p–V Diagrams
- When a gas expands, it does work on its surroundings by exerting pressure on the walls of the container it's in
- For a gas inside a piston, the force exerted by the gas pushes the piston outwards
- As a result, work is done by the gas when the piston expands the volume of the gas
- Alternatively, if an external force is applied to the piston, the gas will be compressed
- In this case, work is done on the gas when the piston compresses the gas
Gas pushed in a piston
The expansion of the gas does work on the piston by exerting a force over a distance, s
- The work done when the volume of a gas changes at constant pressure is:
- Where:
- W = work done (J)
- p = pressure of the gas (Pa)
- ΔV = change in the volume of the gas (m3)
- This equation assumes that the surrounding pressure does not change as the gas expands
- This is true if the gas is expanding against the pressure of the atmosphere, which changes very slowly
p-V diagrams
- Pressure-volume (p-V) diagrams are often used to represent changes in the state of a gas in thermodynamic processes
Gas expanding and compressing in a cylinder by a piston
Positive or negative work done depends on whether the gas is compressed or expanded
- The area under a p–V diagram tells us how much work is done
- When a gas expands (at constant pressure) work done is positive
- Volume increases +ΔV
- Work is done by the gas +W
- When a gas is compressed (at constant pressure) work done W is negative
- Volume decreases −ΔV
- Work is done on the gas −W
- When both the volume and pressure of gas changes
The work done can be determined from the area under a p-V diagram
- In the context of engines, these are referred to as indicator diagrams
Worked example
When a balloon is inflated, its rubber walls push against the air around it.
Calculate the work done when the balloon is blown up from 0.015 m3 to 0.030 m3.
Atmospheric pressure = 1.0 × 105 Pa.
Answer:
- The work done by a gas is equal to
- Where the change in volume is
ΔV = final volume − initial volume = 0.030 − 0.015 = 0.015 m3
- Therefore, work done is
W = (1.0 × 105) × 0.015 = 1500 J
Worked example
An ideal gas is compressed, as shown on the graph below.
Answer:
(a)
- The volume decreases, therefore, work is done on the gas
(b)
- The work done is equal to the area under the p-V diagram
Work done on the gas, W = 240 J
Examiner Tip
Interpreting p-V diagrams is a very important part of Thermodynamics. Questions linked to the ideal gas equation, or might also be involved.