Normal Distribution (A Level only) (OCR A Level Maths: Statistics)

Exam Questions

4 hours34 questions
1a
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1 mark

A continuous random variable can take any value within a given range.  Many naturally occurring continuous quantities can be modelled using the Normal Distribution, for example the height of human beings; the mass of new born puppies or the distribution of all A Level maths exam results.

Give a different example of a quantity that could be modelled using the normal distribution.

1b
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3 marks

The graph of the normal distribution has a characteristic bell shape that is symmetrical about the mean, mu.  If X has a normal distribution with a mean,mu , and variance,sigma squared,  then it can be written as X tilde space N left parenthesis mu comma sigma squared right parenthesis.

 For X tilde N left parenthesis mu comma sigma squared right parenthesis, state:

(i)
straight P left parenthesis X space less than space mu right parenthesis

(ii)
straight P left parenthesis X space greater or equal than space mu right parenthesis

(iii)
straight P left parenthesis X space equals space mu right parenthesis
1c
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1 mark

Using your answers to part (b), or otherwise, explain why there is no difference between greater or equal than and greater than or less or equal than and less than when calculating normal probabilities.

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2a
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1 mark

The graph of the normal distribution has a maximum point at the mean and points of inflection at  mu plus-or-minus sigma,  where sigma is the standard deviation. 

The following diagram shows the distribution of the standard normal variable, Z space tilde space N left parenthesis 0 comma 1 right parenthesis space space spacewith mean mu space equals space 0 comma space spaceand variance sigma squared equals 1..q2-easy-4-3-normal-distributions-edexcel-a-level-maths-statistics

Write down the standard deviation of the standard normal variable,Z .

2b
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3 marks

Write down the values that correspond to:

(i)
the maximum point on the curve.

(ii)
the points of inflection on the curve.
2c
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3 marks

For a normal distribution, probabilities can be calculated by finding the area under the graph.  Approximately 68% of the data lies within one standard deviation of the mean, 95% within two and 99.7% of the data lies within three standard deviations of the mean

Using the given properties, find the values of a, b, and c in the following statements:

(i)
straight P left parenthesis negative 1 space less or equal than space Z space less or equal than space 1 right parenthesis space equals space a

(ii)
straight P left parenthesis negative b space less or equal than space Z space less or equal than space b right parenthesis space equals space 0.997

(iii)
straight P left parenthesis negative c space less or equal than space Z space less or equal than 0 right parenthesis space equals space 0.475

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3a
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3 marks

For the random variable X tilde space N left parenthesis 20 comma space 4 squared right parenthesis find, using the properties of the normal distribution:

(i)
straight P left parenthesis 16 space less or equal than X less or equal than space 24 right parenthesis

(ii)
straight P left parenthesis 20 space less or equal than X space less or equal than space 24 right parenthesis

(iii)
straight P left parenthesis X space less or equal than space 24 right parenthesis
3b
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4 marks

By first writing the standard deviation of the random variable Y tilde N left parenthesis 10 comma 4 right parenthesis comma find:

(i)
straight P left parenthesis 0 space less or equal than Y less or equal than space 20 right parenthesis

(ii)
straight P left parenthesis 0 space less or equal than Y less or equal than space 16 right parenthesis

(iii)
straight P left parenthesis 8 space less or equal than Y less or equal than space 14 right parenthesis

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4a
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3 marks

One method to find probabilities for the normal distribution is to use the normal cumulative distribution function on your calculator. 

 For the random variable, X tilde N left parenthesis 32 comma 9 right parenthesis,

(i)
Write down the mean and standard deviation.

(ii)
Draw a sketch of the graph, labelling the mean and the points of inflection clearly.  
4b
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2 marks

With the help of your diagram, explain how you should know, without carrying out any calculations, that  straight P left parenthesis X less or equal than space 34 right parenthesis space greater than space 0.5.

Define a suitable lower bound you could use on your calculator to calculate straight P left parenthesis X less or equal than space 34 right parenthesis..

4c
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3 marks

Use the normal cumulative distribution function on your calculator to find the following probabilities, giving all answers to four decimal places.

(i)
straight P left parenthesis X less or equal than space 34 right parenthesis

(ii)
straight P left parenthesis X greater than 30 right parenthesis

(iii)
straight P left parenthesis 31 space less or equal than X space less or equal than space 35 right parenthesis

 

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5a
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3 marks

The heights H cm, of young fig trees on a farm in Australia are normally distributed with mean, 90 cm, and standard deviation, 7 cm.  They are modelled as  H tilde space N left parenthesis 90 comma space 7 squared right parenthesis..

