The results of the titration are shown.
Run |
Trial |
1 |
2 |
3 |
Final volume / cm3 |
17.50 |
34.10 |
17.20 |
34.10 |
Initial volume / cm3 |
0.00 |
17.30 |
0.00 |
17.20 |
Titre / cm3 |
17.50 |
|
17.20 |
|
Concordant titres (✓) |
|
|
|
|
Mean titre / cm3 |
|
|
|
|
i)
Complete the table.
(2)
ii)
The equation for the reaction between MnO4- ions from the KMnO4 and C2O42− ions from the sodium ethanedioate solution is shown.
16H+(aq) + 2MnO4−(aq) + 5C2O42−(aq) → 2Mn2+(aq) + 10CO2(g) + 8H2O(l)
Use this equation and your mean titre from (e)(i) to calculate the mass, in mg, of KMnO4 in one tablet.
Give your answer to an appropriate number of significant figures.
(5)
iii)
A textbook suggested the conical flask should be heated during the titration, as the reaction between the MnO4− ions and the C2O42− ions is slow.
Use these electrode potentials and your knowledge of homogeneous catalysis to deduce why the heating is very important at the start of the titration, but less important as the titration proceeds. Justify your answer.
You may include equations in your justification.
Electrode system |
Eθ/ V |
2CO2 (g) + 2e− ⇌ C2O42− (aq) |
+0.64 |
Mn3+ (aq) + e– ⇌ Mn2+ (aq) |
+1.49 |
MnO4− (aq) + 8H+ (aq) + 5e− ⇌ Mn2+ (aq) + 4H2O (l) |
+1.51 |
(4)