Amount of Substance (OCR A Level Chemistry)

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The Mole & the Avogadro Constant

  • Amount of substance is the name given when counting the number of particles in a substance
    • Amount of substance is often seen in calculations using the letter / symbol n
    • The units for amount of substance are moles / mol
  • Amount of substance links to the Avogadro constantNA, which is the number of particles equivalent to the relative atomic, molecular or formula mass of a substance
    • The Avogadro constant applies to atoms, molecules, ions and electrons
    • The value of NA is 6.02 x 1023 g mol-1 
  • The mass of a substance with this number of particles is called a mole (mol)
    • This can be called the molar mass 
    • This is the mass of substance that contains the same number of fundamental units as exactly 12.00 g of carbon-12
  • The amount / number of moles of a substance, n, the mass of the substance, m, and the molar mass, M, are linked by the equation:
n = fraction numerator m a s s comma space m over denominator M o l a r space m a s s comma space M end fraction
  • The molar gas volume is the volume occupied by one mole of any gas, at room temperature and pressure
    • The molar volume is equal to 24 dm3 
  • One mole of any element is equal to the relative atomic mass of the element, in grams
    • For example, if you had one mole of carbon in your hand, you would be holding 6.02 x 1023 atoms of carbon which have a mass of 12.0 g
    • If you were holding one mole of water, you would be holding 6.02 x 1023 molecules of water which have a mass of 18.0 g (2 hydrogen + 1 oxygen = (2 x 1.0) + 16.0 = 18.0 g)

Worked example

Molar mass and molar gas volume

1. Calculate the molar mass of:

a. Carbon dioxide, CO2
b. Magnesium nitrate, Mg(NO3)2 
(Ar data: C = 12.0, O = 16.0, Mg = 24.3, N = 14.0)


2. Calculate the number of moles of each gas:

a. 36.0 dm3 of carbon monoxide, CO
b. 9.6 dm3 of chlorine, Cl2 

Answers

Answer 1:
The molar mass is the mass of one mole of any substance

a. Carbon dioxide, CO2 = 12.0 + (16.0 x 2) = 44.0 g

b. Magnesium nitrate, Mg(NO3)2 = 24.3 + (14.0 x 2) + (16.0 x 3 x 2) = 148.3 g

Answer 2:

One mole of any gas occupies 24.0 dm3 

a. 36.0 dm3 is 1.5 times the molar gas volume of 24.0 dm3, therefore, there are 1.5 moles of carbon monoxide, CO

b. 9.6 dm3 is 0.4 times the molar gas volume of 24.0 dm3, therefore, there are 0.4 moles of chlorine, Cl2

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Richard

Author: Richard

Expertise: Chemistry

Richard has taught Chemistry for over 15 years as well as working as a science tutor, examiner, content creator and author. He wasn’t the greatest at exams and only discovered how to revise in his final year at university. That knowledge made him want to help students learn how to revise, challenge them to think about what they actually know and hopefully succeed; so here he is, happily, at SME.