Sampling & Estimation (CIE A Level Maths: Probability & Statistics 2)

Exam Questions

3 hours28 questions
1a
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1 mark

Junaid, a teaching assistant at a university, takes a sample of his students’ essays and records the number of spelling mistakes, x, each essay contains. The results are summarised as follows.

n equals 50 space space space space space space space space space space space space space space space space sum x equals 5173 space space space space space space space space space space space space space space space space space sum x squared equals 560024

Use the formula below to calculate an unbiased estimate for the population mean number of spelling mistakes in a student’s essay.

̅ x equals fraction numerator sum x over denominator n end fraction

1b
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2 marks

Use the formula below to calculate an unbiased estimate for the population variance of the number of spelling mistakes in a student’s essay.

s to the power of 2 space end exponent equals fraction numerator 1 over denominator n minus 1 end fraction space left parenthesis sum x squared minus fraction numerator left parenthesis sum x right parenthesis squared over denominator n end fraction right parenthesis

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2a
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1 mark

Mike takes a sample of five snails from a local field and records how far they travel in 10 minutes. The distances, in metres, are shown below.

2.6      3.1      2.9      2.4      3.6

Use the formula below to calculate an unbiased estimate for the population mean.

̅ x space equals space fraction numerator sum x over denominator n end fraction

2b
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2 marks

Use the formula below to calculate an unbiased estimate for the population variance.

s to the power of 2 space end exponent equals fraction numerator 1 over denominator n minus 1 end fraction space left parenthesis sum x squared minus fraction numerator left parenthesis sum x right parenthesis squared over denominator n end fraction right parenthesis

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3
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4 marks

n observations of a random variable X are used to form a random sample. The sample mean is denoted ̅ X. If X has mean mu and variance sigma squared then ̅ X has mean mu and variance sigma squared over n.

Find the E space open parentheses ̅ X close parentheses and V a r space open parentheses ̅ X close parentheses in the case when:

(i)
E space left parenthesis X right parenthesis equals 20 comma space space space space space space space space space space space V a r space left parenthesis X right parenthesis equals 8 space space space space space space space space space a n d space space space space space space space n equals 4
(ii)
E space left parenthesis X right parenthesis equals 50 comma space space space space space space space space space space V a r space left parenthesis X right parenthesis equals 105 space space space space space space a n d space space space space space space n equals 20
(iii)
E space left parenthesis X right parenthesis equals negative 17 comma space space space space space space V a r space left parenthesis X right parenthesis equals 42 space space space space space space space space a n d space space space space space space n equals 30

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4a
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4 marks

A random sample of n observations of X space tilde space N left parenthesis 10 comma 16 right parenthesis are taken and the distribution of the sample mean is denoted ̅ X subscript n. It is known that the sample mean also follows a normal distribution regardless of the size of the sample.

(i)
In the case where the sample size is 25, write down the distribution of the sample mean, ̅ X subscript 25.
(ii)
Write down the standard deviation of ̅ X subscript 25.
(iii)
Find P left parenthesis 9 less than ̅ X subscript 25 less than 11 right parenthesis.
4b
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2 marks

State which distribution, ̅ X subscript 20 or ̅ X subscript 50, will have the smallest standard deviation. Give a reason for your answer.

4c
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1 mark

Given that the variance of ̅ X subscript n is 0.16, state the value of n.

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5
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4 marks

For each of the following scenarios, state with a reason whether the Central Limit theorem (CLT) is needed for the random variable, ̅ X, to be modelled as a normal distribution.

(i)
The lengths of unicorn horns are known to be normally distributed. A random sample of 20 unicorns are taken and the mean length of their horns is calculated, ̅ X .
(ii)
In an experiment, each participant is asked to flip a fair coin 10 times and count the number of times it lands on tails. 50 people are asked to conduct the experiment and the mean number of tails each person obtained is calculated, ̅ X.
(iii)
The lengths of time taken by university students to complete a crossword puzzle follows a normal distribution. A random sample of 80 students is taken and the mean of their times taken to complete the crossword puzzle is calculated, ̅ X .
(iv)
A fair die is rolled, and George records the number of rolls taken before he obtains a 6. George repeats this process 40 times and calculates the mean number of rolls taken before obtaining a 6.

