Further Differentiation (CIE A Level Maths: Pure 3)

Exam Questions

3 hours35 questions
1
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8 marks
i)
Differentiate  space tan space x space plus ln space x space.
ii)
Use the product rule to differentiate  e to the power of x space cos space x .
iii)
Use the quotient rule to differentiate  fraction numerator sin space x space over denominator x end fraction.
iv)
Use the chain rule to differentiate space e to the power of x 2 minus 3 x plus 17 end exponent.

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2a
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2 marks

A curve has the equation space y equals 5 e to the power of negative 2 x end exponent.

Find an expression for  fraction numerator d y over denominator d x end fraction.

2b
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3 marks
(i)
Find the gradient of the tangent at the point where x equals 1, giving your answer in the form negative a e to the power of negative 2 end exponent where a is a positive integer to be found.

(ii)
Hence show that the gradient of the normal to the curve at the point where space x equals 1 space is fraction numerator space 1 over denominator 10 end fraction e squared.

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3
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4 marks

Find  fraction numerator d y over denominator d x end fractionfor

(i)
y equals sin space open parentheses 3 x squared close parentheses,
(ii)
y equals 2 ln space open parentheses x cubed close parentheses .

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4
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4 marks

The curve with equation  y equals e to the power of x squared minus 9 end exponent  passes through the point with coordinates (-3 , 1).

(i)
Find an expression for  fraction numerator d y over denominator d x end fraction.
(ii)
Find the equation of the tangent to the curve at the point (-3 , 1).

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5a
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3 marks

Differentiate  space left parenthesis x cubed minus 2 x right parenthesis ln space x spacewith respect to x.

5b
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3 marks

Differentiate  e to the power of x cos space 2 x space space with respect to x.

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6a
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3 marks

Differentiate  fraction numerator cos space x over denominator space sin space x end fraction   with respect to x

6b
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3 marks

Differentiate  fraction numerator space 2 x squared minus 3 x plus 4 over denominator sin space 3 x space end fraction with respect to x.

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7
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2 marks

Write down  fraction numerator d y over denominator d x end fraction  when

(i)
y equals sec space 5 x space comma

(ii)

y equals cosec space 3 x space.

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8a
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4 marks

The function space straight f left parenthesis x right parenthesis  is defined as

straight f open parentheses x close parentheses equals open parentheses x squared minus 4 x plus 4 close parentheses ln open parentheses space x close parentheses space comma space space space space space space x greater than 0

Show that the graph of space y equals straight f open parentheses x close parentheses  intercepts the x-axis at the points (1 , 0) and (2 , 0).

8b
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4 marks

Find space straight f apostrophe open parentheses x close parentheses.

8c
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2 marks

Find the gradient of the tangent at the point (1 , 0).

8d
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2 marks

Hence find the equation of the tangent at the point (1 , 0), giving your answer in the form  a x plus b y plus c equals 0, where a, b and c are integers to be found.

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9a
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2 marks

Given that the derivative of  tan to the power of negative 1 end exponent space x  is  fraction numerator 1 over denominator 1 plus x squared end fraction ,  use the chain rule to show that the derivative of  tan to the power of negative 1 end exponent space space open parentheses a x close parentheses spaceis

fraction numerator a over denominator 1 plus a squared x squared end fraction

where a is a real constant.

9b
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3 marks

Hence find the coordinates of the point(s) where the curve  space y equals tan to the power of negative 1 space end exponent open parentheses 2 x close parentheses spacehas a gradient of 1.  The coordinates should in every case be given as exact values.

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1
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8 marks
i)
Differentiate  4 space cos space x space minus 3 space sin space x

ii)
Use the product rule to differentiate  e to the power of x ln space x

iii)
Use the quotient rule to differentiate space fraction numerator tan space x over denominator space x end fraction

iv)
Use the chain rule to differentiate  cos space open parentheses x squared minus 7 x plus 1 close parentheses

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2
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4 marks

A curve has the equation  y equals e to the power of negative 3 x end exponent plus ln space x space comma space space x greater than 0.

Find the gradient of the normal to the curve at the point open parentheses 1 comma space e to the power of negative 3 end exponent close parentheses, giving your answer correct to 3 decimal places.

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3a
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4 marks

Find  fraction numerator d y over denominator d x end fraction  for each of the following:

y equals cos open parentheses space x squared minus 3 x plus 7 close parentheses plus sin space open parentheses e to the power of x close parentheses space

3b
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3 marks

y equals ln space open parentheses 2 x cubed close parentheses space

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4
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4 marks

Find the equation of the tangent to the curve  y equals e to the power of 3 x squared space plus space 5 x space minus space 2 end exponent  at the point open parentheses negative 2 comma space space 1 close parentheses, giving your answer in the formspace a x plus b y plus c equals 0, where a, b and c are integers.

