Acids, Bases & Buffers (OCR A Level Chemistry)

Exam Questions

4 hours34 questions
1a1 mark

This question is about some reactions of ethanoic acid.

Ethanoic acid can be defined as an acid by Brønsted-Lowry acid-base theory.
Define what is meant by a Brønsted-Lowry acid.

1b3 marks

Ethanoic acid solution, CH3COOH, reacts with the strong base sodium hydroxide, NaOH, to form sodium ethanoate and water. 

i)
Write an equation for this reaction, including state symbols.

[2]

ii)
Identify the conjugate base to ethanoic acid that makes up one of the conjugate acid-base pairs in this reaction.

[1]

1c1 mark

Write an ionic equation for the reaction of ethanoic acid with sodium hydroxide.

1d2 marks

Ethanoic acid is a weak acid, and so the concentration of the acid is not equal to the concentration of available H+ ions. 

i)
Write an expression for the acid dissociation constant, Ka, of ethanoic acid.

[1]

ii)
Deduce the units for Ka.

[1]

Did this page help you?

2a2 marks

This question is about pH calculations.

Two acids used in the same laboratory, which both have the same concentration, 0.1 mol dm-3, can have significantly different pH values. Explain why.

2b
Sme Calculator
2 marks

Calculate the pH of a solution of 0.1 mol dm-3 HCl.

2c
Sme Calculator
4 marks

A sample of 0.1 mol dm-3 methanoic acid has a Ka value of 1.78 x 10-4 mol dm-3 at 298 K. 

i)

Write an expression for the acid dissociation constant, Ka, for methanoic acid. 

ii)

Calculate the pH of the 0.1 mol dm-3 methanoic acid. Give your answer to two decimal places.

2d1 mark

Using your answer to part c), at which concentration would the pH of hydrochloric acid, HCl, be equal to the pH of 0.1 mol dm-3 methanoic acid?

Did this page help you?

3a
Sme Calculator
3 marks

This question is about using the ionic product of water, Kw.

The value of Kw at 298 K is 1.00 x 10-14 mol2 dm-6.

i)
Write an expression for Kw.

[1]

ii)
Calculate the pH of water at 298 K.

[2]

3b
Sme Calculator
2 marks

The pH of water varies with temperature. At lower temperatures, the pH is more basic and at higher temperatures, the pH is more acidic.

i)
Calculate [H+] when the pH of pure water is 7.27.

[1]

ii)
Calculate [OH-] when the pH of pure water is 7.27.

[1]

3c
Sme Calculator
1 mark

Calculate the value of Kw when the pH of water is 7.27, using your answer from b) including units.

3d
Sme Calculator
2 marks

The ionic product of water can also be used to calculate the pH of strong bases, where [H+not equal to[OH-]. 

Calculate the pH of KOH at 298 K when [OH-] = 1.00 x 10-3 mol dm-3 and give your answer to the appropriate number of decimal places. 

Kw at 298 = 1.00 x 10-14 mol2 dm-6.

Did this page help you?

4a3 marks

This question is about buffer solutions.

Acidic buffer solutions are made of a weak acid and its salt. pH calculations of buffer solutions can be conducted using the same equation used for weak acids:

Kabegin mathsize 14px style fraction numerator left square bracket straight H to the power of plus right square bracket left square bracket straight A to the power of minus right square bracket over denominator left square bracket HA right square bracket end fraction end style

State the assumptions made when using this equation for buffer solutions.

4b1 mark

Suggest a salt that could be used to form a buffer solution with propanoic acid, CH3CH2COOH.

4c4 marks

A buffer solution contains a 0.15 mol dm-3 concentration of propanoic acid and a propanoate salt with a concentration of [A-] = 0.30 mol dm-3. 

At 298 K the value of Ka for propanoic acid is 1.35 × 10–5 mol dm–3 

i)
Calculate the concentration of [H+] in this buffer solution at 298 K. Give your answer to 2 decimal places.
[3]
ii)
Calculate the pH of the buffer solution to 2 decimal places.

 

[1]
4d2 marks

Buffer solutions can be tailored to a specific pH by 'coarse-tuning' by changing the acid used, and 'fine-tuning' by altering the ratio of [HA]: [A-]. 

Predict and explain the effect on the pH of the buffer solution by increasing the concentration of the salt only.

Did this page help you?

5a3 marks

This question is about titration curves.