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6a
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2 marks

The standard normal distribution is given by Z space tilde space N left parenthesis 0 comma 1 squared right parenthesis.

Given that P space left parenthesis negative a less than Z less than a right parenthesis equals 0.95,

(i)
explain why P space left parenthesis Z less than a right parenthesis equals 0.975,
(ii)
hence find the value of a.
6b
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3 marks

A random sample of 25 observations is taken from N space left parenthesis mu comma 6 ² right parenthesis and the sample mean, ̅ x is 15. The formula for the end-points of the 95% confidence interval for the population mean, mu is given by:

̅ x space plus-or-minus space z cross times fraction numerator sigma over denominator square root of n end fraction space space space w h e r e space P space left parenthesis negative z less than Z less than z right parenthesis equals 0.95

Using your answer to part (a) and the formula above

(i)
Calculate the end-points of the 95% confidence interval for mu,
(ii)
Hence write down the 95% confidence interval for mu.
6c
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1 mark

Write down the probability that the confidence interval found in part (b) contains the true population mean, mu.

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7a
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2 marks

The standard normal distribution is given by Z space tilde space N left parenthesis 0 comma 1 squared right parenthesis.

Given that P space left parenthesis negative a less than Z less than a right parenthesis equals 0.99,

(i)
Explain why P space left parenthesis Z less than a right parenthesis equals 0.995,
(ii)
Hence find the value of a.
7b
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1 mark

The probability of success in a trial is p. A random sample of 64 trials are carried out and there were 24 successes.

Calculate the proportion of the trials in the sample, p subscript s, that were successful.

7c
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2 marks

The formula for the end-points of the 99% confidence interval for the probability of success, p is given by:

p subscript s plus-or-minus z cross times square root of fraction numerator p subscript s left parenthesis 1 minus p subscript s right parenthesis over denominator n end fraction end root space space space space space space space w h e r e space P space left parenthesis negative z less than Z less than z right parenthesis equals 0.99

Calculate an approximate 99% confidence interval for the probability of success in a trial, p.

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1a
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3 marks

The times, T seconds, of a random sample of 8 TV adverts on Channel π are as follows.

35

61

42

40

37

35

53

49

Calculate unbiased estimates of the population mean and variance of T.

1b
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3 marks

It is known that the population of T follows a Normal distribution with a variance of 81.

Using the sample from part (a), find a 95% confidence interval for the population mean of T.

1c
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1 mark

Write down the probability that the confidence interval contains the true population mean.

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2a
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3 marks

The masses, M grams, of a random sample of 80 potatoes from a farm are summarised as follows.

n equals 80 space space space space space space space space space space space space sum m equals 17764 space space space space space space space space space space space sum m squared equals 4103225

Calculate unbiased estimates of the population mean and variance.

2b
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3 marks

Calculate a 90% confidence interval for the population mean.

2c
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1 mark

Explain why it was necessary to use the Central Limit theorem in your answer to part (b).

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3a
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3 marks

The gestation period of a female kangaroo, X can be modelled as a Normal distribution with a mean of 29 days and a standard deviation of 4 days.

Given that a randomly selected female kangaroo is pregnant, find the probability that the gestation period will be between 27 and 30 days.

3b
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3 marks

A random sample of 16 pregnant kangaroos is taken and the mean of their gestation periods is calculated.

(i)
Write down the distribution of the sample mean, ̅ X.
(ii)
Calculate the probability that the sample mean of the 16 gestation periods is between 27 and 30 days.
3c
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1 mark

Explain whether it was necessary to use the Central Limit theorem in the solution to part (b).

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4a
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2 marks

For the video game, Super Maria, it is known that the length of time, T minutes, it takes a gamer to complete the final level of the game can be modelled as a Normal distribution with T space tilde space N left parenthesis 57.2 comma 5 squared right parenthesis.

Find the interquartile range for the times taken to complete the final level of Super Maria.

4b
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4 marks

During a Super Maria competition, gamers are randomly put into teams of 9 and each member plays the final level. The mean time for each team is calculated and prizes are given to teams whose means are in the fastest 10% of mean times.

