Le Chatelier’s Principle (OCR A Level Chemistry A): Revision Note
Equilibrium & Reaction Conditions
Position of the equilibrium
The position of the equilibrium refers to the relative amounts of products and reactants in an equilibrium mixture
When the position of equilibrium shifts to the left, it means the concentration of reactants increases
When the position of equilibrium shifts to the right, it means the concentration of products increases
Le Chatelier’s principle
Le Chatelier’s principle says that if a change is made to a system in dynamic equilibrium, the position of the equilibrium moves to counteract this change
The principle is used to predict changes to the position of equilibrium when there are changes in temperature, pressure or concentration
Effects of concentration
How the equilibrium shifts with concentration changes
![](https://cdn.savemyexams.com/cdn-cgi/image/f=auto,width=3840/https://cdn.savemyexams.com/uploads/2020/05/7.2-Effects-of-concentration-table.png)
Worked Example
Changes in equilibrium position
Using the reaction below:
CH3COOH (I) + C2H5OH (I) ⇌ CH3COOC2H5 (I) + H2O (I)
Explain what happens to the position of equilibrium when:
1. More CH3COOC2H5 is added
2. Some C2H5OH is removed
Using the reaction below:
Ce4+ (aq) + Fe2+ (aq) ⇌ Ce3+ (aq) + Fe3+ (aq)
Explain what happens to the position of equilibrium when
3. Water is added to the equilibrium mixture
Answer 1:
The position of the equilibrium moves to the left and more ethanoic acid and ethanol are formed
The reaction moves in this direction to oppose the effect of added ethyl ethanoate, so the ethyl ethanoate decreases in concentration
Answer 2:
The position of the equilibrium moves to the left and more ethanoic acid and ethanol are formed
The reaction moves in this direction to oppose the removal of ethanol so more ethanol (and ethanoic acid) is formed from ethyl ethanoate and water
Answer 3:
There is no effect as the water dilutes all the ions equally so there is no change in the ratio of reactants to products
Effects of pressure
Changes in pressure only affect reactions where the reactants or products are gases
How the equilibrium shifts with pressure changes
![Effects of pressure table, IGCSE & GCSE Chemistry revision notes](https://cdn.savemyexams.com/cdn-cgi/image/f=auto,width=3840/https://cdn.savemyexams.com/uploads/2020/05/7.2-Effects-of-pressure-table.png)
Worked Example
Changes in pressure
Predict the effect of increasing the pressure on the following reactions:
1. N2O4 (g) ⇌ 2NO2 (g)
2. CaCO3 (s) ⇌ CaO (s) + CO2 (g)
Predict the effect of decreasing the pressure on the following reaction:
3. 2NO2 (g) ⇌ 2NO (g) + O2 (g)
Answer 1:
The equilibrium shifts to the left as there are fewer gas molecules on the left
This causes a decrease in pressure
Answer 2:
The equilibrium shifts to the left as there are no gas molecules on the left but there is CO2 on the right
This causes a decrease in pressure
Answer 3:
The equilibrium shifts to the right as there is a greater number of gas molecules on the right
This causes an increase in pressure
Effects of temperature
How the equilibrium shifts with temperature changes
![Effects of temperature table, IGCSE & GCSE Chemistry revision notes](https://cdn.savemyexams.com/cdn-cgi/image/f=auto,width=3840/https://cdn.savemyexams.com/uploads/2020/05/7.2-Effects-of-temperature-table.png)
Worked Example
Changes in temperature
Using the reaction below:
H2 (g) + CO2 (g) ⇌ H2O (g) + CO (g) ΔH = +41.2 kJ mol-1
1. Predict the effect of increasing the temperature on this reaction
Using the reaction below:
Ag2CO3 (s) ⇌ Ag2O (s) + CO2 (g)
2. Increasing the temperature increases the amount of CO2(g) at constant pressure. Is this reaction exothermic or endothermic?