Find, giving all answers to four decimal places.:

(i)
straight P left parenthesis H space less or equal than space 91 right parenthesis

(ii)
straight P left parenthesis H space greater than space 91 right parenthesis

(iii)
straight P left parenthesis H space greater or equal than space 89 right parenthesis
5b
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2 marks

Explain why it was only necessary to use the normal distribution function on your calculator for part (i) in question (a).

5c
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2 marks

The fig trees need to be moved to a more spacious area once they reach a height of one metre. The heights of the fig trees are measured at the start of each day.

(i)
Find the probability a fig tree chosen at random is more than one metre tall.

(ii)
If, on a particular day, the farmer has 100 fig trees, how many would they expect to have to move that day?

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6a
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1 mark

The slithering speeds, S kmph, of a population of garden snails are modelled as a normal distribution with  S italic tilde N left parenthesis 0.04 comma space straight sigma squared right parenthesis.

Use the properties of the normal distribution to find , given that 68% of snails chosen at random from the population slither with speeds in the range 0.03 kmph and 0.05 kmph.

6b
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2 marks

Given that 60% of snails slither with a speed of no more than s kmph, draw a diagram to show that  s greater than 0.04 kmph.

Use the inverse normal distribution function on your calculator to find the value of  s, giving your answer in kmph to four decimal places.

6c
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2 marks
(i)
With the help of a diagram, show that if  straight P left parenthesis S space less or equal than space a right parenthesis space equals space 0.7, and  straight P left parenthesis S space greater or equal than space b right parenthesis space equals space 0.3 comma space spacethen space a space equals space b.

(ii)
Hence, or otherwise, find the value of b, such that 30% of the garden snails slither with a speed of greater than b kmph.

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7a
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3 marks

For the standard normal distribution, Z space tilde space N left parenthesis 0 comma 1 ² right parenthesis ,the probability straight P left parenthesis Z space less than space z right parenthesis spacecan be written as  text Φ end text left parenthesis z right parenthesis space

Using the normal cumulative distribution function on your calculator with the parameters for the standard normal distribution, write the following in the form straight P left parenthesis Z space less than space z right parenthesis space, and find each solution to four decimal places.

(i)
straight capital phi left parenthesis 1.2 right parenthesis

(ii)
text Φ end text left parenthesis negative 0.6 right parenthesis

(iii)
1 space minus space straight capital phi left parenthesis 0.8 right parenthesis
7b
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3 marks

A random variable X tilde N left parenthesis mu comma sigma squared right parenthesis can be coded to model the standard normal variable Z space tilde space N left parenthesis 0 comma 1 right parenthesis comma spaceusing the formula:

Z equals fraction numerator X minus mu over denominator sigma end fraction

For the random variable X tilde N left parenthesis 54 comma 5 squared right parenthesis comma write in terms of  straight capital phi left parenthesis z right parenthesis space and hence find:

(i)
straight P left parenthesis X space less or equal than space 60 right parenthesis

(ii)
straight P left parenthesis X space less than space 51 right parenthesis

(iii)
straight P left parenthesis X space greater or equal than space 58 right parenthesis

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8a
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2 marks

The percentage points of the normal distribution table below provides z-values that correspond to given probabilities.  It gives values of p such that straight P left parenthesis Z greater than z right parenthesis space equals space p.

p z p z
0.5000 0.0000 0.0500 1.6449
0.4000 0.2533 0.0250 1.9600
0.3000 0.5244 0.0100 2.3263
0.2000 0.8416 0.0050 2.5758
0.1500 1.0365 0.0010 3.0902
0.1000 1.2816 0.0005 3.2905


From the table, straight P left parenthesis Z space greater than space 0.2533 right parenthesis space equals space 0.4. On a sketch of the normal distribution curve, show that straight P left parenthesis Z space less than space minus space 0.2533 right parenthesis space equals space 0.4 space spaceand straight P left parenthesis Z space greater than negative space 0.2533 right parenthesis space equals space 0.6.

8b
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1 mark

Use the percentage points table for the standard normal distribution to find the value of z for which straight P left parenthesis Z greater than z right parenthesis equals 0.05.