(i)
Write down the distribution of the sample mean, ̅ T.
(ii)
Find, to the nearest second, the maximum mean time that would lead to a team winning a prize. Give your answer in minutes and seconds.

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5a
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4 marks

A spinner has 5 sectors labelled 1 to 5. The spinner is spun 150 times and there were 131 occasions when it landed on the number 3.

Calculate an approximate 92% confidence interval for p, the probability that the spinner lands on the number 3.

5b
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1 mark

Calculate the width of the confidence interval to 3 significant figures.

5c
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2 marks

Explain why the method in part (a) would not be suitable if the spinner had only been spun 15 times.

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6a
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3 marks

ChocoCakes sells chocolate brownies and claims they are good value for money.  Sasha, an inspector, takes a random sample of 40 brownies and records the mass, M grams, of each one.  The results are summarised as follows.

sum m equals 3404 space space space space space space space space space space space space sum m squared equals 297409

Calculate an unbiased estimate of the population mean of the mass of a brownie and show that an unbiased estimate for the variance is 198 g, correct to 3 significant figures.

6b
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5 marks

Sasha takes another large sample of n brownies from ChocoCakes and finds the sample mean, ̅ M. Sasha claims that P space left parenthesis M space ̅ greater than 81.6 right parenthesis equals 0.9909.

Use your estimates from (a) to

(i)
Write down the distribution of ̅ M

(ii)
Show that 3.5 square root of n over 198 end root equals 2.36

(iii)
And hence find the value of n.
6c
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1 mark

Explain why it was important that the sample was large.

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7a
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5 marks

The amount of rainfall, in millimetres, on a summer’s day in London has mean 1.6 and standard deviation 0.6.

A random sample of 40 days is taken over one summer, find the probability that the mean daily amount of rainfall for this sample is between 1.5 and 1.8 millimetres.

7b
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1 mark

Explain whether it was necessary to use the Central Limit theorem in the solution to part (a).

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1a
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3 marks

The times, T minutes, taken by athletes to run a marathon can be modelled by a normal distribution with a known standard deviation of 19 minutes. Below shows the times taken to complete a marathon by a random sample of 7 athletes.

145

131

139

157

166

133

171

Calculate unbiased estimates for the mean and the variance of T.

1b
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3 marks

Calculate a 95% confidence interval for the population mean marathon time.

1c
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2 marks

Find the probability that the confidence interval found in part (b) is wholly below the true value of the population mean.

1d
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1 mark

A random sample of 30 athletes is now taken and a 95% confidence interval is found. Without calculation, state whether this confidence interval will be wider or narrower than the confidence interval found in part (b). Give a reason for your answer.

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2a
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6 marks

Jim, a pigeon researcher, records the speeds, S kilometres per hour, of pigeons as they fly past a particular spot. Jim takes a random sample of 60 pigeons and the results are summarised as follows.

n equals 60 space space space space space space space space space space space space space sum s equals 6309 space space space space space space space space space space space space sum s squared equals 688312

Calculate a 97% confidence interval for the population mean speed, giving the end-points correct to 1 decimal place.

2b
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1 mark

Explain whether it was necessary to use the Central Limit theorem in part (a).

2c
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1 mark

In total, Jim takes three random samples, each containing 60 pigeons. Jim calculates the 97% confidence intervals for the population mean, mu, for each sample. Find the probability that all three of these intervals contain the true value of mu.

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3a
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2 marks

The amount of time, measured in hours, that French bulldogs sleep in a day can be modelled using N left parenthesis 13.2 comma 3.6 right parenthesis.

Find the probability that a randomly selected French bulldog sleeps for more than 12 hours in a day.

3b
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3 marks

At a French bulldog fan club meeting, owners share the lengths of time that their dogs sleep. Collectively, they have 8 French bulldogs, and it can be assumed that they form a random sample.

Find the probability that the mean length of time that the 8 French bulldogs sleep is more than 12 hours in a day.

3c
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1 mark

Explain whether it was necessary to use the Central Limit theorem in part (b).

