Further Integration (Edexcel A Level Maths: Pure): Exam Questions

5 hours52 questions
1
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3 marks

Find

(i)

integral 1 over x space straight d x

(ii)

integral subscript 0 superscript 1 straight e to the power of x space straight d x

(iii)

integral 3 cos space theta space straight d theta

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2a
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2 marks

Use a suitable substitution to show that

integral 3 cos space open parentheses 3 x plus 2 close parentheses space straight d x equals integral cos space u space straight d u

2b
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1 mark

Hence find

integral 3 cos space open parentheses 3 x plus 2 close parentheses space straight d x

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3a
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1 mark

Find

integral sin space x space straight d x

3b
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2 marks

Show that

integral subscript 1 superscript 4 1 over x space straight d x equals ln space 4

3c
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1 mark

Find

integral 7 straight e to the power of 7 x end exponent space straight d x

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4
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6 marks

Find

(i)

integral 8 open parentheses 2 x minus 1 close parentheses cubed space straight d x

(ii)

integral subscript 0 superscript straight pi over 4 end superscript sin space 2 x space straight d x

(iii)

integral 3 straight e to the power of 3 x end exponent space straight d x

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5a
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1 mark

Given the identity cos space 2 A identical to 1 minus 2 space sin squared A, show that

sin squared A identical to 1 half left parenthesis 1 minus cos space 2 A right parenthesis

5b
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3 marks

Hence find the exact value of

integral subscript straight pi over 2 end subscript superscript straight pi sin squared x space straight d x

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6
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3 marks

Show that

integral subscript 1 superscript 2 straight e to the power of 3 x plus 2 end exponent space d x equals 1 third straight e to the power of 5 open parentheses straight e cubed minus 1 close parentheses

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7a
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2 marks

Find

integral cos space 2 x space straight d x

7b
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4 marks

Show that

integral subscript 0 superscript 2 open parentheses 3 x minus 1 close parentheses cubed space straight d x equals 52

7c
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1 mark

Find

integral straight e to the power of 5 x end exponent space straight d x

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8a
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2 marks

Find

integral 5 left parenthesis straight e to the power of 5 x end exponent minus straight e to the power of negative 5 x end exponent right parenthesis space straight d x

8b
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2 marks

Find

integral open parentheses sin space x plus cos space x close parentheses space straight d x

8c
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3 marks

Show that

integral subscript negative 8 end subscript superscript negative 2 end superscript 1 over x space straight d x equals ln open parentheses 1 fourth close parentheses

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1a1 mark

Express limit as delta x rightwards arrow 0 of sum from x equals 2.1 to 6.3 of 2 over x delta x space as an integral.

1b
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2 marks

Hence show that

limit as delta x rightwards arrow 0 of sum from x equals 2.1 to 6.3 of 2 over x delta x space equals ln space k

where k is a constant to be found.

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2a4 marks

Given that k element of straight integer numbers to the power of plus

show that integral subscript k superscript 3 k end superscript fraction numerator 2 over denominator open parentheses 3 x minus k close parentheses end fraction d x is independent of k.

2b3 marks

Given that k element of straight integer numbers to the power of plus

show that integral subscript k superscript 2 k end superscript 2 over open parentheses 2 x minus k close parentheses squared d x is inversely proportional to k.

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3a3 marks

Given that

fraction numerator x squared plus 8 x minus 3 over denominator x plus 2 end fraction identical to A x plus B plus fraction numerator C over denominator x plus 2 end fraction space space space space space space space space space space space space space x element of straight real numbers space space space space x not equal to negative 2

find the values of the constants A, B and C

3b
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4 marks

Hence, using algebraic integration, find the exact value of

integral subscript 0 superscript 6 fraction numerator x squared plus 8 x minus 3 over denominator x plus 2 end fraction space straight d x

giving your answer in the form a plus b ln 2 where a and b are integers to be found.

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45 marks

Show that

integral subscript 1 superscript straight e squared end superscript x cubed ln space x straight d x equals a straight e to the power of 8 plus b

where a and b are rational constants to be found.