Sketch the titration curve expected when a strong base is added to a strong acid, where the solutions are of similar concentrations.

5b2 marks

Which indicator would be most suitable for the titration of a weak base with a strong acid, shown in the titration curve below, and why?

weak-base-strong-acid-titration-ocr-a2-sq-5-3-a5b

26346a8a-4b71-414d-9c51-1db232f4677e

5c
Sme Calculator
2 marks

Titration curves are useful to find out the equivalence and half equivalence points, allowing Ka to be calculated.

weak-base-strong-acid-titration-ocr-a2-sq-5-3-a5b

i)
Determine the equivalence point of the above titration, in cm3 of acid added.

[1]

ii)
Determine the pH at the half-equivalence point.

[1]

5d3 marks

The indicator used is a weak acid represented by HIn. In solution this can react in the following manner:

HIn (aq) + H2O (l) rightwards harpoon over leftwards harpoon H3O+ (aq) + In- (aq)


Explain why the colour of the indicator changes between the half equivalence point where the solution is basic, and the end of the neutralisation in this reaction, where the solution is acidic.

Did this page help you?

1a3 marks

This question is about Brønsted-Lowry acids and bases.

i)

Give the meaning of the term Brønsted-Lowry base.

ii)

Explain the term weak acid.

1b2 marks

When an acid and a base react they produce a conjugate base and a conjugate acid.

acid + base  ⇋  conjugate base + conjugate acid

Write an equation to show how hydrochloric acid behaves as a strong acid when it reacts with water, and state the role of water in this reaction.

1c
Sme Calculator
2 marks

The pH of an acid or base can be calculated using the concentration of hydrogen ions. 

i)

Calculate the pH of a 0.2 mol dm-3 solution of HCl at 298K. 

ii)

Calculate the hydrogen ion concentration of a solution of nitric acid which has a pH of 3. 

1d2 marks

Acids can be classed as monobasic, dibasic and tribasic.

Give an example of a diprotic acid and explain the term dibasic.

1e
Sme Calculator
2 marks

A student measured 50.0 cm3 of 0.025 mol dm−3 hydrochloric acid into a beaker. The student then added 100 cm3 of distilled water into the beaker.

Calculate the pH of the solution formed after 100 cm3 of distilled water is added to the beaker. Give your answer to 3 significant figures.

Did this page help you?

2a2 marks

At 298K, water molecules dissociate into equal quantities of ions, and the pH is 7. 

i)

Write an equation to show the dissociation of water. 

ii)
At 313 K, the pH of water is 6.77. Explain why water is neutral at a pH of 6.77 at this temperature.
2b5 marks

The ionic product of water, Kw, can be used to find the pH of a strong base. Changing the temperature will affect the value for Kw.

i)

Give the expression and units for the ionic product of water, Kw.

ii)

As temperature is increased, the value for Kw  also increases. Explain why.

2c2 marks

At 40 ℃ the Kw of pure water is 2.916 x 10-14 mol2 dm-3

Calculate the pH of pure water. Give your answer to 3 significant figures.

2d
Sme Calculator
2 marks

Strong bases fully ionise in water, as shown by the equation of dissociation of sodium hydroxide:

NaOH (aq) →  Na+ (aq) + OH- (aq)

At 298K, Kw is 1 x 10-14 mol2 dm-6

Calculate the pH of a 0.05 mol dm-3 solution of NaOH at 298 K. Give your answer to 3 significant figures.
       
2e2 marks

The ionic product of water, Kw is an equilibrium constant.

However, the expression for Kw does not include the concentration of water. Explain why.

Did this page help you?

3a1 mark

Weak acids don’t fully ionise in solution. The equilibrium constant, Ka is used to determine the hydrogen ion concentration.

Write an expression for the acid dissociation constant, Ka for the acid HA. 

3b
Sme Calculator
4 marks

A sample of 0.01 mol dm-3 butanoic acid has a Ka value of 1.51 x 10-5 mol dm-3.

i)

Write an expression for the acid dissociation constant, Ka, for butanoic acid. 

ii)

Calculate the pH of the 0.01 mol dm-3 butanoic acid. Give your answer to two decimal places.

3c
Sme Calculator
4 marks

The pH of a 0.15 mol dm-3 solution of HCN is 5.08 at 298K. 

Determine the value of Ka for HCN at 298 K. 