3d
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4 marks

The amount of time, in hours, that English bulldogs sleep in a day can also be modelled by a normal distribution with mean 10.4.  It is known from observations that there is a 10% chance that a random sample of 10 English bulldogs will have a mean of less than 10.1 for the number of hours they sleep in a day.

Find the standard deviation of the lengths of time that English bulldogs sleep in a day.

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4a
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1 mark

The price, £ space P, for an hour tutoring session in a local town can be modelled by a normal distribution with mean mu and standard deviation sigma. A random sample of 20 one-hour tutoring sessions was taken, and the 99% confidence interval for  was calculated to be £29.42 to £41.68.

Write down the mean price of the 20 tutoring sessions in the sample.

4b
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3 marks

Show that sigma equals 10.64, correct to two decimal places.

4c
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3 marks

Find the minimum sample size needed so that the width of the 99% confidence interval for mu is less than 5.

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5a
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2 marks

A random sample of 80 people from Politicity were asked whether they are planning to vote in the next election, k people said that they were planning to vote. An alpha percent sign confidence interval for the population proportion planning to vote is 0.4678 less than p less than 0.6822.

By finding the mid-point of this confidence interval, find the value of k.

5b
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4 marks

Find the value of alpha.

5c
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1 mark

It is known that 59.3% of the population of Politicity voted in the last election.

Assuming everyone who plans to vote, does indeed vote, state with a reason whether there is evidence to say that the proportion of people who vote has changed.

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6a
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4 marks

Loompers, a candy shop, sells bags of pick ‘n’ mix sweets. The masses, M grams, of these bags follow a normal distribution with variance 973. William, the owner, advertises that the mean mass of a bag of pick ‘n’ mix sweets is 300 g. Charlie, the owner of a rival shop, takes a random sample of 60 bags of pick ‘n’ mix sweets and finds that the mean mass is 289 g. Charlie claims that William is overstating the mean mass.

By calculating a 98% confidence interval for the true population mean, state with a reason whether Charlie’s claim is justified.

6b
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1 mark

Would your answer to part (a) have been any different if the population of masses was not normally distributed? Give a reason for your answer.

6c
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2 marks

William takes a random sample of 60 bags and calculates the confidence interval for the population mean to be 282 to 304 grams. State, with a reason, whether William used a higher or lower confidence level than Charlie’s 98%.

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7a
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3 marks

At Abacus High School, students are not grouped by ability, instead they are randomly assigned to a teacher. Two months before their external examination, students are given a practice paper. The headteacher uses this to measure student progress and teacher performance. It is known that each year the standard deviation of marks in this practice paper is 15.7 but the mean mark mu varies. Mr Cauchy calculates the mean for the 35 students in his class to be 75.4.

Using Mr Cauchy’s class as a random sample, calculate a 95% confidence interval for mu.

7b
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1 mark

Explain whether it was necessary to use the Central Limit theorem in your answer to part (a).

7c
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2 marks

Find the probability that the confidence interval found in part (a) is wholly above the true value of mu.

7d
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2 marks

The headteacher calculates that this year’s population mean for the practice paper is 68.7 marks.

What conclusions might the Headteacher make about Mr Cauchy and his students?

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1a
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2 marks

The mass of a penny follows a normal distribution with mean 3.56 g and standard deviation 0.63 g.

Find the probability that a randomly selected penny weighs less than 3.9 g.

1b
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7 marks

Stuart has ten random pennies in his pocket.

(i)
Find the probability that the total mass of the ten pennies is less than 39 g.
(ii)
Find the probability that more than one quarter of Stuart’s pennies weigh less than 3.9 g.
1c
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2 marks

Stuart uses his sample to calculate a 90% confidence interval for the population mean. Given that the confidence interval is 3.48 to 3.54 grams, give the conclusion Stuart should come to about his sample.

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2a
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4 marks

Zodiac Soda Ltd sells watermelon flavoured soda. The volume of soda in one of the bottles, V ml, is modelled using the distribution V space N left parenthesis w comma 9 squared right parenthesis. Zodiac Soda Ltd sells the soda in packs of eight bottles.

A pack is chosen at random. Find the probability the mean volume of the eight bottles is within 5 ml of w.