8c
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3 marks

The weights, W kg, of watermelons arriving for packing at Walter’s Wacky Watermelon Warehouse are modelled as W tilde N left parenthesis 10 comma 2.5 ² right parenthesis. Walter keeps the heaviest 5% of watermelons to enter into a weekly competition and sends the rest to the farmers market to be sold. 

(i)
By substituting the values of the mean and standard deviation into the formula connecting W and  Z, show that W space equals space 2.5 Z space plus space 10.

 

(ii)
Use your answer to part (b) to find  w such that straight P left parenthesis W space greater than space w right parenthesis space equals space 0.05 comma and thus find the lightest weight of a watermelon that Walter would enter into the competition.

 

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9a
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3 marks

A soft serve ice cream machine is set to produce serving portion sizes, X comma that are normally distributed with a mean of 100 ml and a standard deviation of sigma ml.  It is given that 10% of the servings produced by the machine are less than 98 ml.

(i)
Find, to four decimal places, the value of  z such that straight P left parenthesis Z space less than space z right parenthesis space = 0.1.

(ii)
By substituting your answer to part (i) into the formula connecting X and  Z,show that sigma space equals space 1.56 space m l comma,to two decimals places.
9b
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3 marks

The containers for the soft serve ice cream are designed to hold a volume, V ml with distribution V space tilde space N left parenthesis mu comma 15 ² right parenthesis.

Given that 20% of the containers can hold a volume of more than 150 ml, find the value of mu to one decimal place.

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1a
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3 marks

The following diagram shows the distribution of heights, in cm, of adult women in the UK:q1-medium-4-3-normal-distributions-edexcel-a-level-maths-statistics

The distribution of heights follows a normal distribution, with a mean of 162 cm and a standard deviation of 6.3 cm.

 Write down the values of the height that correspond to:

(i)
the maximum point on the curve 
 
(ii)
the points of inflection on the curve

 

1b
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3 marks

Use the properties of the normal distribution to suggest a range of heights within which the heights of

(i)
68%

(ii)
95%

(iii)
nearly all

of adult women in the UK will fall.

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2a
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3 marks

For the random variable X tilde N left parenthesis 23 comma 4 squared right parenthesis find the following probabilities:

(i)
straight P left parenthesis X less than 20 right parenthesis

(ii)
straight P left parenthesis X greater or equal than 29 right parenthesis

(iii)
straight P left parenthesis 20 less or equal than X less than 29 right parenthesis

 

2b
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3 marks

For the random variable Y tilde N left parenthesis 100 comma 225 right parenthesis find the following probabilities:

(i)
straight P left parenthesis Y less or equal than 90 right parenthesis

(ii)
straight P left parenthesis Y greater than 140 right parenthesis

(iii)
straight P left parenthesis 85 less or equal than Y less or equal than 115 right parenthesis

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3a
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2 marks

The weight, Wg, of a chocolate bar produced by a certain manufacturer is modelled as W tilde N left parenthesis 200 comma space 1.75 squared right parenthesis.

Find:

(i)
straight P left parenthesis W less than 195 right parenthesis

(ii)
straight P left parenthesis W greater than 203 right parenthesis
3b
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2 marks

Heledd buys a pack containing 12 of the chocolate bars.  It may be assumed that the 12 bars in the pack represent a random sample.

Find the probability that all of the bars in the pack have a weight of at least 195 g.

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4a
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4 marks

The random variable X tilde N left parenthesis 330 comma space 10 squared right parenthesis

 Find the value of a, to 2 decimal places, such that:

(i)
straight P left parenthesis X less than a right parenthesis equals 0.25

(ii)
straight P left parenthesis X greater than a right parenthesis equals 0.25

(iii)
straight P left parenthesis 315 less or equal than X less or equal than a right parenthesis equals 0.5
4b
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2 marks

The random variable Y tilde N left parenthesis 10 comma 10 right parenthesis.

Find the value of b and the value of  c, each to 2 decimal places, such that:

(i)
straight P left parenthesis Y less than b right parenthesis equals 0.4

(ii)
straight P left parenthesis Y greater than c right parenthesis equals 0.25
4c
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2 marks

Use a sketch of the distribution of Y to explain why straight P left parenthesis b less or equal than Y less or equal than c right parenthesis equals 0.35.

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5a
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3 marks

The test scores, X, of a group of RAF recruits in an aptitude test are modelled as a normal distribution with X tilde N left parenthesis 210 comma space 27.8 squared right parenthesis.