Give your answer to two decimal place and state its units. 

3d3 marks

The value of Ka can be used to determine the strength of an acid. The lower the value for Ka the weaker the acid is. Hydrofluoric acid has a Ka value of 5.5 x 10-4. In comparison, the Ka value for ethanoic acid is 1.7 x 10-5.

Considering the expression for Ka, explain why the value of Ka is larger in hydrofluoric acid than in ethanoic acid.

3e
Sme Calculator
3 marks

Formic acid is a weak monoprotic acid. At 298K the pH of 0.025 mol dm-3 formic acid is 5.4.

Calculate the pKa of formic acid at 298 K. Give your answer to three significant figures.

Did this page help you?

4a3 marks

A student titrated 0.10 mol dm-3 acid into a conical flask containing 25.0 cm3 of 0.1 mol dm-3 of a base, recording the pH with each addition of acid.

The student repeated the procedure using different combinations of acids and bases. 

1-5

Identify which curve shown above, is the acid-base combination for the following: 

i)
Ammonia and ethanoic acid.

ii)
Ammonia and nitric acid.

iii)
Sodium hydroxide and propanoic acid.
4b3 marks

Identify which indicator given in the table would be most suitable for curve Y. Justify your answer. 

26346a8a-4b71-414d-9c51-1db232f4677e

4c
Sme Calculator
3 marks

The pH curve shown below was obtained when a 0.150 mol dm–3 solution of sodium hydroxide was added to 25.0 cm3 of an aqueous solution of ethanoic acid.

The half equivalence point is where half of the volume of sodium hydroxide required for neutralisation has been added to the ethanoic acid.

OCR A2 SQ 5.3 Q4

i)

Label the graph with an X to show the position of the half equivalence point.

ii)

When half of the ethanoic acid solution has been neutralised, the remaining ethanoic acid concentration is equal to that of the sodium ethanoate that had formed. The Ka =1.75 x 10-5 mol dm-3. Calculate the pH at this point. Give your answer to two decimal places.

4d
Sme Calculator
4 marks

The student plotted a graph of the results of the reaction between butanoic acid and potassium hydroxide. The results are shown in the pH curve below.

Use the curve to determine the value of Ka for butanoic acid at 298K. State the units for Ka

3-4

Did this page help you?

5a1 mark

This question is about buffers.

Give the meaning of the term buffer solution.

5b2 marks

Buffers can be acidic but they can also be basic. This is determined by the reactants which are combined to create the buffer

i)
Describe how an acidic buffer is made.

ii)
State the key feature which makes a buffer acidic. 
5c4 marks

Ethanoic acid is a weak acid. Hydrogen carbonate ions act as a weak acid if they are in an aqueous solution.

i)

Write equations for each of these weak acids at equilibrium. 

ii)

A solution was made up containing sodium hydrogen carbonate and sodium carbonate. Explain how this solution would act as a buffer if a small amount of acid was added to it.

5d2 marks

Explain how the solution of ethanoic acid works as a buffer when small amounts of alkali are added.

5e
Sme Calculator
4 marks

A buffer solution contains 0.10 mol dm-3 concentration of methanoic acid and a 0.20 mol dm-3 concentration of sodium methanoate. The values of Ka for methanoic acid is 1.80 × 10–5 mol dm–3Calculate the pH of this buffer solution at 298 K. Give your answer to 2 decimal places.

Did this page help you?

6a
Sme Calculator
4 marks

Propanoic acid has an acid dissociation constant value, Ka, of 1.34 x 10-5 mol dm−3 at 298K.

A buffer solution containing propanoic acid and sodium propanoate was prepared. 

The concentration of the propanoate ions in the buffer solution was 0.177 mol dm−3.  The pH of the buffer solution was 4.01. 

i)

Give the expression for the acid dissociation constant Ka for propanoic acid.

ii)

Calculate the concentration of the propanoic acid in the buffer solution.

Give your answer to two decimal places.

