Acid-base Titrations (OCR A Level Chemistry A): Revision Note
Exam code: H432
Acid-base Titrations
Volumetric analysis
Volumetric analysis determines the concentration of an unknown solution by reacting it with a solution of known concentration (a standard solution)
The most common method is a titration
This uses precise volume measurements
The two main pieces of equipment used are a volumetric pipette (or graduated pipette) and a burette
A standard solution must first be prepared carefully before the titration can be performed
Accurate apparatus is essential throughout the process to minimise uncertainty
Key apparatus
Some key pieces of apparatus used in preparing a standard solution and performing a titration include:
Beaker
Burette
Volumetric pipette
Conical flask
Volumetric flask

Making a standard solution
Chemists often need to prepare solutions with accurately known concentrations
These are called standard solutions or volumetric solutions
To ensure precision, a 3 d.p. balance and a volumetric flask are used
This helps reduce uncertainty in measurement
Method
Weigh out the solute
Use a 3 d.p. balance to accurately weigh the required mass of solid
Dissolve the solute
Transfer the solid into a beaker containing a small volume of distilled water
Stir using a glass rod until completely dissolved
Transfer to a volumetric flask
Pour the solution into a clean volumetric flask using a funnel
Rinse the beaker
Rinse the beaker and glass rod with distilled water
Add the rinsings to the volumetric flask to ensure no solute is lost
Make up to the mark
Add distilled water until the bottom of the meniscus sits exactly on the scratch mark
Stopper the flask and invert to mix thoroughly


Performing the titration
The key piece of equipment used in the titration is the burette
Burettes are usually marked to a precision of 0.10 cm3
Since they are analogue instruments, the uncertainty is recorded to half the smallest marking, i.e. ±0.05 cm3
The end point or equivalence point occurs when the two solutions have reacted completely and is shown with the use of an indicator
Method
Measure a known volume (typically 25 cm3) of one solution using a volumetric pipette
Transfer it into a conical flask
Add a few drops of indicator to the solution in the conical flask

Place the conical flask on a white tile
The white tile makes it easier to observe the colour change
Fill the burette with the second solution and record the initial volume
Slowly add the solution from the burette to the conical flask while swirling
As the end point approaches, add the solution drop by drop until the colour changes

Record the final burette volume
Repeat the titration until you obtain concordant titres
Concordant results are within 0.10 cm3 of each other
Recording and processing titration results
Record initial and final burette readings to 2 decimal places, ending in .00 or .05
This is because the precision/uncertainty of the burette is ±0.05 cm3
Calculate the titre by subtracting the initial from the final volume
The uncertainty of the titre is ±0.10 cm3
This is because two readings with 0.05 cm3 uncertainty are used to determine the titre
Discard any rough or inconsistent results
The rough titre is usually far over the end point and should be discarded
Calculate an average titre using only concordant values
Example titre table
Rough | Run 1 | Run 2 | Run 3 | |
---|---|---|---|---|
Initial (cm3) | 0.00 | 23.15 | 0.25 | 23.00 |
Final (cm3) | 23.75 | 45.95 | 23.00 | 46.10 |
Titre (cm3) | 23.75 | 22.80 | 22.75 | 23.10 |
Concordant? | ✗ | ✓ | ✓ | ✗ |
✓ = Concordant results used to calculate the average titre
Run 3 is discarded as an outlier since it is outside the concordant range
The average titre is calculated from Run 1 and Run 2 only:
= 22.775 → 22.78 cm3
Percentage uncertainties
Percentage uncertainty helps assess how significant an error is compared to the measured value
The percentage uncertainty formula is:
percentage uncertainty = x 100
Adding or subtracting measurements
When adding or subtracting quantities, add the absolute uncertainties
This applies to:
Mass measurements (initial and final)
Temperature changes
Burette readings (initial and final)
Each instrument is read twice, so uncertainties are doubled
Acid-base titration calculations
Volumes & concentrations of solutions
The concentration of a solution is the amount of solute in 1 dm³ of solution
The solute is the substance being dissolved
The solvent is the liquid doing the dissolving (usually water)
A concentrated solution contains a high amount of solute
A dilute solution contains a small amount of solute
Concentration can be expressed as:
Moles per dm3
Mass per dm3
Parts per million (ppm), often used for trace substances in environmental chemistry
Using concentration in calculations
To calculate values involving concentration, use:
concentration (mol dm-3) =
This rearranges to:
number of moles (mol) = concentration (mol dm-3) x volume (dm3)
To convert between mass and moles:
mass (g) = amount (mol) × molar mass (g mol-1)
Examiner Tips and Tricks
Don’t forget:
Convert cm3 to dm3 by dividing by 1000
Use molar mass to convert between mass and moles
Worked Example
Titration calculation
A student uses 25.0 cm3 of 0.050 mol dm-3 sodium hydroxide to neutralise 19.6 cm3 of dilute nitric acid in a titration.
Calculate the concentration of the nitric acid
Answer:
Write the balanced symbol equation
NaOH + HNO3 → NaNO3 + H2O
Calculate the amount, in moles, of sodium hydroxide:
Rearrange the equation for amount of substance (mol)
Divide the volume by 1000 to convert cm3 to dm3
amount (NaOH) = 0.025 dm3 x 0.050 mol dm-3 = 0.00125 mol
Calculate the moles of nitric acid required using the reaction’s stoichiometry:
1 mol of NaOH reacts with 1 mol of HNO3
The molar ratio is 1 : 1
So, 0.00125 moles of NaOH react with 0.00125 moles of HNO3
Calculate the concentration, in mol dm-3, of nitric acid:
concentration of HNO3 =
concentration of HNO3 =
concentration of HNO3 = 0.064 mol dm-3
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