(i)
Find the values of a and b such that  straight P left parenthesis X less than a right parenthesis equals 0.25 space spaceand  straight P left parenthesis X greater than b right parenthesis equals 0.25.

(ii)
Hence find the interquartile range of the scores.
5b
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2 marks

Those who score in the top 30% on the test move on to the next stage of training.

One of the recruits, Amelia, achieves a score of 231. Determine whether Amelia will move on to the next stage of training.

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6a
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4 marks

For the standard normal distribution Z tilde N left parenthesis 0 comma 1 squared right parenthesis, find:

(i)
straight P left parenthesis Z less than 1.5 right parenthesis

(ii)
straight P left parenthesis Z greater than negative 0.8 right parenthesis

(iii)
straight P left parenthesis negative 2.1 less than Z less than negative 0.3 right parenthesis
6b
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3 marks

The random variable X tilde N left parenthesis 2 comma space 0.1 squared right parenthesis.

By using the coding relationship between X and Z, re-express the probabilities from parts (a) (i), (ii) and (iii) in the forms straight P left parenthesis X less than a right parenthesisspace straight P left parenthesis X greater than b right parenthesis and straight P left parenthesis c less than X less than d right parenthesis space spacerespectively, where a, b, c and d are constants to be found.

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7a
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3 marks

The table below shows the percentage points of the normal distribution.  The values z in the table are those which a random variable Z tilde N left parenthesis 0 comma 1 right parenthesis exceeds with probability p.

p z p z
0.5000 0.0000 0.0500 1.6449
0.4000 0.2533 0.0250 1.9600
0.3000 0.5244 0.0100 2.3263
0.2000 0.8416 0.0050 2.5758
0.1500 1.0365 0.0010 3.0902
0.1000 1.2816 0.0005 3.2905

(i)

Use the percentage points table for the standard normal distribution to find the value of z for which  straight P left parenthesis Z greater than z right parenthesis equals 0.2.

(ii)
Use your answer to part (a)(i) along with the properties of the normal distribution to work out the values of a and b for which  straight P left parenthesis Z less than a right parenthesis equals 0.2  and  straight P left parenthesis Z less than b right parenthesis equals 0.8.

7b
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2 marks

The weights, W kg, of coconuts grown on the Coconutty As They Come coconut plantation are modelled as a normal distribution with mean 1.25 kg and standard deviation 0.38 kg.  The plantation only considers coconuts to be exportable if their weight falls into the 20% to 80% interpercentile range.

Use your answer to part (a)(ii) to find the range of possible weights, to the nearest 0.01 kg, for an exportable coconut.

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8a
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2 marks

A machine is used to fill cans of a particular brand of soft drink.  The volume, V ml, of soft drink in the cans is normally distributed with mean 330 ml and standard deviation sigma ml.  Given that 15% of the cans contain more than 333.4 ml of soft drink, find:

the value of sigma

8b
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1 mark

straight P left parenthesis 320 less or equal than V less or equal than 340 right parenthesis.

8c
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3 marks

Six cans of the soft drink are chosen at random.

Find the probability that all of the cans contain less than 329 ml of soft drink.

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9a
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2 marks

The random variable X tilde N left parenthesis mu comma sigma squared right parenthesis. It is known that straight P left parenthesis X greater than 36.88 right parenthesis equals 0.025 and straight P left parenthesis X less than 27.16 right parenthesis equals 0.1

Find the values of a and b for which space straight P left parenthesis Z greater than a right parenthesis equals 0.025 and straight P left parenthesis Z less than b right parenthesis equals 0.1 comma space spacewhere Z is the standard normal variable.  Give your answers correct to 4 decimal places.

9b
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2 marks

Use your answers to part (a), along with the relationship between Z and X, to show that the following simultaneous equations must be true:

mu plus 1.96 sigma equals 36.88

mu minus 1.2816 sigma equals 27.16

9c
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2 marks

By solving the simultaneous equations in (b), determine the values of mu and sigma. Give your answers correct to 2 decimal places.

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1a
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3 marks

The following diagram shows the distribution of heights, in cm, of adult men in the UK:q1-hard-4-3-normal-distributions-edexcel-a-level-maths-statistics

The distribution of heights follows a normal distribution, with a mean of 175.3 cm and a standard deviation of 7.6 cm.

Write down the values of the height that correspond to:

(i)
the line of symmetry of the curve.

