodically passed over the beam of light
This created regular pulses of light travelling towards the distant mirror
The path of the light passing through a gap in the toothed wheel
Light from the source was continuous, but the toothed wheel caused the mirror to receive periodic bursts of light. The light here passes through a particular gap, labelled G, while the toothed wheel rotates.
In the example shown in the diagram, the light passes through a particular gap, labelled G
The light had to travel a distance d from the source to the mirror and then back to the observer
The total path length of the light was 2d and the speed of light was labelled c
The total time for the light to pass through the toothed wheel and return was:
The speed at which the wheel rotated could be changed - at a certain wheel speed, the light on its returning path would hit the tooth next to G
This meant the observer would see no light returning from the mirror
Diagram showing the returning light blocked by a tooth
In the previous diagram, the initial beam of light passed through gap G. The wheel then kept rotating. By the time the light has travelled to the mirror and returned, gap G has now been replaced with the tooth next to it and the light is blocked.
The wheel's rotational speed is increased slightly
Now, by the time the light that passed through G has returned, G has been replaced with the next gap
The returning light passes through this gap and the observer sees reflected light through the toothed wheel
Diagram showing the returning light passing through the next gap
At this rotational speed, the same thing happens for light passing through every gap. The time of the light's path is equal to the time taken for one gap to be replaced by the next gap.
The toothed wheel has n gaps and n teeth which both have the same width
This means that, if a full revolution has a period of T, then the time taken for a gap to be replaced by a tooth is:
Recall that time period is the reciprocal of frequency f (of teeth passing a point per second) so we can write this as:
When the observer sees the reflected light disappear, the time taken for light to travel to the mirror is the time taken for a gap to be replaced by a tooth, so:
Rearranging this allowed Fizeau to calculate the speed of light as:
Other Experiments done by Fizeau
Fizeau also measured the speed of light in water by a similar method and found it to be slower than the speed of light in air
This was another piece of evidence contradicting Newton's corpuscular theory - recall that this predicted light would travel faster in a denser medium
Examiner Tips and Tricks
As with many other concepts in Turning Points, this builds on a lot of other ideas. Revising circular motion will help a lot with calculations on this topic.
Worked Example
Fizeau repeated his experiment, but this time he increased the speed of the toothed wheel until the light appeared again at maximum brightness. Rewrite his equation to calculate the speed of light for this new wheel frequency, .
Answer:
Step 1: Determine which part of the equation needs changing:
We no longer need to calculate the time taken for a gap to be replaced by a tooth, but the time taken for a gap to be replaced by another gap
As the teeth and gaps are of equal width, this should take twice as long as it would for a gap to be replaced by a tooth, so:
Step 2: Re-Derive Fizeau's equation for c:
Equating this to the time taken for light to return gives:
A quick logic check confirms this
For a gap to now replace the initial gap, the teeth must cover twice the distance of before in the same time
Therefore the new frequency must be twice the old frequency, so
Substituting this into the above expression gives our original equation
Examiner Tips and Tricks
A great skill in an exam is finding alternative methods to verify your answers - if you finish with a bit of spare time, go back to yor calculation questions. Try answering them with a different method and see if you get the same answer.
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