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5a
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3 marks

Differentiate with respect to x, simplifying your answers as far as possible:

open parentheses 4 cos space x space minus 3 sin space x close parentheses space e to the power of 3 x space minus space 5 space end exponent

5b
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3 marks

open parentheses x cubed minus 4 x squared plus 7 close parentheses ln space x

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6
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4 marks

Differentiate  fraction numerator 5 x to the power of 7 over denominator sin space 2 x space space end fraction with respect to x.

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7a
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5 marks

Show that if  y equals cosec 2 x , then 

fraction numerator d y over denominator d x end fraction equals negative 2 cosec space 2 x space cot space 2 x

7b
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1 mark

Hence find the gradient of the tangent to the curve space y equals cos e c space 2 x space at the point with coordinates open parentheses pi over 3 comma fraction numerator 2 square root of 3 over denominator 3 end fraction close parentheses

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8a
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4 marks

The diagram below shows part of the graph of  y equals straight f open parentheses x close parentheses, wherespace straight f open parentheses x close parentheses spaceis the function defined by

straight f open parentheses x close parentheses equals open parentheses x squared minus 1 close parentheses ln open parentheses x plus 3 close parentheses comma space space space space space x greater than negative 3

q8a-7-3-further-differentiation-medium-a-level-maths-pure-screenshots

Points A, B and C are the three places where the graph intercepts the x-axis.

Find straight f apostrophe open parentheses x close parentheses.

8b
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2 marks

Show that the coordinates of point A are (-2, 0).

8c
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3 marks

Find the equation of the tangent to the curve at point A.

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9a
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2 marks

Use the chain rule to differentiate  tan to the power of negative 1 end exponent open parentheses a x close parentheses ,  where a is a real constant.

9b
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2 marks

What does your answer to part (a) tell you about the number of stationary points on the curve space space y equals tan to the power of negative 1 end exponent open parentheses 3 x space close parentheses ?

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1
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8 marks

Use an appropriate method to differentiate each of the following.

i)
sin space 2 x space minus e to the power of 7 x end exponent

ii)
x squared ln space x

iii)
fraction numerator cos space 3 x over denominator space tan space 2 x end fraction

iv)
ln space open parentheses tan space x close parentheses

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2
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6 marks

A curve has the equation  y equals e to the power of negative 3 x end exponent plus ln space x space comma space space x greater than 0.

Show that the equation of the tangent to the curve at the point with x-coordinate 1 is

y equals open parentheses fraction numerator e cubed minus 3 over denominator e cubed end fraction close parentheses x plus fraction numerator 4 minus e cubed over denominator e cubed end fraction

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3
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3 marks

For space y equals ln space open parentheses a x to the power of n space close parentheses , where a greater than 0 is a real number and space n greater or equal than 1 spaceis an integer, show that

fraction numerator d y over denominator d x end fraction equals n over x

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4
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4 marks

Find the gradient of the normal to the curve space y equals 5 cos space left parenthesis e to the power of x minus pi over 2 right parenthesis spaceat the point with x-coordinate 0.  Give your answer correct to 3 decimal places. 

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5a
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3 marks

Differentiate with respect to x, simplifying your answers as far as possible:

open parentheses 2 sin space 3 x space minus cos space 3 x close parentheses space e to the power of 6 minus x space end exponent

5b
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3 marks

open parentheses x squared minus x close parentheses squared ln space 5 x

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6
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3 marks

By writing  y equals fraction numerator space straight f open parentheses x close parentheses over denominator straight g open parentheses x close parentheses end fraction  as space y equals straight f open parentheses x close parentheses open square brackets straight g open parentheses straight x close parentheses close square brackets to the power of negative 1 space end exponent and then using the product and chain rules, show that

fraction numerator d y over denominator d x end fraction equals fraction numerator straight g open parentheses x close parentheses straight f apostrophe open parentheses x close parentheses minus straight f open parentheses x close parentheses straight g apostrophe open parentheses x close parentheses over denominator open parentheses g open parentheses x close parentheses close parentheses squared end fraction

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7a
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2 marks

Given that x equals sec space 7 y ,

Find  fraction numerator d y over denominator d x end fraction  in terms of y

7b
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4 marks

Hence find fraction numerator d y over denominator d x end fraction in terms of x.

