Enthalpy of Solution & Hydration (OCR A Level Chemistry A): Revision Note
Enthalpy of Solution & Hydration
Enthalpy of solution
The standard enthalpy change of solution (ΔHsol) is the enthalpy change when 1 mole of an ionic substance dissolves in sufficient water to form an infinitely dilute solution
The symbol (aq) is used to show that the solid is dissolved in sufficient water
For example, the enthalpy changes of solution for potassium chloride are described by the following equations:
KCl (s) + aq → KCl (aq)
OR
KCl (s) + aq → K+(aq) + Cl-(aq)
ΔHsolꝋ can be exothermic (negative) or endothermic (positive)
Enthalpy of hydration
The standard enthalpy change of hydration (ΔHhyd) is the enthalpy change when 1 mole of a specified gaseous ion dissolves in sufficient water to form an infinitely dilute solution
For example, the enthalpy change of hydration for magnesium ions is described by the following equation:
Mg2+(g) + aq → Mg2+(aq)
Hydration enthalpies are the measure of the energy that is released when there is an attraction formed between the ions and water molecules
Hydration enthalpies are exothermic
When an ionic solid dissolves in water, positive and negative ions are formed
Water is a polar molecule with a δ- oxygen (O) atom and δ+ hydrogen (H) atoms which will form ion-dipole attractions with the ions present in the solution
The oxygen atom in water will be attracted to the positive ions and the hydrogen atoms will be attracted to the negative ions
![Chemical Energetics - Ion-Dipole Bonds, downloadable AS & A Level Chemistry revision notes](https://cdn.savemyexams.com/cdn-cgi/image/f=auto,width=3840/https://cdn.savemyexams.com/uploads/2021/01/5.1-Chemical-Energetics-Ion-Dipole-Bonds.png)
The polar water molecules will form ion-dipole bonds with the ions in solution causing the ions to become hydrated
How are enthalpy of solution and hydration enthalpies related?
![Lattice enthalpy- hydration & solution enthalpies, downloadable AS & A Level Chemistry revision notes](https://cdn.savemyexams.com/cdn-cgi/image/f=auto,width=3840/https://cdn.savemyexams.com/uploads/2021/09/5.1.5-Lattice-enthalpy-hydration-solution-enthalpies-.png)
The relationship between lattice enthalpy, hydration enthalpies and enthalpy of solution
From the diagram we can see that the relationship is
Enthalpy of solution = reverse lattice enthalpy* + hydration enthalpy
The hydration enthalpy is the sum of the hydration enthalpies of each ion
If there is more than one cation or anion, such as in MgCl2, then you must multiply by the appropriate coefficient for that ion
*To be consistent with lattice formation enthalpy
Enthalpy of Solution & Hydration Calculations
Questions in this topic typically ask you to calculate the hydration enthalpy of one of the ions, given the lattice enthalpy, enthalpy of solution and hydration enthalpy of the other ion.
This can be done by constructing an appropriate energy cycle and using Hess's Law to find the unknown energy value
The energy cycle above shows that there are two routes to go from the gaseous ions to the ions in an aqueous solution:
Route 1: going from gaseous ions → ionic solid → ions in aqueous solution (this is the indirect route)
Route 2: going from gaseous ions → ions in aqueous solution (this is the direct route)
According to Hess’s law, the enthalpy change for both routes is the same, such that:
ΔHhydꝋ = ΔHlattꝋ + ΔHsolꝋ
Each ion will have its own enthalpy change of hydration, ΔHhydꝋ, which will need to be taken into account during calculations
The total ΔHhydꝋ is found by adding the ΔHhydꝋ values of both anions and cations together
Worked Example
Calculate the enthalpy of hydration of the chloride ion given the following data:
ΔHlattꝋ [KCl] = -711 kJ mol-1
ΔHsolꝋ [KCl] = +26 kJ mol-1
ΔHhydꝋ [K+] = -322 kJ mol-1
Answer
Step 1: Draw the energy cycle and make ΔHhydꝋ [Cl-] the subject of the formula:
![Worked Example -Energy Cycle KCl, downloadable AS & A Level Chemistry revision notes](https://cdn.savemyexams.com/cdn-cgi/image/f=auto,width=3840/https://cdn.savemyexams.com/uploads/2021/09/5.1.5-Worked-Example-Energy-Cycle-KCl.png)
Step 2: Substitute the values to find ΔHhyd [Cl-]
ΔHhydꝋ[Cl-] = (-711) + (+26) - (-322) = -363 kJ mol-1
Alternative Diagram
You can also draw a Born-Haber cycle as an alternative approach to the same problem
Energy level diagram:
![Chemical Energetics - Energy Level Diagram KCl (1), downloadable AS & A Level Chemistry revision notes](https://cdn.savemyexams.com/cdn-cgi/image/f=auto,width=3840/https://cdn.savemyexams.com/uploads/2021/01/5.1-Chemical-Energetics-Energy-Level-Diagram-KCl-1.png)
![Chemical Energetics - Energy Level Diagram KCl (2), downloadable AS & A Level Chemistry revision notes](https://cdn.savemyexams.com/cdn-cgi/image/f=auto,width=3840/https://cdn.savemyexams.com/uploads/2021/01/5.1-Chemical-Energetics-Energy-Level-Diagram-KCl-2.png)
Worked Example
Construct an energy cycle to calculate the ΔHhydꝋof magnesium ions in magnesium chloride, given the following data:
ΔHlattꝋ[MgCl2] = -2592 kJ mol-1
ΔHsolꝋ[MgCl2] = -55 kJ mol-1
ΔHhydꝋ[Cl-] = -363 kJ mol-1
Answer
Step 1: Draw an energy cycle:
![Worked Example - Energy Cycle MgCl2, downloadable AS & A Level Chemistry revision notes](https://cdn.savemyexams.com/cdn-cgi/image/f=auto,width=3840/https://cdn.savemyexams.com/uploads/2021/09/5.1.5-Worked-Example-Energy-Cycle-MgCl2.png)
Step 2: Substitute the values to find ΔHhydꝋ [Mg2+]
ΔHhydꝋ[Mg2+] = (-2592) + (-55) - (2 x -363) = -1921 kJ mol-1
Alternative route to find ΔHhydꝋ[Mg2+]
Here is the same solution using a Born-Haber cycle
![Chemical Energetics - Energy Level Diagram MgCl2, downloadable AS & A Level Chemistry revision notes](https://cdn.savemyexams.com/cdn-cgi/image/f=auto,width=3840/https://cdn.savemyexams.com/uploads/2021/01/5.1-Chemical-Energetics-Energy-Level-Diagram-MgCl2.png)
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