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5
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2 marks

Find

integral fraction numerator 4 x over denominator 2 x squared plus 5 end fraction space straight d x

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6
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4 marks

Show that

integral subscript 2 superscript 6 4 open parentheses 4 x plus 1 close parentheses to the power of 1 half end exponent d x equals 196 over 3

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7
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3 marks

Find

integral negative 15 sin space open parentheses 5 x minus 2 close parentheses space straight d x

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8
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3 marks

Find

integral negative 3 x sin space x space straight d x

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9
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6 marks

Use the substitutionĀ u equals x plus 4 to show that

integral subscript 1 superscript 2 fraction numerator x over denominator x plus 4 end fraction space straight d x equals 1 plus 4 ln open parentheses 5 over 6 close parentheses

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10
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3 marks

Find

integral fraction numerator 3 x squared plus 2 over denominator 2 x cubed plus 4 x end fraction space straight d x

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11a
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2 marks

Find

integral 2 sin space x space cos space x space straight d x

11b
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4 marks

Use algebraic integration to find the exact value of

integral subscript 1 superscript 3 open parentheses 4 x plus 1 close parentheses to the power of 5 space straight d x

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12
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3 marks

Find

integral 8 x space sin left parenthesis 3 x squared plus 1 right parenthesis space straight d x

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13a
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2 marks

Show that

fraction numerator 11 over denominator left parenthesis 2 x minus 3 right parenthesis left parenthesis x plus 4 right parenthesis end fraction

can be written in the form

fraction numerator A over denominator 2 x minus 3 end fraction plus fraction numerator B over denominator x plus 4 end fraction

where A and B are constants to be found.

13b
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4 marks

Hence find

integral fraction numerator 11 over denominator left parenthesis 2 x minus 3 right parenthesis left parenthesis x plus 4 right parenthesis end fraction space straight d x

writing your answer in the form

ln vertical line straight f open parentheses x close parentheses vertical line plus c

where straight f open parentheses x close parentheses is a function you should find and c is a constant.

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14
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6 marks

The figure below shows a sketch of the curves with equations y equals x squared minus 3 x plus 4 and y equals 4 minus x squared plus 2 x.

The shaded region R is bounded by the two curves.

q11-8-2-further-integration-medium-a-level-maths-pure-screenshot

Use algebraic integration to find the exact area of R.

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15a
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2 marks

Given that

fraction numerator 2 x minus 1 over denominator left parenthesis x plus 1 right parenthesis left parenthesis x minus 2 right parenthesis end fraction identical to fraction numerator A over denominator x plus 1 end fraction plus fraction numerator B over denominator x minus 2 end fraction

find the values of the constants A and B.

15b
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4 marks

Hence show that if x greater than 2 then

integral fraction numerator 2 x minus 1 over denominator left parenthesis x plus 1 right parenthesis left parenthesis x minus 2 right parenthesis end fraction space straight d x equals ln open parentheses c open parentheses x plus 1 close parentheses open parentheses x minus 2 close parentheses close parentheses

where c is a constant.

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16
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6 marks

The figure below shows a sketch of the curves with equations y equals x cubed plus 3 and y equals negative x cubed plus 2 x plus 3.

The finite regions bounded by the two curves are shaded.

q11-8-2-further-integration-hard-a-level-maths-pure-screenshot

Use algebraic integration to find the exact total area of the shaded regions.

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13 marks
Graph of y = square root of x with shaded rectangle at point P on curve. Axes marked x and y, with intervals at 4, Ī“x, and 9 on x-axis.
Figure 3

Figure 3 shows a sketch of the curve with equation y equals square root of x.

The point P open parentheses x comma space y close parentheses lies on the curve.

The rectangle, shown shaded on Figure 3, has height y and width delta x.

Calculate

limit as delta x rightwards arrow 0 of space sum from x equals 4 to 9 of square root of x delta x

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2a
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3 marks

The curve C with equation

table row cell y equals fraction numerator p minus 3 x over denominator open parentheses 2 x minus q close parentheses open parentheses x plus 3 close parentheses end fraction end cell blank cell x element of straight real numbers comma space x not equal to negative 3 comma space x not equal to 2 end cell end table

where p and q are constants, passes through the point open parentheses 3 comma space 1 half close parentheses and has two vertical asymptotes with equations x equals 2 and x equals negative 3

(i) Explain why you can deduce that q equals 4

(ii) Show that p equals 15

2b
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8 marks
Graph showing a decreasing curve labelled C. The area bounded by the x-axis and a vertical line at x=3 is shaded and labelled R.
Figure 4

Figure 4 shows a sketch of part of the curve C. The region R, shown shaded in Figure 4, is bounded by the curve C, the x-axis and the line with equation x equals 3

Show that the exact value of the area of R is a ln 2 plus b ln 3, where a and b are rational constants to be found.

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3a4 marks

Use the substitution x equals u squared plus 1 to show that

integral subscript 5 superscript 10 fraction numerator 3 space straight d x over denominator open parentheses x minus 1 close parentheses open parentheses 3 plus 2 square root of x minus 1 end root close parentheses end fraction equals integral subscript p superscript q fraction numerator 6 space straight d u over denominator u open parentheses 3 plus 2 u close parentheses end fraction

where p and q are positive constants to be found.