(ii)
the points of inflection on the curve.
1b
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4 marks

Use the properties of the normal distribution to determine whether each of the following statements is likely to be true. In each case give a reason for your answer.

(i)
95% of adult men in the UK will have a height less than 190.5 cm.

(ii)
68% of adult men in the UK will have a height between 167.7 cm and 182.9 cm.

(iii)
81.5% of adult men in the UK will have a height between 160.1 cm and 182.9 cm.
1c
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2 marks

Paul, a renowned mathematics educationalist, has a height of 196 cm.

Find the percentage of adult men in the UK who have a height that is less than Paul’s.

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2a
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2 marks

The weight, W kg, of the feed in a sack of partridge feed produced by a certain manufacturer is modelled as W tilde N left parenthesis 20 comma 0.01 right parenthesis.

Find:

(i)
straight P left parenthesis W less than 19.75 right parenthesis

(ii)
straight P left parenthesis W greater than 20.15 right parenthesis
2b
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3 marks

Roger buys ten sacks of the manufacturer’s partridge feed to feed to the partridges who have begun showing up at his backyard bird feeding station.

Using one of your answers to part (i), along with the properties of the normal distribution, find the probability that all ten sacks contain feed with a weight that is within 250 g of 20 kg.

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3a
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3 marks

The random variable X tilde N left parenthesis 13 comma 4 squared right parenthesis

Find the value of a, to 3 decimal places, such that:

(i)
straight P left parenthesis X greater than a right parenthesis equals 0.3

(ii)
straight P left parenthesis a less or equal than X less or equal than 14 right parenthesis equals 0.5
3b
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2 marks

The random variable Y tilde N left parenthesis 20 comma 44 right parenthesis..

Find the value of b and the value of c, each to 3 decimal places, such that:

(i)
straight P left parenthesis Y less than b right parenthesis equals 0.13

(ii)
straight P left parenthesis Y greater than c right parenthesis equals 0.27
3c
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3 marks

Use a sketch of the distribution of Y, along with the properties of the normal distribution, to explain why straight P left parenthesis b less than Y less than c right parenthesis equals 0.6..

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4a
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3 marks

The test scores, X, of a group of Royal Navy recruits in an aptitude test are modelled as a normal distribution with  X tilde N left parenthesis 520 comma space 89.9 squared right parenthesis.

Find the interquartile range of the scores.

4b
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2 marks

Those who score in the top 1% on the test are eligible to join the submarine service.

One of the recruits, Mervyn, is a keen would-be submariner. He achieves a score of 750 on the test.  Determine whether Mervyn will be eligible to join the submarine service.

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5a
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3 marks

For the standard normal variable  Z tilde N left parenthesis 0 comma 1 squared right parenthesis comma  the function straight capital phi is defined by

straight capital phi left parenthesis a right parenthesis equals P left parenthesis Z less than a right parenthesis

Find:

(i)
straight capital phi left parenthesis 1.2 right parenthesis

(ii)
straight capital phi left parenthesis 0.3 right parenthesis

(iii)
straight capital phi left parenthesis negative 2.1 right parenthesis
5b
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4 marks

The random variable X tilde N open parentheses 30 comma space 2 squared close parentheses.

Use your answers from part (a), along with the relationship between X and Z, to work out the following probabilities:

(i)
straight P left parenthesis X less than 30.6 right parenthesis

(ii)
straight P left parenthesis X greater than 32.4 right parenthesis

(iii)
straight P left parenthesis 25.8 less or equal than X less than 27.6 right parenthesis

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6a
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3 marks

The table below shows the percentage points of the normal distribution. The values z in the table are those which a random variable Z tilde N left parenthesis 0 comma 1 right parenthesis exceeds with probability p.

p z p z
0.5000 0.0000 0.0500 1.6449
0.4000 0.2533 0.0250 1.9600
0.3000 0.5244 0.0100 2.3263
0.2000 0.8416 0.0050 2.5758
0.1500 1.0365 0.0010 3.0902
0.1000 1.2816 0.0005 3.2905


Use the percentage points table for the standard normal distribution, along with the general properties of the normal distribution, to work out the values of a and b for which space straight P left parenthesis Z less than a right parenthesis equals 0.15 and  text P end text left parenthesis Z less than b right parenthesis equals 0.85..