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8
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5 marks

The diagram below shows part of the graph of space y equals straight f open parentheses x close parentheses, where space straight f open parentheses x close parentheses spaceis the function defined by

straight f open parentheses x close parentheses equals fraction numerator sin space x over denominator 1 minus e to the power of x end fraction space comma space   x greater than 0

q7-7-3-further-differentiation-medium-a-level-maths-pure-screenshots

Point A is a maximum point on the graph.

Show that the x-coordinate of A is a solution to the equation

fraction numerator cos space x space plus e to the power of x open parentheses sin space x minus cos space x close parentheses over denominator space e to the power of 2 x end exponent minus 2 e to the power of x plus 1 end fraction space equals 0

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9a
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2 marks

Use the chain rule to show that the derivative of y space equals space tan to the power of negative 1 end exponent open parentheses x over a close parentheses, where a space not equal to space 0 is a real constant, is a

dy over dx equals fraction numerator a over denominator a squared plus x squared end fraction

9b
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3 marks

Hence find the coordinates of any stationary point(s) on the curve with equation

y space equals space minus x over 4 plus tan to the power of negative 1 end exponent open parentheses x over 2 close parentheses

giving your answers as exact values.

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1
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8 marks

Use an appropriate method to differentiate each of the following.

i)
tan space 3 x space plus e to the power of 7 minus 2 x squared end exponent
ii)
open parentheses space x squared plus 2 x minus 8 close parentheses space cos open parentheses space 3 minus x space close parentheses
iii)
fraction numerator space ln space 7 x over denominator sin open parentheses space x squared plus 5 space close parentheses end fraction space
iv)
square root of cos space 4 x space end root

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2
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4 marks

A curve has the equation space y equals 3 to the power of x plus 2 to the power of negative x end exponent.

Show that the gradient of the normal to the curve at the point  open parentheses 1 comma space fraction numerator space 7 over denominator 2 end fraction close parentheses space is

fraction numerator 2 over denominator ln space 2 minus 6 ln space 3 space space space end fraction space space

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3
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4 marks

Find the derivative of the function space straight f open parentheses x close parentheses equals sin space open parentheses cos space open parentheses ln space 1 over x close parentheses close parentheses space comma space space x greater than 0.

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4a
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4 marks

Show that the derivative  y equals 4 to the power of negative x to the power of 4 end exponent  is

fraction numerator d y over denominator d x end fraction equals negative open parentheses ln space 4 close parentheses space x cubed 4 to the power of 1 minus x to the power of 4 end exponent

4b
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2 marks

Hence find the equation of the tangent to the curve at the point open parentheses 1 comma 1 fourth close parentheses, giving your answer in the form y equals a x plus b, where a and b are to be given as exact values.

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5a
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3 marks

Differentiate with respect to x, simplifying your answers where possible:

open parentheses 5 plus sin to the power of 2 space end exponent 3 x close parentheses space e to the power of x squared minus 3 x plus 2 end exponent

5b
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3 marks

3 to the power of square root of x end exponent open parentheses square root of x minus fraction numerator 1 over denominator square root of x end fraction close parentheses

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6
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6 marks

The diagram below shows the graph of y equals straight f open parentheses x close parentheses, where straight f open parentheses x close parentheses is the function defined by

space straight f open parentheses x close parentheses equals fraction numerator sin space 3 x over denominator e to the power of 2 x minus 3 end exponent end fraction space comma space   space space space space space space space space space 0 less or equal than x less or equal than fraction numerator 2 pi over denominator 3 end fraction

q8a-7-3-further-differentiation-vh-a-level-maths-pure-screenshots

The points A and B are maximum and minimum points, respectively.

Find the range of straight f open parentheses x close parentheses , giving your answer correct to 3 decimal places.

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7
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5 marks

A sequence of functions is defined by the recurrence relation

u subscript k plus 1 end subscript open parentheses x close parentheses equals fraction numerator straight d over denominator straight d x end fraction u subscript k open parentheses x close parentheses comma space space space u subscript 1 open parentheses x close parentheses equals sin space open parentheses x square root of 2 close parentheses

Based on that sequence, the functionspace straight f subscript n open parentheses x close parentheses spaceis defined by

straight f subscript n open parentheses x close parentheses equals sum from r equals 1 to n of u subscript r open parentheses x close parentheses

Calculate the value of space straight f subscript 41 space open parentheses fraction numerator straight pi square root of 2 over denominator 4 end fraction close parentheses

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8
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6 marks

Use calculus to find the coordinates of the stationary points of the curve

y equals x over 3 minus tan to the power of negative 1 end exponent space open parentheses fraction numerator 2 x over denominator 3 end fraction close parentheses

and determine whether each one is a maximum or a minimum.  The coordinates should be given as exact values.

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