6b2 marks

This question is about buffers.

i)

Explain the term basic buffer solution.

ii)
Suggest why buffers are used in the cosmetics industry. 
6c2 marks

When we exercise, chemical changes occur which can cause our blood pH to drop. If the pH drops below 7.4 a condition called acidosis occurs. This can be very dangerous as many chemical reactions involve proteins which work at pH 7.4. The most important buffer for maintaining acid-base balance in the blood is the carbonic acid, H2CO3, hydrogencarbonate, HCO3- buffer.

i)
Write a balanced equation to show the dissociation of carbonic acid, acting as a buffer solution.

ii)
Explain how the carbonic acid-hydrogencarbonate buffer maintains blood pH at 7.4 when we exercise. Use your answer to part (i).
6d2 marks

Much of the atmospheric carbon dioxide we produce is absorbed by dissolving into the oceans, forming carbonic acid. An equilibrium is set up within the oceans using the same buffer solution as in the body, described in part (b). 

In this buffer solution there is an almost unlimited amount of hydrogen carbonate ions and the carbonic acid available has a high concentration.

Using your answer to (b) part (i), suggest the changes which would lead to more CO2 dissolving into the oceans. Explain your answer.

Did this page help you?

1a
Sme Calculator
4 marks

Lithium hydroxide monohydrate is used in the production of cathodes for lithium-ion batteries

A 4.2 g sample of lithium hydroxide monohydrate, LiOH.H2O(s), is added to 250 cm3 of water. State the pH of the solution at 298 K. Give your answer to 1 decimal place. 

(Kw = 1.00 x 10-14 mol2 dm-6 at 298 K)

1b
Sme Calculator
5 marks

40.00 cm3 of 0.01 mol dm-3 hydrochloric acid, HCl (aq), is added to 60.00 cm3 of the of lithium hydroxide monohydrate solution given in part (a). State the new pH of this solution
Give your answer to 2 decimal places. 

1c
Sme Calculator
6 marks

The value of Kw is 5.476 x 10-14 mol dm-3 at 323K whilst at 373K the value of Kw changes to 51.3 x 10-14.

i)
Calculate the ratio of the concentrations of H+ ions at these two temperatures.

ii)
Using your answer to part (c) (i), calculate the pH difference between water at these two temperatures.
1d
Sme Calculator
3 marks

6.00 cm3 of 0.30 mol dm-3 potassium hydroxide solution is added to 994 cm3 of pure water at 50°C. Using the values for Kw in part (c), calculate the pH of the solution to 2 decimal places. 

Did this page help you?

2a4 marks

This question is about acid-base reactions.

Calculate the volume of water in cm3 required to raise the pH of 35.0 cm3 of hydrochloric acid from 0.70 to 0.90 at 298 K. 

2b
Sme Calculator
2 marks

After a neutralisation reaction between sodium hydroxide and hydrochloric acid, a solution of sodium chloride is evaporated and 2.85 g of pure sodium chloride is produced. 

Determine the volume, in cm3, of 0.20 mol dm-3 of hydrochloric acid required in the reaction to produce this mass of sodium chloride. 

2c
Sme Calculator
5 marks

44.00 cm3 of 0.20 mol dm-3 hydrochloric acid is added to 40.00 cm3 of 0.50 mol dm-3 sodium hydroxide. Calculate the pH of the resulting solution at 298 K. Give your answer to 2 decimal places.  

(Kw = 1.00 x 10-14 mol2 dm-6 at 298 K)

2d
Sme Calculator
5 marks

25.00 cm3 of 0.20 mol dm-3 barium hydroxide solution, Ba(OH)2 (aq), is added to the 25.00 cm3 of 0.20 mol dm-3 of hydrochloric acid. What is the pH of the new solution at 298 K? 

Give your answer to 2 decimal places.  

(Kw = 1.00 x 10-14 mol2 dm-6 at 298 K)

Did this page help you?

3a2 marks

Chemicals in the blood resist changes in pH when hydroxide ions enter the bloodstream.

Explain, using equations, how this occurs.

3b1 mark

A buffer solution contains a mixture of ethanoic acid and its salt. A small amount of nitric acid is added to the buffer. 

Write an equation, including state symbols, showing how this buffer can resist the change in pH.

3c
Sme Calculator
2 marks

Determine the pH of the buffer solution which is 0.050 mol dm-3 of ethanoic acid and 0.050 dm-3 of sodium ethanoate. You must show working and give your answer to 2 decimal places. 

(The pKa of ethanoic acid is 4.77)

3d
Sme Calculator
3 marks

Calculate the concentration of methanoic acid used in a buffer which has a pH of 3.45 and a methanoate salt concentration of 0.149 mol dm-3. Give your answer to 3 significant figures.