6b
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2 marks

A new agricultural standardisation scheme has been proposed that will measure the bendiness of bananas in terms of a unit called the ‘bent’.  It is found that the bendiness measurements, B, of bananas grown on the Yes We Have Some Bananas banana plantation can be modelled as a normal distribution with mean 55.3 bents and standard deviation 6.1 bents.  Because the owners of the plantation are committed to making sure that the bananas they export are neither too bendy nor not bendy enough, the plantation only considers bananas to be exportable if their bendiness falls into the 15% to 85% interpercentile range of the plantation’s banana bendiness measurements.

Use your answer to part (a) to find the range of possible bendiness measurements, to the nearest hundredth of a bent, for an exportable banana.

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7a
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3 marks

A machine is used to fill bags of potatoes for a supermarket chain.  The weight, W kg, of potatoes in the bags is normally distributed with mean 3 kg and standard deviation sigma kg. 

Given that 7% of the bags contain a weight of potatoes that is at least 50 g more than  the mean, find:

straight P left parenthesis 2.9 less or equal than W less or equal than 3.1 right parenthesis.

7b
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4 marks

Twelve of the bags of potatoes are chosen at random.

Find the probability that not more than one of the bags will contain less than 2.96 kg of potatoes.

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8a
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4 marks

The random variable X tilde N left parenthesis mu comma sigma squared right parenthesis. It is known that straight P left parenthesis X greater than 34.451 right parenthesis equals 0.001 and straight P left parenthesis X less than 14.792 right parenthesis equals 0.2

Use the relationship between X and the standard normal variable Z to show that the following simultaneous equations must be true:

mu plus 3.0902 sigma equals 34.451

mu minus 0.8416 sigma equals 14.792

8b
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2 marks

By solving the simultaneous equations in (a), determine the values of mu and sigma.

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1a
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3 marks

The following histogram shows the distribution of weights, in grams, of a population of dormice in the UK:q1-very-hard-4-3-normal-distributions-edexcel-a-level-maths-statistics

(i)
Explain why it would be appropriate to use a normal distribution to model the distribution of weights of the dormouse population.

(ii)
Explain how the histogram could be altered so as to better approximate the smooth curve of the normal distribution.
1b
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3 marks

The mean and standard deviation for the weights of the dormouse population are calculated to be 20.5 g and 2.6 g respectively.  A normal curve is drawn corresponding to these values.

Write down the values of the weight that correspond to the line of symmetry and the points of inflection of the normal curve.

1c
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4 marks

Use the properties of the normal distribution to determine whether each of the following statements is likely to be true. In each case give a reason for your answer.

(i)
84% of the dormice have a weight that is less than 23.1 g.

(ii)
More than 99% of the dormice have a weight that is between 15.3 g and  28.3 g.

(iii)
18.5% of the dormice have a weight that is either less than 17.9 g or greater than 25.7 g.

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2
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5 marks

The weight, W kg, of the feed in a sack of pheasant feed produced by a certain manufacturer is modelled as  W tilde N open parentheses table row cell 20 comma end cell cell 1 over 3600 end cell end table close parentheses .

Roger buys twelve sacks of the manufacturer’s pheasant feed to feed to the pheasants who have begun showing up at his backyard bird feeding station.

Find the probability that all twelve sacks contain feed with a weight that is within 35 g of 20 kg.

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3a
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3 marks

The random variable X tilde N left parenthesis 2.35 comma space 0.3 squared right parenthesis. 

Find the value of a, to 3 decimal places, such that:

(i)
straight P left parenthesis X greater than a right parenthesis equals 0.005

(ii)
straight P left parenthesis a less or equal than X less or equal than 3 right parenthesis equals 0.47
3b
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2 marks

 The random variable Y tilde N left parenthesis 15 comma 101 right parenthesis..

 Find the value of b and the value of c, each to 3 decimal places, such that:

(i)
straight P left parenthesis Y greater than b right parenthesis equals 0.97

(ii)
straight P left parenthesis Y less than c right parenthesis equals 0.23
3c
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3 marks

Use a sketch of the distribution of Y, along with the properties of the normal distribution, to explain why straight P left parenthesis b less or equal than Y less or equal than c right parenthesis equals 0.2..

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4a
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4 marks

The distribution of the test scores, X, of a group of British Army officer cadets on an aviation aptitude test is modelled as a normal distribution with  X tilde N left parenthesis 120 comma space 26.5 squared right parenthesis.

