Acid-base Titrations (OCR A Level Chemistry A): Revision Note

Exam code: H432

Philippa Platt

Written by: Philippa Platt

Reviewed by: Richard Boole

Updated on

Acid-base Titrations

Volumetric analysis

  • Volumetric analysis determines the concentration of an unknown solution by reacting it with a solution of known concentration (a standard solution)

  • The most common method is a titration

    • This uses precise volume measurements

    • The two main pieces of equipment used are a volumetric pipette (or graduated pipette) and a burette

  • A standard solution must first be prepared carefully before the titration can be performed

  • Accurate apparatus is essential throughout the process to minimise uncertainty

Key apparatus

  • Some key pieces of apparatus used in preparing a standard solution and performing a titration include:

    1. Beaker

    2. Burette

    3. Volumetric pipette

    4. Conical flask

    5. Volumetric flask

Five laboratory glassware types with blue liquid: beaker, burette, pipette with bulb, conical flask, and volumetric flask with stopper.
Key pieces of apparatus used for volumetric analysis

Making a standard solution

  • Chemists often need to prepare solutions with accurately known concentrations

    • These are called standard solutions or volumetric solutions

  • To ensure precision, a 3 d.p. balance and a volumetric flask are used

    • This helps reduce uncertainty in measurement

Method

  1. Weigh out the solute

    • Use a 3 d.p. balance to accurately weigh the required mass of solid

  2. Dissolve the solute

    • Transfer the solid into a beaker containing a small volume of distilled water

    • Stir using a glass rod until completely dissolved

  3. Transfer to a volumetric flask

    • Pour the solution into a clean volumetric flask using a funnel

  4. Rinse the beaker

    • Rinse the beaker and glass rod with distilled water

    • Add the rinsings to the volumetric flask to ensure no solute is lost

  5. Make up to the mark

    • Add distilled water until the bottom of the meniscus sits exactly on the scratch mark

    • Stopper the flask and invert to mix thoroughly

Step-by-step process: 1. Weigh a precise amount of solid. 2. Dissolve in water with glass rod in a beaker. 3. Transfer to a volumetric flask using a funnel.
Step 4, rinse beaker into flask; Step 5, fill to scratch mark and mix; labels indicate meniscus and mark.

Performing the titration

  • The key piece of equipment used in the titration is the burette

  • Burettes are usually marked to a precision of 0.10 cm3

    • Since they are analogue instruments, the uncertainty is recorded to half the smallest marking, i.e. ±0.05 cm3

  • The end point or equivalence point occurs when the two solutions have reacted completely and is shown with the use of an indicator

Method

  1. Measure a known volume (typically 25 cm3) of one solution using a volumetric pipette

  2. Transfer it into a conical flask

  3. Add a few drops of indicator to the solution in the conical flask

Diagram showing a pipette safety filler, volumetric pipette, and conical flask with blue solution and indicator drops. Labels describe each component.
  1. Place the conical flask on a white tile

    • The white tile makes it easier to observe the colour change

  2. Fill the burette with the second solution and record the initial volume

  3. Slowly add the solution from the burette to the conical flask while swirling

  4. As the end point approaches, add the solution drop by drop until the colour changes

Burette on stand above conical flask, dispensing liquid for titration, with text "The second solution is added until indicator just changes colour."
  1. Record the final burette volume

  2. Repeat the titration until you obtain concordant titres

    • Concordant results are within 0.10 cm3 of each other

Recording and processing titration results

  • Record initial and final burette readings to 2 decimal places, ending in .00 or .05

    • This is because the precision/uncertainty of the burette is ±0.05 cm3

  • Calculate the titre by subtracting the initial from the final volume

    • The uncertainty of the titre is ±0.10 cm3

    • This is because two readings with 0.05 cm3 uncertainty are used to determine the titre

  • Discard any rough or inconsistent results

    • The rough titre is usually far over the end point and should be discarded

  • Calculate an average titre using only concordant values

Example titre table

Rough

Run 1

Run 2

Run 3

Initial (cm3)

0.00

23.15

0.25

23.00

Final (cm3)

23.75

45.95

23.00

46.10

Titre (cm3)

23.75

22.80

22.75

23.10

Concordant?

