Using suvat (AQA A Level Maths: Mechanics)

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Dan

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Dan

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Using suvat

How do I use the suvat equations to solve projectile problems?

2-6-1-horizontal-_-vertical-components-diagram-2

  • For projectile motion with acceleration a m s-2 and initial velocity u m s-1
    • ax = 0, ay = ±g (depending on which direction is positive)
    • ux = Ucosθ, uy = Usinθ
  • Acceleration is constant so the suvat equations apply
  • Projectile motion is 2D so s, u, v and a are vectors
    • 1D suvat formulae can be applied to the directions separately

(Note the formula v2 = u2 + 2as still applies in 1D)

  • Remember that acceleration is different for each direction
    • ax = 0 so the suvat formulae reduce to sx = uxt horizontally

How do I solve problems involving the maximum height?

2-6-2-using-suvat-diagram-1-1

  • Projectile motion follows a symmetrical curve (a parabola)
  • Therefore there will be a maximum height that the projectile reaches
  • At the maximum height
    • Horizontal velocity, vx m s-1, will be the same as the initial horizontal velocity ux
    • Vertical velocity, vy m s-1 will be instantaneously zero
    • If the projectile launches and lands at the same height then the horizontal distance to the maximum height is half of the range of the projectile
  • Time t is the parameter that will be the same for both the horizontal and vertical components

Harder concepts with projectiles

  •  You will need all your skills from your previous work with suvat
    • Speed is the magnitude of velocity and can be found by using Pythagoras’ Theorem
    • A good understanding of the relationship between distance and displacement
    • Simultaneous equations
    • Finding the point of intersection of two projectiles
  • Sometimes the launch and landing points will be at different heights such as if a stone is thrown from the top of a cliff into the sea
      • Think carefully about the vertical displacement from the start to the end
  • You might get asked to use the model of a projectile to decide whether an object passes over a certain height
    • Find the time taken to travel the horizontal distance and use this to find the maximum vertical height of the projectile

Worked example

2.6.2_WE_Using Suvat_1

(a)  Find the maximum height above the ground that the stone reaches.

2-6-2-using-suvat-example-solution-aqa-a

(b)  Find the time taken for the stone to hit the ground.

2-6-2-using-suvat-example-solution-aqa-b

(c)  Find the horizontal distance from the building to the point where the stone lands.

2-6-2-using-suvat-example-solution-aqa-c

Examiner Tip

  • Always draw a diagram and add to it as you work through the question. Make it clear which direction you are using as positive.
  • Questions could ask you to find the speed at an instant, to do this remember to first find both components of the velocity and then find the magnitude of the velocity.
  • Not all projectiles are projected upwards, for example a cannonball fired from the turret of a castle aimed at an enemy on the ground!
    Remember to round answers to 2 significant figures if g=9.8 is used.

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Dan

Author: Dan

Expertise: Maths

Dan graduated from the University of Oxford with a First class degree in mathematics. As well as teaching maths for over 8 years, Dan has marked a range of exams for Edexcel, tutored students and taught A Level Accounting. Dan has a keen interest in statistics and probability and their real-life applications.