Only cadets who score in the top 10% on the test are eligible to proceed directly to helicopter pilot training.  Cadets whose scores are between the 40th and 90th percentiles, however, are eligible to resit the test in an attempt to improve their scores.

Given that it is only possible to receive an integer number of marks as a score on the test, determine the range of test scores for which cadets would be eligible to resit the test.

4b
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3 marks
(i)
Find straight P left parenthesis X greater than 200 right parenthesis

(ii)

The maximum score it is possible to receive on the test is 200.  Use this fact, and your answer to part (b)(i), to criticise the model being used for the score distribution.

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5a
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3 marks

For the standard normal variable  Z tilde N left parenthesis 0 comma 1 squared right parenthesis comma  the function straight capital phi is defined by

 straight capital phi left parenthesis a right parenthesis equals P left parenthesis Z less than a right parenthesis comma space space space space a element of R

The constants q comma r and s are positive real numbers.

Find an expression for each of the following probabilities, giving your answers as simply as possible in terms of  space straight capital phi left parenthesis q right parenthesis comma straight capital phi left parenthesis r right parenthesis comma space and straight capital phi left parenthesis s right parenthesis.

(i)
straight P left parenthesis Z greater than q right parenthesis

(ii)
straight P left parenthesis negative s less than Z less than r right parenthesis

 

5b
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4 marks

The random variable X tilde N left parenthesis mu comma sigma right parenthesis.

Find an expression for each of the following probabilities. You should give your answers as simply as possible in terms of the function straight capital phi comma where the argument of the function should in each case be given in terms of mu and sigma

(i)
straight P left parenthesis X less than 103 right parenthesis

(ii)
straight P left parenthesis X greater than negative 7 right parenthesis

(iii)
straight P left parenthesis negative 80 less than X less or equal than 2500 right parenthesis

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6
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5 marks

The table below shows the percentage points of the normal distribution.  The values z in the table are those which a random variable Z tilde N left parenthesis 0 comma 1 right parenthesis exceeds with probability p.

p z p z
0.5000 0.0000 0.0500 1.6449
0.4000 0.2533 0.0250 1.9600
0.3000 0.5244 0.0100 2.3263
0.2000 0.8416 0.0050 2.5758
0.1500 1.0365 0.0010 3.0902
0.1000 1.2816 0.0005 3.2905

The Monkey Puzzle Tree Marketing Board has proposed a new scheme that will measure the puzzlingness of monkey puzzle trees in terms of a unit called the ‘fuddle’.  It is found that the puzzlingness measurements, X, of monkey puzzle trees grown on the We Puzzling Monkeys monkey puzzle tree plantation can be modelled as a normal distribution with mean mu fuddles and standard deviation sigma fuddles.  Because the owners of the plantation are committed to making sure that the monkey puzzle trees they sell to gardeners are neither too puzzling nor not puzzling enough, the plantation only considers monkey puzzle trees to be saleable if their puzzlingness falls into the 10% to 97.5% interpercentile range of the plantation’s monkey puzzle tree puzzlingness measurements.

Using the percentage points table for the standard normal distribution, or otherwise, find the range of possible puzzlingness measurements for a saleable monkey puzzle tree.  Your answer should be given in terms of mu and sigma.

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7
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7 marks

A machine is used to produce the 3-metre barge poles sold by the You Would Touch It With One Of Ours barge pole company.  The actual length, L m, of the barge poles is normally distributed with mean 3 m, standard deviation sigma m, and interquartile range 0.01712 m.

Twenty of the barge poles are chosen at random.

Find the probability that at most two of the barge poles will be shorter than 3 m by 1 cm or more.

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8a
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6 marks

An archaeologist has devoted his life to studying ancient Greek vases produced by a particular Boeotian pottery workshop.  The vases were made to a standard pattern, and after measuring a very large number of them the archaeologist has found that 5% of the vases have a mass greater than 2.237 kg, while only 1% of them have a mass less than 1.906 kg.

Given that the masses of the vases may be assumed to be distributed normally, find the mean and standard deviation of the distribution.

8b
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4 marks

The archaeologist has found that vases made by the workshop with a mass less than 1.93 kg are particularly fragile and require special care.

 A museum has just purchased a collection of k vases produced by the workshop.  The k vases may be assumed to be a random sample.

Given that there is a less than 15% chance that the collection contains vases that are particularly fragile and require special care, find the greatest possible value of k. Your answer should be supported by clear algebraic working.

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