(Ka of methanoic acid = 1.8 x 10-4 mol dm-3)

Did this page help you?

4a4 marks

This question is about organic acids.

0.3825 g of an organic monobasic aromatic carboxylic acid containing only carbon, hydrogen and oxygen were dissolved in ethanol. A few drops of the indicator were added to the mixture titrated with 0.100 mol dm-3 sodium hydroxide.

It took 25.50 cm3 of alkali to obtain the first permanent colour change.

Suggest a structure for the acid.

4b2 marks

Table 1 shows a few common indicators and the pH ranges of their colour changes.

Suggest a suitable indicator from the table below for the procedure outlined in part (a) and explain your answer.

Table 1

Indicator Methyl orange Bromophenol blue Phenolphthalein
pH range of colour change 3.1 - 4.4 3.4 - 4.6 8.3 - 10.0

4c
Sme Calculator
4 marks

The value of the acid dissociation constant, Ka, of benzoic acid is 6.3 x 10-5 mol dm-3 at 298K.

Calculate the pH of the 0.50 g dissolved in 250 cm3 of water. Give your answer to 2 decimal places. 

4d5 marks

Calculate the pH of the solution formed when 0.060 g of sodium hydroxide is added to 500.00 cm3 of 0.005 mol dm-3 of benzoic acid. Give your answer to 2 decimal places.

Did this page help you?

5a
Sme Calculator
5 marks

This question is about buffer solutions

What is the pH of a buffer solution made by dissolving 0.275 g of benzoic acid and 0.525 g of sodium benzoate in 250 cm3 of water? Give your answer to 2 decimal places. 

(Ka of benzoic acid = 6.3 x 10-5 mol dm-3)

5b
Sme Calculator
3 marks

Calculate the pH of a buffer solution made by mixing together 130 cm3 of 0.2 mol dm-3 ethanoic acid and 85 cm3 of 0.45 mol dm-3 sodium ethanoate. Give your answer to 2 decimal places.

(Ka of ethanoic acid = 1.74 x 10-5 mol dm-3)

5c
Sme Calculator
5 marks

Calculate the new pH of the buffer solution given in part (b) if 1.00 cm3 of 1.00 mol dm-3 sodium hydroxide is added. Comment on the pH value after the addition of sodium

5d2 marks

Buffers are solutions that can resist changes in pH if a small volume of acid or base is added.

i)
Write an equation to show the action of the buffer given in part (b) if a small volume of acid was added.

ii)
Write an equation to show the action of the buffer given in part (b) if a small volume of base was added.

Did this page help you?

6a3 marks

This question is about pH titration curves.

Figure 1 shows a sketch of a graph pH curve when ammonia, NH3 (aq), is added to a hydrochloric acid, HCl (aq). 

20.00 cm3 of 0.5 mol dm-3 HCl (aq) was required to neutralise 38.65 cm3 of NH3 (aq). 

Figure 1

ph-curve

i)
Write two equations to show how hydrochloric acid and ammonia can act as a Brønsted-Lowry acid and base respectively.
[1]

ii)
Suggest a value for the pH at point 2 on the curve and explain your answer.
[1]

iii)
Calculate the pH of the solution at point 1. Give your answer to 2 decimal places.

[1]

6b3 marks

The 'half volume method' can be used to find the Ka of a weak acid as pKa = pH at the half equivalence point. This method was carried out as follows:

Step 1 15.00 cm3 of a weak acid was added to a conical flask with a few drops of phenolphthalein indicator.

Step 2 This solution was then titrated against NaOH (aq) until the endpoint.

Step 3 The volume of NaOH (aq) required to reach the endpoint was noted.

Step 4 The titration was then repeated without an indicator and adding only half the volume of NaOH (aq) required to reach the endpoint.

Step 5 The pH of the solution was measured using a pH probe.

The student’s graph is shown below in Figure 2.

Figure 2

half-volume-method

Using Figure 2, calculate the value for Ka of the acid. Give your answer to 3 significant figures.

6c3 marks

The complete neutralisation of sodium carbonate with hydrochloric acid happens in two separate stages. In the first stage, sodium hydrogencarbonate is produced. This then goes on to react further with hydrochloric acid in the second stage.

Figure 3 shows the change in pH during these two stages.

Explain using equations the two reactions in this double endpoint titration.

Figure 3

ph-curve-2

Did this page help you?