  • ✓ = Concordant results used to calculate the average titre

  • Run 3 is discarded as an outlier since it is outside the concordant range

  • The average titre is calculated from Run 1 and Run 2 only:

fraction numerator 22.80 plus 22.75 over denominator 2 end fraction = 22.775 → 22.78 cm3

Percentage uncertainties

  • Percentage uncertainty helps assess how significant an error is compared to the measured value

  • The percentage uncertainty formula is:

percentage uncertainty = fraction numerator uncertainty over denominator measured space value end fraction x 100

Adding or subtracting measurements

  • When adding or subtracting quantities, add the absolute uncertainties

  • This applies to:

    • Mass measurements (initial and final)

    • Temperature changes

    • Burette readings (initial and final)

  • Each instrument is read twice, so uncertainties are doubled

Acid-base titration calculations

Volumes & concentrations of solutions

  • The concentration of a solution is the amount of solute in 1 dm³ of solution

    • The solute is the substance being dissolved

    • The solvent is the liquid doing the dissolving (usually water)

  • A concentrated solution contains a high amount of solute

    • A dilute solution contains a small amount of solute

  • Concentration can be expressed as:

    • Moles per dm3

    • Mass per dm3

    • Parts per million (ppm), often used for trace substances in environmental chemistry

Using concentration in calculations

  • To calculate values involving concentration, use:

concentration (mol dm-3) = fraction numerator number space of space moles space of space solute space left parenthesis mol right parenthesis over denominator volume space of space solution space left parenthesis dm cubed right parenthesis end fraction

  • This rearranges to:

number of moles (mol) = concentration (mol dm-3) x volume (dm3)

  • To convert between mass and moles:

mass (g) = amount (mol) × molar mass (g mol-1)

Examiner Tips and Tricks

Don’t forget:

  • Convert cm3 to dm3 by dividing by 1000

  • Use molar mass to convert between mass and moles

Worked Example

Titration calculation

A student uses 25.0 cm3 of 0.050 mol dm-3 sodium hydroxide to neutralise 19.6 cm3 of dilute nitric acid in a titration.

Calculate the concentration of the nitric acid

Answer:

  1. Write the balanced symbol equation

NaOH + HNO3  →  NaNO3  +  H2O

  1. Calculate the amount, in moles, of sodium hydroxide:

    • Rearrange the equation for amount of substance (mol)

    • Divide the volume by 1000 to convert cm3 to dm3

amount (NaOH) = 0.025 dm3 x 0.050 mol dm-3 = 0.00125 mol

  1. Calculate the moles of nitric acid required using the reaction’s stoichiometry:

    • 1 mol of NaOH reacts with 1 mol of HNO3

      • The molar ratio is 1 : 1

    • So, 0.00125 moles of NaOH react with 0.00125 moles of HNO3

  2. Calculate the concentration, in mol dm-3, of nitric acid:

concentration of HNO3 = fraction numerator amount space left parenthesis mol right parenthesis over denominator volume space left parenthesis dm cubed right parenthesis end fraction

concentration of HNO3 =fraction numerator 0.00125 over denominator 0.0196 end fraction

concentration of HNO3 = 0.064 mol dm-3

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Philippa Platt

Author: Philippa Platt

Expertise: Chemistry Content Creator

Philippa has worked as a GCSE and A level chemistry teacher and tutor for over thirteen years. She studied chemistry and sport science at Loughborough University graduating in 2007 having also completed her PGCE in science. Throughout her time as a teacher she was incharge of a boarding house for five years and coached many teams in a variety of sports. When not producing resources with the chemistry team, Philippa enjoys being active outside with her young family and is a very keen gardener

Richard Boole

Reviewer: Richard Boole

Expertise: Chemistry Content Creator

Richard has taught Chemistry for over 15 years as well as working as a science tutor, examiner, content creator and author. He wasn’t the greatest at exams and only discovered how to revise in his final year at university. That knowledge made him want to help students learn how to revise, challenge them to think about what they actually know and hopefully succeed; so here he is, happily, at SME.