Logarithmic Forms of Inverse Hyperbolic Functions (Edexcel A Level Further Maths: Core Pure)

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Logarithmic Forms of Inverse Hyperbolic Functions

What are the definitions of the inverse hyperbolic functions?

  • arsinh x equals ln open parentheses x plus square root of x squared plus 1 end root close parenthesesx element of straight real numbers
  • ar cosh x equals ln open parentheses x plus square root of x squared minus 1 end root close parenthesesx greater or equal than 1
    • Since coshx is a many-to-one function, its domain is restricted to x ≥ 0 when finding the inverse
    • Therefore, its range is coshx ≥ 1
    • So, the domain of the inverse function is x ≥ 1
  • artanh x equals 1 half ln open parentheses fraction numerator 1 plus x over denominator 1 minus x end fraction close parenthesesvertical line x vertical line less than 1
  • These three definitions are in the formula booklet

What are the graphs of the inverse hyperbolic functions and their key features?

  • As they are inverse functions, they are reflections of their original functions in the line y=x
  • space y equals arsinh x
    • Domain: x element of straight real numbers
    • Range: space y element of straight real numbers

edexcel-al-fm-cp-4-1-2-arsinhx-graph

  • space y equals ar cosh x
    • Domain: x greater or equal than 1
    • Range: space y greater or equal than 0

edexcel-al-fm-cp-4-1-2-arcoshx-graph

  • space y equals ar tanh x
    • Domain: negative 1 less than x less than 1
    • Range: space y element of straight real numbers

edexcel-al-fm-cp-4-1-2-artanhx-graph

How do I derive the logarithmic formulae for the inverse hyperbolic functions?

  • You need to be able to derive each inverse from the definition of the original
  • STEP 1
    Write in terms of e
    • space y equals arsinh x and rearrange to x equals sinh y
    • x equals 1 half open parentheses straight e to the power of y minus straight e to the power of negative y end exponent close parentheses
  • STEP 2
    Form a quadratic in terms of ey
    • Multiply by 2ey and rearrange
    • open parentheses straight e to the power of y close parentheses squared minus 2 x straight e to the power of y minus 1 equals 0
  • STEP 3
    Solve the quadratic and find an expression for y
    • straight e to the power of y equals x plus-or-minus square root of x squared plus 1 end root
      • Reject x minus square root of x squared plus 1 end root as this produces negative values as square root of x squared plus 1 end root greater than x whereas straight e to the power of y greater than 0
    • space y equals ln open parentheses x plus square root of x squared plus 1 end root close parentheses
  • The derivations of the other two formulae are similar
    • For arcosh x both ln open parentheses x plus square root of x squared minus 1 end root close parentheses and ln open parentheses x minus square root of x squared minus 1 end root close parentheses are well-defined for x greater or equal than 1 
      • We choose arcosh x equals ln open parentheses x plus square root of x squared minus 1 end root close parentheses as arcosh x greater or equal than 0 and it can be shown that ln open parentheses x minus square root of x squared minus 1 end root close parentheses equals ln open parentheses fraction numerator 1 over denominator x plus square root of x squared minus 1 end root end fraction close parentheses equals negative ln open parentheses x plus square root of x squared minus 1 end root close parentheses

Examiner Tip

  • Be careful when working with the circular (“normal”) inverse trig functions and the inverse hyperbolic functions
    • Only the “ar” denotes inverse
      • The “c” in arcsin x, arccos x, arctan x indicates the circular functions
      • The hyperbolic functions have “h”, but the “h” doesn’t come immediately after the “ar”: arsinh x, arcosh x, artanh x
    • Be careful not to confuse these, especially when looking them up in the formulae booklet

Worked example

Starting from the definition of tanh x, show that 

artanh x equals 1 half ln open parentheses fraction numerator 1 plus x over denominator 1 minus x end fraction close parentheses when vertical line x vertical line less than 1.

al-fm-4-1-2-we-solution

 

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Paul

Author: Paul

Expertise: Maths

Paul has taught mathematics for 20 years and has been an examiner for Edexcel for over a decade. GCSE, A level, pure, mechanics, statistics, discrete – if it’s in a Maths exam, Paul will know about it. Paul is a passionate fan of clear and colourful notes with fascinating diagrams – one of the many reasons he is excited to be a member of the SME team.