Attenuation of X-rays in Matter
- When a collimated beam of X-rays passes through a patient’s body, the X-ray photons are absorbed and scattered
- Different materials absorb X-rays by different amounts
- For example, bones absorb a large proportion of X-ray photons which is why they appear bright white on an X-ray image
- As the X-rays pass through a material, the intensity of the beam is found to decay exponentially
- This decrease in intensity is known as attenuation
- The attenuation of X-rays can be calculated using the equation:
- Where:
- = the intensity of the incident beam (W m-2)
- = the intensity of the transmitted beam (W m-2)
- = the linear absorption coefficient (m-1)
- = distance travelled through the material (m)
- The linear attenuation coefficient is defined as
The fraction of X-rays removed per unit thickness of the material for a specified energy of the X-rays
- The value of μ depends on the density of a substance and the energy of the X-ray photons
- The greater the density of a material, the greater the value of μ
- For example, bone absorbs a greater proportion of X-rays than soft tissue due to its higher density
Absorption of X-rays by flesh and bone
Bone is denser than soft tissues, such as flesh, so X-rays are absorbed more over a shorter distance
Half-value thickness
- Similar to half-life in radioactivity, a material's ability to absorb X-rays is known as its half-value thickness
- The half-value thickness of a material can be defined as:
The thickness of the material which will reduce the intensity of X-rays to half its original level for a specified energy of the X-rays
- If the half-value thickness is , then intensity has a value of , so substituting this into the attenuation equation gives:
- Taking natural logarithms of both sides gives
- Hence, the half-value thickness of a substance is given by:
Worked example
A student investigates the absorption of X-ray radiation in a model arm. A cross-section of the model arm is shown in the diagram.
Parallel X-ray beams are directed along line MM and line BB. The linear absorption coefficients of the muscle and the bone are 0.20 cm−1 and 12 cm−1 respectively.
Calculate the ratio:
for a parallel X-ray beam directed along
(a) line MM
(b) line BB
and state whether the X-ray images have good contrast.
Answer:
(a)
Step 1: Write out the known quantities
- Linear absorption coefficient for muscle, = 0.20 cm-1
- Distance travelled through the muscle, = 8.0 cm
Step 2: Write out the equation for attenuation and rearrange
- Where = the intensity of the incident X-ray beam from the model
- And = the intensity of the incident X-ray beam on the model
Step 3: Substitute in values and calculate the ratio
(b)
Step 1: Write out the known quantities
- Linear absorption coefficient for muscle, = 0.20 cm-1
- Linear absorption coefficient for bone, = 12 cm-1
- Distance travelled through the muscle, = 4.0 cm
- Distance travelled through the bone, = 4.0 cm
Step 2: Write out the equation for attenuation for two media and rearrange
Step 3: Substitute in values and calculate the ratio
Step 4: Write a concluding statement
- Each ratio gives a measure of the amount of transmission of the beam from the model
- A good contrast is when:
- There is a large difference between the intensities
- The ratio is much less than 1.0
- Therefore, both images have a good contrast