Torque

The change in rotational motion due to a turning force is called torque
The torque of a force F about an axis is given by

$τ = F r$

Where:
- $τ$ = torque (N m)
- F = applied force (N)
- r = perpendicular distance between the axis of rotation and the line of action of the force (m)

Torque of a perpendicular force

11-1-3-torque

The torque applied by a cyclist on a bicycle pedal can be determined using the magnitude of the applied force, from the cyclist, and the distance between the line of action of the force and the axis of rotation, the length of the crank arm r

Torque of a Couple

When applied to a couple (2 forces), torque can be described as

The sum of the moments produced by each of the forces in the couple

Torque of a couple on a steering wheel

Torque of a Couple Steering Wheel Example, for IB HL Physics Revision Notes

The steering wheel is in rotational equilibrium since the resultant force and resultant torque are zero. This means it does not have linear or angular acceleration.

For example, the torque provided by a couple on a steering wheel of radius r is

$τ = (F \times r) + (F \times r) = 2 F r$

Therefore, the torque of a couple is equal to double the magnitude of the torque of the individual forces
The forces are equal and act in opposite directions
- Therefore, couples produce a resultant force of zero

Due to Newton’s Second law (F = ma), the steering wheel does not accelerate
- In other words, when the force is applied, the steering wheel rotates with a constant angular speed but remains in the same location

Worked example

A grinding wheel is used to sharpen the edges of pieces of wood in a school workshop. A piece of wood is forced against the edge of the wheel so that the tangential force on the wheel is a steady 12.0 N as the wheel rotates. The diameter of the wheel is 0.13 m.

Calculate the torque on the grinding wheel, giving an appropriate unit

Answer:

Step 1: State the equation for torque

$τ = F r$

Step 2: Calculate the perpendicular distance from the axis of rotation

This is the radius of the wheel since the rotation is from the centre of the wheel

$r = \frac{0.13}{2} = 0.065 m$

Step 3: Substitute the values

$τ = 12.0 \times 0.065 = 0.78$

Step 4: State the appropriate unit

$τ = 0.78 N m$

Examiner Tip

The terminology in this section can get confusing. For example, a moment is not a 'turning force' - the turning force is only part of the moment, the moment is the effect that the turning force has on the system when applied at a distance from a turning point, or pivot.

This is often linked with content from the moments section of the course.

Ultimately, when you carry out calculations, make sure you can identify

The magnitude of the applied force
The perpendicular distance between the force and the turning point (along the line of action)

When considering an object in rotational equilibrium, choosing certain points can simplify calculations of resultant torque. Remember you can choose any point, not just the axis of rotation.

To simplify your calculation, choose a point where the torque of (most of) the forces are unknown, or when you need to determine where the resultant torque is zero. To do this, choose a point through which the lines of action of the forces pass.

Torque (AQA A Level Physics)

Revision Note

Torque

Torque of a perpendicular force

Torque of a Couple

Torque of a couple on a steering wheel

Worked example

Examiner Tip

You've read 0 of your 10 free revision notes

Unlock more, it's free!

Join the 100,000+ Students that ❤️ Save My Exams

Author: Ashika