Explain your answer
Answer 1:
The reaction will absorb the excess energy and since the forward reaction is endothermic, the equilibrium will shift to the right
Answer 2:
The reaction will absorb the excess energy and since this causes a shift of the equilibrium towards the right (as more CO2(g) is formed) this means that the reaction is endothermic
Equilibrium & Catalysts
Effects of catalysts
A catalyst is a substance that increases the rate of a chemical reaction (they increase the rate of the forward and reverse reaction equally)
Catalysts only cause a reaction to reach equilibrium faster
Catalysts therefore have no effect on the position of the equilibrium once this is reached
Investigating changes to the equilibrium position with concentration
The equilibrium between aqueous chromate ions, CrO42-, and dichromate ions, Cr2O72- is sensitive to changes in acid concentration
Solutions of chromate and dichromate ions have different colours so it is easy to see any shift in the equilibrium position
![3-6-chromate-dichromate-equilibrium](https://cdn.savemyexams.com/cdn-cgi/image/f=auto,width=3840/https://cdn.savemyexams.com/uploads/2022/05/3-6-chromate-dichromate-equilibrium.png)
By adding dilute sulfuric acid, we can increase the concentration of H+ (aq) in the solution
This increases the rate of the forward reaction causing the equilibrium position to shift to minimise the change in H+ (aq) concentration
This decreases the concentration of the added reactant, H+ (aq)
Equilibrium shifts to the right, making more products
Solution turns orange due to the formation of more Cr2O72- (aq)
By adding aqueous sodium hydroxide, we can decrease the concentration of H+ (aq) in the solution
The added OH-(aq) ions react with H+(aq) ions forming water
H+ (aq) + OH- (aq) → H2O (l)
This decreases the rate of the forward reaction causing the equilibrium position to shift to minimise the change in H+(aq) concentration
This decreases the concentration of reactant that has been removed, H+ (aq)
Equilibrium shifts to the left, making more H+ (aq) reactant
Solution turns yellow due to the formation of more CrO42- (aq)
Investigating changes in equilibrium position with temperature
Cobalt chloride, CoCl2, dissolves in water to form a pink solution
The dissolving process produces an equilibrium between two different coloured cobalt complexes
[Co(H2O)6]2+ (aq) + 4Cl- (aq) ⇌ [CoCl4]2- (aq) + 6H2O (l)
The forward reaction in this process is endothermic and the backward reaction is exothermic
By heating up the solution we can increase the amount of heat energy in the system
This causes the equilibrium to shift to minimise the change
Equilibrium shifts to the right favouring the endothermic reaction (ΔH is positive)
This allows the system to take heat energy in and minimise the increase in temperature
The solution turns blue as more CoCl42- (aq) is formed
Cooling down the solution removes the heat energy from the system
This again causes the equilibrium to shift to minimise the change
Equilibrium shifts to the left favouring the exothermic reaction (ΔH is negative)
This allows the system to release heat energy and minimise the decrease in temperature
The solution turns pink as more Co(H2O)62+ (aq) is formed
Operational Conditions
Equilibrium reactions are involved in some stages of large-scale production of certain chemicals
An understanding of equilibrium and Le Chatelier’s principle is therefore very important in the chemical industry
Haber process
The Haber process involves the synthesis of ammonia according to:
N2 (g) + 3H2 (g) ⇌ 2NH3 (g) ΔHr = -92 kJ mol-1
Le Chatelier’s principle is used to get the best yield of ammonia
Maximising the ammonia yield
Pressure
An increase in pressure will result in the equilibrium shifting in the direction of the fewest molecules of gas formed to reduce the pressure
In this case, the equilibrium shifts towards the right so the yield of ammonia increases
An increase in pressure will cause the particles to be closer together and therefore increasing the number of successful collisions leading to an increased reaction rate
Very high pressures are expensive to produce therefore a compromise pressure of 200 atm is chosen
Temperature
To get the maximum yield of ammonia the position of equilibrium should be shifted as far as possible to the right as possible
Since the Haber process is an exothermic reaction, according to Le Chatelier’s principle the equilibrium will shift to the right if the temperature is lowered
A decrease in temperature will decrease the energy of the surroundings so the reaction will go in the direction in which energy is released to counteract this
Since the reaction is exothermic, the equilibrium shifts to the right
However, at a low temperature the gases won’t have enough kinetic energy to collide and react and therefore equilibrium would not be reached therefore compromise temperature of 400-450 oC is used in the Haber process
A heat exchanger warms the incoming gas mixture to give molecules more kinetic energy such that the gas molecules collide more frequently increasing the likelihood of a reaction
Catalysts
In the absence of a catalyst the reaction is so slow that hardly anything happens in a reasonable time!
Adding an iron catalyst speeds up the rate of reaction
Contact process
The Contact process involves the synthesis of sulfuric acid according to:
2SO2 (g) + O2 (g) ⇌ 2SO3 (g) ΔHr = -197 kJ mol-1
Le Chatelier’s principle is used to get the best yield of sulfuric acid
Maximising the sulfuric acid yield
Pressure
An increase in pressure will result in the equilibrium shifting in the direction of the fewest molecules of gas formed to reduce the pressure
In this case, the equilibrium shifts towards the right so the yield of sulfuric acid increases
In practice, the reaction is carried out at only 1 atm
This is because Kp for this reaction is already very high meaning that the position of the equilibrium is already far over to the right
Higher pressures than 1 atm will be unnecessary and expensive
Temperature
The same principle applies to increasing the temperature in the Contact process as in the Haber process
A compromise temperature of 450 oC is used
Catalysts
The Contact process uses vanadium(V) oxide as a catalyst to increase the rate of reaction
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