3b6 marks

Hence, using algebraic integration, show that

integral subscript 5 superscript 10 fraction numerator 3 space straight d x over denominator open parentheses x minus 1 close parentheses open parentheses 3 plus 2 square root of x minus 1 end root close parentheses end fraction equals space ln space a

where a is a rational constant to be found.

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4
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5 marks

Use the substitutionĀ u equals 2 plus ln space x to show that

integral fraction numerator 1 over denominator x open parentheses 2 plus ln space x close parentheses cubed end fraction space straight d x equals fraction numerator negative 1 over denominator 2 open parentheses ln space x space plus 2 close parentheses squared end fraction plus c

where c is a constant.

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5
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6 marks

Use algebraic integration to show that

integral subscript 0 superscript 1 left parenthesis 5 x minus 4 right parenthesis straight e to the power of 3 x end exponent space straight d x equals fraction numerator 17 minus 2 straight e cubed over denominator 9 end fraction

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6
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3 marks

FindĀ 

integral square root of 1 plus cot squared x end root space d x

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7
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6 marks

Use algebraic integration to show that

integral subscript straight pi over 4 end subscript superscript straight pi over 2 end superscript cos squared theta space d theta equals straight pi over 8 minus 1 fourth

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8
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3 marks

The figure below shows a sketch of the curve with equationĀ y equals 1 plus 2 x minus 1 fourth x squared where

  • the pointĀ  P left parenthesis x comma space y right parenthesisĀ lies on the curve

  • the shaded rectangle shown has width delta x and height y

q1-8-2-further-integration-hard-a-level-maths-pure-screenshot

By expressing the series as a suitable integral, show that

limit as delta x rightwards arrow 0 of space sum from x equals 1 to 8 of open parentheses space 1 plus 2 x minus 1 fourth x squared close parentheses space delta x equals 329 over 12

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9
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7 marks

Use algebraic integration to show that

integral subscript straight pi over 6 end subscript superscript straight pi over 3 end superscript space fraction numerator 2 minus 2 cos squared theta space over denominator sin space 2 theta end fraction space straight d theta equals 1 half ln space 3 space

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10
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5 marks

Use algebraic integration to show that

integral subscript 0 superscript 1 fraction numerator 3 x straight e to the power of negative 3 x squared end exponent over denominator 3 minus 2 straight e to the power of negative 3 x squared end exponent end fraction space straight d x equals 1 fourth ln left parenthesis 3 minus 2 straight e to the power of negative 3 end exponent right parenthesis

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11
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6 marks

Use algebraic integration to show that

integral subscript straight pi over 2 end subscript superscript fraction numerator 5 straight pi over denominator 6 end fraction end superscript space fraction numerator 2 space cos space x over denominator 1 minus cos space 2 x end fraction space space straight d x equals negative 1

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12a
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5 marks

Use algebraic integration to show that

integral open parentheses 2 x squared minus 1 close parentheses straight e to the power of x space straight d x equals open parentheses p x squared plus q plus r close parentheses straight e to the power of x plus c

where p, q and r are integers to be found and c is a constant.

12b
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4 marks

Show that

integral ln space x space straight d x equals x ln space x minus x plus c

where c is a constant.

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13
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7 marks

Use algebraic integration to find

integral fraction numerator x squared minus 4 x plus 7 over denominator open parentheses x minus 1 close parentheses open parentheses x minus 3 close parentheses squared end fraction space straight d x

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14a
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3 marks

Use algebraic integration to find

integral 5 cos squared space 4 x space sin space 4 x space straight d x

14b
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3 marks

Use algebraic integration to find

integral 3 x open parentheses 5 x squared plus 4 close parentheses to the power of 4 space straight d x

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15a
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3 marks

Use algebraic integration to find

integral 6 x squared straight e to the power of x cubed end exponent space straight d x

15b
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3 marks

Use algebraic integration to find

integral open parentheses 16 minus 32 x close parentheses sin open square brackets open parentheses 4 x minus 2 close parentheses squared close square brackets space straight d x

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16a
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6 marks

Use algebraic integration to find

integral x squared sin space 3 x space straight d x

16b
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4 marks

Use algebraic integration to find

integral fraction numerator ln space x over denominator space x cubed end fraction space straight d x

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1
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10 marks
Graph showing axes x and y with lines l and C intersecting at point P(e, e). A region bounded by C, l and the x-axis is shaded and labelled R. The origin is labelled O.
Figure 2

Figure 2 shows a sketch of part of the curve C with equation y equals x ln x comma space x greater than 0

The line l is the normal to C at the point P open parentheses straight e comma space straight e close parentheses

The region R, shown shaded in Figure 2, is bounded by the curve C, the line l and the x-axis.

Show that the exact area of R is A straight e squared plus B where A and B are rational numbers to be found.