2b
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3 marks

A pack is classed as insufficient if the mean volume of the eight bottles is less than 374 ml.

Given that 2.5% of all packs are insufficient, calculate the value of w giving your answer to the nearest millilitre.

2c
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1 mark

The owner of Zodiac Soda Ltd takes a random sample of 50 bottles and calculates a 95% and 99% confidence interval for the population mean w. The two intervals are 379 to 383 ml and 375 to 381 ml respectively.

State, with a reason, which interval has the 95% confidence level.

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3a
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6 marks

Roger has a keen fascination with rabbits that live on Easter Island, in particular the lengths of their ears. The mean length of a rabbit’s ear on Easter Island is mu cm. He takes a random sample of 40 rabbits and finds that a 90% confidence interval for mu is 8.3 to 9.9 cm.

Using the same sample, find a 99% confidence interval for mu. Give the end-points correct to 1 decimal place.

3b
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4 marks

Roger wants to find a confidence interval for mu with a width of 1.28 cm. Find the confidence level that Roger should use.

3c
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1 mark

Roger takes 100 random samples and calculates a 95% confidence interval for each one. How many of the confidence intervals would be expected to contain the true population mean, mu.

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4a
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8 marks

El Cumpleanyos is a business specialising in birthday party goods. Takato collects a random sample of 30 birthday candles from El Cumpleanyos and records how long each one stays lit, T minutes. The results are summarised as follows.

n equals 30 space space space space space space space space space space space space space space sum t equals 827 space space space space space space space space space space space space sum t squared equals 25374 

Kenta takes a different random sample of 50 birthday candles and calculates unbiased estimates for the mean and variance of T, shown below.

̅ t equals 28.1 space space space space space space space space space space space space and space space space space space space space space space space space s subscript t superscript 2 equals 105.7

(i)
By combining the two samples into one sample of size 80, calculate unbiased estimates for the mean and variance of T.
(ii)
Using the mean and variance in part (a)(i), calculate a 92% confidence interval for the population mean time that the candles stay lit.
4b
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2 marks

Kazu takes five random samples of candles and for each sample he calculates a 92% confidence interval for the population mean. Find the probability that exactly four of the confidence intervals will contain the true value of the population mean.

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5a
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7 marks

A spinner has 8 sectors labelled 1 to 8. Richard spins the spinner n times and it lands on the number ‘7’ 35 times. An alpha percent sign confidence interval for the true probability of landing on the number ‘7’ is 0.1059 less than p less than 0.1741.

Find the value of alpha.

5b
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1 mark

Richard claims that the spinner has unequal sectors such that the probability of it landing on a seven is different to the probability of it landing on the other numbers.

Use the confidence interval to comment on Richard’s claim.

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6a
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3 marks

A biased four-sided die is rolled once and the random variable D is the number showing when the die lands. The probability distribution of D is shown in the table below.

d

1

2

3

4

P left parenthesis D equals d right parenthesis

0.4

0.3

0.2

0.1


Find E left parenthesis X right parenthesis and show that V a r left parenthesis X right parenthesis equals 1.

6b
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5 marks

The die is rolled 100 times and the sum, S, of all the numbers it lands on is found.

By considering the mean, find an estimate for P space left parenthesis S less than 195 right parenthesis.

6c
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1 mark

State, with a reason, whether it was necessary to use the Central Limit theorem in your answer to part (b).

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7a
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2 marks

Students at a school for superheroes have the strength of their powers measured using units called Powerpoints (PP). The strengths of the students’ powers are normally distributed with a mean mu PP and a standard deviation 15 PP. The school has thousands of students so three teachers take random samples and use them to calculate confidence intervals for the population mean mu.

Jean’s sample consists of 100 students. She calculates a 95% confidence interval for mu.

Calculate the width of Jean’s confidence interval.

7b
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3 marks

Scott’s sample consists of 50 students. He wants the width of his confidence interval to be the same as Jean’s. Calculate the confidence level that Scott should use to calculate his confidence interval.

7c
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3 marks

Ororo uses a 99% confidence level for her confidence interval. She wants the width of her confidence interval to be no bigger than Jean’s. Calculate the smallest number of students that Ororo should include in her sample.

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