Electrode Potentials (OCR A Level Chemistry A): Revision Note
Standard Electrode Potential
Standard electrode potential
The position of equilibrium and therefore the electrode potential depends on factors such as:
Temperature
Pressure of gases
Concentration of reagents
So, to be able to compare the electrode potentials of different species, they all have to be measured against a common reference or standard
Standard conditions also have to be used when comparing electrode potentials
These standard conditions are:
Ion concentration of 1.00 mol dm-3
A temperature of 298 K
A pressure of 100 kPa
Standard measurements are made using a high resistance voltmeter so that no current flows and the maximum potential difference is achieved
The electrode potentials are measured relative to a standard hydrogen electrode
The standard hydrogen electrode is given a value of 0.00 V, and all other electrode potentials are compared to this standard
This means that the electrode potentials are always referred to as a standard electrode potential (Eθ)
The standard electrode potential (Eθ) is the potential difference ( sometimes called voltage) produced when a standard half-cell is connected to a standard hydrogen cell under standard conditions
For example, the standard electrode potential of bromine suggests that relative to the hydrogen half-cell it is more likely to get reduced, as it has a more positive Eθ value
Br2(l) + 2e– ⇌ 2Br–(aq) Eθ = +1.09 V
2H+(aq) + 2e– ⇌ H2(g) Eθ = 0.00 V
The standard electrode potential of sodium, on the other hand, suggests that relative to the hydrogen half-cell it is less likely to get reduced as it has a more negative Eθ value
Na+ (aq) + e– ⇌ Na(s) Eθ = -2.71 V
2H+ (aq) + 2e– ⇌ H2(g) Eθ = 0.00 V
Electrochemical Cells
The standard hydrogen electrode is a half-cell used as a reference electrode and consists of:
Hydrogen gas in equilibrium with H+ ions of concentration 1.00 mol dm-3 (at 100 kPa)
2H+ (aq) + 2e- ⇌ H2 (g)
An inert platinum electrode that is in contact with the hydrogen gas and H+ ions
When the standard hydrogen electrode is connected to another half-cell, the standard electrode potential of that half-cell can be read off a high resistance voltmeter
The standard electrode potential of a half-cell can be determined by connecting it to a standard hydrogen electrode
There are three different types of half-cells that can be connected to a standard hydrogen electrode
A metal / metal ion half-cell
A non-metal / non-metal ion half-cell
An ion / ion half-cell (the ions are in different oxidation states)
Metal / metal-ion half-cell
Example of a metal / metal ion half-cell connected to a standard hydrogen electrode
An example of a metal/metal ion half-cell is the Ag+/ Ag half-cell
Ag is the metal
Ag+ is the metal ion
This half-cell is connected to a standard hydrogen electrode and the two half-equations are:
Ag+ (aq) + e- ⇌ Ag (s) Eꝋ = + 0.80 V
2H+ (aq) + 2e- ⇌ H2 (g) Eꝋ = 0.00 V
Since the Ag+/ Ag half-cell has a more positive Eꝋ value, this is the positive pole and the H+/H2 half-cell is the negative pole
The standard cell potential (Ecellꝋ) is Ecellꝋ = (+ 0.80) - (0.00) = + 0.80 V
The Ag+ ions are more likely to get reduced than the H+ ions as it has a greater Eꝋ value
Reduction occurs at the positive electrode
Oxidation occurs at the negative electrode
Non-metal / non-metal ion half-cell
In a non-metal / non-metal ion half-cell, platinum wire or foil is used as an electrode to make electrical contact with the solution
Like graphite, platinum is inert and does not take part in the reaction
The redox equilibrium is established on the platinum surface
An example of a non-metal / non-metal ion is the Br2 / Br- half-cell
Br2 is the non-metal
Br- is the non-metal ion
The half-cell is connected to a standard hydrogen electrode and the two half-equations are:
Br2 (aq) + 2e- ⇌ 2Br- (aq) Eꝋ = +1.09 V
2H+ (aq) + 2e- ⇌ H2 (g) Eꝋ = 0.00 V
The Br2 / Br- half-cell is the positive pole and the H+ / H2 is the negative pole
The Ecellꝋ is: Ecellꝋ = (+ 1.09) - (0.00) = + 1.09 V
The Br2 molecules are more likely to get reduced than H+ as they have a greater Eꝋ value
Example of a non-metal / non-metal ion half-cell connected to a standard hydrogen electrode
Ion / Ion half-cell
A platinum electrode is again used to form a half-cell of ions that are in different oxidation states
An example of such a half-cell is the MnO4- / Mn2+ half-cell
MnO4- is an ion containing Mn with oxidation state +7
The Mn2+ ion contains Mn with oxidation state +2
This half-cell is connected to a standard hydrogen electrode and the two half-equations are:
MnO4- (aq) + 8H+ (aq) + 5e- ⇌ Mn2+ (aq) + 4H2O (l) Eꝋ = +1.52 V
2H+ (aq) + 2e- ⇌ H2 (g) Eꝋ = 0.00 V
The H+ ions are also present in the half-cell as they are required to convert MnO4- into Mn2+ ions
The MnO4- / Mn2+ half-cell is the positive pole and the H+ / H2 is the negative pole
The Ecellꝋ is Ecellꝋ = (+ 1.52) - (0.00) = + 1.52 V
Ions in solution half cell
Conventional Representation of Cells
Chemists use a type of shorthand convention to represent electrochemical cells
In this convention:
A solid vertical (or slanted) line shows a phase boundary, that is an interface between a solid and a solution
A double vertical line (sometimes shown as dashed vertical lines) represents a salt bridge
A salt bridge has mobile ions that complete the circuit
Potassium chloride and potassium nitrate are commonly used to make the salt bridge as chlorides and nitrates are usually soluble
This should ensure that no precipitates form which can affect the equilibrium position of the half cells
The substance with the highest oxidation state in each half cell is drawn next to the salt bridge
The cell potential difference is shown with the polarity of the right hand electrode
The cell convention for the zinc and copper cell would be
Zn (s)∣Zn2+ (aq) ∥Cu2+ (aq)∣Cu (s) E cell = +1.10 V
This tells us the copper half cell is more positive than the zinc half cell, so that electrons would flow from the zinc to the copper
The same cell can be written as:
Cu (s)∣Cu2+ (aq) ∥Zn2+ (aq)∣Zn (s) E cell = -1.10 V
The polarity of the right hand half cell is negative, so we can still tell that electrons flow from the zinc to the copper half cell
Worked Example
Writing a cell diagram
If you connect an aluminium electrode to a zinc electrode, the voltmeter reads 0.94V and the aluminium is the negative. Write the conventional cell diagram to the reaction.
Answer
Al (s)∣Al3+ (aq) ∥ Zn2+ (aq)∣Zn (s) E cell = +0.94 V
It is also acceptable to include phase boundaries on the outside of cells as well:
∣ Al (s)∣Al3+ (aq) ∥ Zn2+ (aq)∣Zn (s) ∣ E cell = +0.94 V
Examiner Tips and Tricks
Writing the cell representation is not a specific requirement of the syllabus, however questions will sometimes use cell representations to present information so it is useful to know what a cell representation is.
Students often confuse the redox processes that take place in electrochemical cells.
Oxidation takes place at the negative electrode.
Reduction takes place at the positive electrode.
Remember, oxidation is the loss of electrons, so you are losing electrons at the negative.
∣ Al (s)∣Al3+ (aq) ∥Zn2+ (aq)∣Zn (s) ∣ E cell = +0.94 V
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