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25 marks
Graph showing a curve with shaded area R under it, between x=2 and x=4, with axes labelled x and y.
Figure 2

Figure 2 shows a sketch of part of the curve with equation

y equals open parentheses ln x close parentheses squared space space space x greater than 0

The finite region R, shown shaded in Figure 2, is bounded by the curve, the line with equation x equals 2, the x-axis and the line with equation x equals 4.

Use algebraic integration to find the exact area of R, giving your answer in the form

a open parentheses ln 2 close parentheses squared plus b ln 2 plus c

where a, b and c are integers to be found.

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3a
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4 marks

In this question you must show all stages of your working.

Solutions relying entirely on calculator technology are not acceptable.

Find the first three terms, in ascending powers of x, of the binomial expansion of

open parentheses 3 plus x close parentheses to the power of negative 2 end exponent

writing each term in simplest form.

3b
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4 marks

Using the answer to part (a) and using algebraic integration, estimate the value of

integral subscript 0.2 end subscript superscript 0.4 end superscript fraction numerator 6 x over denominator open parentheses 3 plus x close parentheses squared end fraction space d x

giving your answer to 4 significant figures.

3c
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5 marks

Find, using algebraic integration, the exact value of

integral subscript 0.2 end subscript superscript 0.4 end superscript fraction numerator 6 x over denominator open parentheses 3 plus x close parentheses squared end fraction space d x

giving your answer in the form a space ln open parentheses b close parentheses plus c, where a, b and c are constants to

be found.

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4
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7 marks

Show that

integral subscript 0 superscript 2 2 x square root of x plus 2 end root space d x equals 32 over 15 open parentheses 2 plus square root of 2 close parentheses

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56 marks

Use the substitution u equals 4 minus square root of h to show that

integral fraction numerator d h over denominator 4 minus square root of h end fraction equals negative 8 ln open vertical bar 4 minus square root of h close vertical bar minus 2 square root of h plus k

where k is a constant.

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6
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3 marks

Find the value of

limit as delta x rightwards arrow 0 space of sum from x equals 2 to 5 of 2 straight e to the power of 0.1 x end exponent space delta x

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7
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6 marks

Use the substitutionĀ x equals cos space theta to show that

integral subscript fraction numerator 1 over denominator square root of 2 end fraction end subscript superscript fraction numerator square root of 3 over denominator 2 end fraction end superscript fraction numerator 1 over denominator square root of 1 minus x squared end root space end fraction straight d x equals pi over 12

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8
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5 marks

Use algebraic integration to find

integral open parentheses 2 tan space x space plus 3 sec space x close parentheses squared space straight d x

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9a
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3 marks

Prove that

integral tan space k x space straight d x equals 1 over k ln space open vertical bar sec space k x close vertical bar plus c

where k and c are constants.

9b
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5 marks

Use algebraic integration to show that

integral subscript straight pi over 18 end subscript superscript straight pi over 9 end superscript fraction numerator cosec to the power of 2 space end exponent 3 theta space over denominator 3 space cot space 3 theta end fraction space straight d theta equals a ln space 3

where a is a rational number to be found.

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10
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8 marks

Show that

integral fraction numerator 8 x squared minus 8 x minus 1 over denominator left parenthesis 4 x squared minus 1 right parenthesis left parenthesis x minus 2 right parenthesis end fraction space straight d x equals ln open parentheses k vertical line x minus 2 vertical line square root of vertical line 4 x squared minus 1 vertical line end root close parentheses

where k is a constant.

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11
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6 marks

Show that

integral straight e to the power of x sin space x space straight d x equals 1 half straight e to the power of x open parentheses sin space x minus cos space x close parentheses plus c

where c is a constant.

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12a
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1 mark

The figure below shows a sketch of the curves with equations y equals square root of 25 minus x squared space space end root Ā  Ā  andĀ y equals 6 x minus x squared minus 5.

The finite regions bounded by the two curves are shaded.

q9-8-2-further-integration-veryhard-a-level-maths-pure-screenshot

Show that the x-coordinates of the points of intersection are x equals 3, x equals 4 and x equals 5.

[You do not need to solve an equation in x]

12b
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7 marks

Use the substitutionĀ x equals 5 sin space u to show that

integral square root of 25 minus x squared end root space straight d x equals fraction numerator 25 arcsin open parentheses x over 5 close parentheses space plus x square root of 25 minus x squared end root over denominator 2 end fraction plus c

where c is a constant.

12c
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5 marks

Hence show that the exact area of the shaded regions is

fraction numerator 25 pi over denominator 4 end fraction minus 4 minus 25 over 2 open parentheses 2 arcsin open parentheses 4 over 5 close parentheses minus arcsin open parentheses 3 over 5 close parentheses close parentheses

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