Testing for Carbonyls (Edexcel A Level Chemistry)

• Carbonyl compounds can undergo a number of reactions, some of which allow you to distinguish between an aldehyde and a ketone
  1. Oxidation - with acidified potassium dichromate(VI) solution, Tollens' reagent or Fehling's / Benedict's solution
  2. Reduction - with lithium tetrahydridoaluminate / lithium aluminium hydride in dry ether
  3. Nucleophilic addition - with HCN or acidified KCN
  4. Non-specific carbonyl testing
     1. 2,4-dinitrophenylhydrazine (2,4-DNPH) - to identify a carbonyl compound
     2. Iodoform test - iodine in the presence of alkali

Acidified potassium dichromate(VI)

• Aldehydes can be oxidised to form carboxylic acids using acidified potassium dichromate(VI) solution
  • K₂Cr₂O₇ (aq) with sulfuric acid, H₂SO₄ 

General reaction of an aldehyde with an oxidising agent

• Ketones are very resistant to being oxidised
  • This is because ketones do not have a readily available hydrogen atom, like aldehydes do
  • An extremely strong oxidising agent would be needed for oxidation of a ketone to take place
  • Such oxidation will likely oxidise a ketone in a destructive way, breaking a C-C bond
• Heating with acidified potassium dichromate can distinguish between an aldehyde and a ketone
  • The aldehyde would be oxidised, and you would see an orange to green colour change
  • The ketone would not be oxidised, so you would see no colour change

Tollens' reagent

• Tollens' reagent contains the silver(I) complex ion [Ag(NH₃)₂]⁺
• This is formed when aqueous ammonia is added to a solution of silver nitrate
  • Tollens' reagent is also known as ammoniacal silver nitrate

• If gently warmed with Tollens' reagent, an aldehyde will become oxidised
• The silver(I) complex ion solution, [Ag(NH₃)₂]⁺, is colourless
• As the aldehyde is oxidised, it causes the [Ag(NH₃)₂]⁺ ions to become reduced to solid metallic silver, Ag
• This is why a positive test result is called a "silver mirror"

Positive Test Result:

• When Tollens' reagent is gently warmed with an aldehyde, the silver mirror is formed
  • This is the positive test result

• When Tollens' reagent is gently warmed with a ketone, no silver mirror will be seen, as the ketone cannot be oxidised by Tollens' reagent, so no reaction takes place
  • This is a negative test result

The Ag⁺ ions in Tollens’ reagent are oxidising agents, oxidising the aldehyde to a carboxylic acid and getting reduced themselves to silver atoms

Fehling's Solution 

• Fehling’s solution is a solution containing copper(II) ions dissolved in sodium hydroxide, which act as the oxidising agent
  • Benedict's solution is exactly the same as Fehling's solution but the copper(II) ions are dissolved in sodium carbonate
• If an aldehyde is warmed with Fehling's solution, the aldehyde will be oxidised and a colour change will take place
• Fehling's solution is blue, because of the copper(II) complex ions present
• During the reaction, as the aldehyde is oxidised to a carboxylic acid, the blue Cu²⁺ ions are reduced to Cu⁺ ions and a brick red precipitate is formed
• The brick red precipitate is copper(I) oxide
• If a ketone is warmed with Fehling's solution, no reaction takes place as the ketone will not be oxidised, so the solution will remain blue

The copper(II) ions in Fehling’s solution are oxidising agents, oxidising the aldehyde to a carboxylic acid and getting reduced themselves to copper(I) ions in the Cu₂O precipitate

Reduction of Carbonyls

• Aldehydes are reduced to primary alcohols and ketones are reduced to secondary alcohols
• This is done with lithium tetrahydridoaluminate / lithium aluminium hydride, LiAlH₄, in dry ether
  • The LiAlH₄ generates a hydride ion nucleophile, :H^-
  • The hydride ion reduces the carbonyl group in an aldehyde or a ketone
    • When this reaction takes place, it is an example of a nucleophilic addition reaction

Reduction equation for an aldehyde

Reduction equation for a ketone

Nucleophilic addition

• Many of the reactions which carbonyl compounds undergo are nucleophilic addition reactions
• The carbonyl group -C=O, in aldehydes and ketones is polarised
• The oxygen atom is more electronegative than carbon drawing electron density towards itself
• This leaves the carbon atom slightly positively charged and the oxygen atom slightly negatively charged
• The carbonyl carbon is therefore susceptible to attack by a nucleophile, such as the cyanide ion

   

General Mechanism with an aldehyde

General Mechanism with a ketone

• In both reactions, the nucleophile (Nu) attacks the carbonyl carbon to form a negatively charged intermediate which quickly reacts with a proton

Addition of HCN to carbonyl compounds

The nucleophilic addition of hydrogen cyanide to carbonyl compounds is a two-step process, as shown below

• In step 1, the cyanide ion attacks the carbonyl carbon to form a negatively charged intermediate
• In step 2, the negatively charged oxygen atom in the reactive intermediate quickly reacts with aqueous H⁺ (either from HCN, water or dilute acid) to form 2-hydroxynitrile compounds,
  • e.g. 2-hydroxypropanenitrile
• This reaction is important in organic synthesis, because it adds a carbon atom to the chain, increasing the chain length
• The products of the reaction are hydroxynitriles
  • The nitrile group is the priority functional group so it is attached to carbon 1 and results in the suffix -nitrile
  • The hydroxyl group is not the priority functional group so the hydroxyl group is named using the hydroxy- prefix, rather than the -ol suffix

2,4-dinitrophenylhydrazine (2,4-DNPH)

• 2,4-dinitrophenylhydrazine (also known as 2,4-DNPH) is a reagent which detects the presence of carbonyl compounds (compounds with -C=O group)
• The carbonyl group of aldehydes and ketones undergoes a condensation reaction with 2,4-dinitrophenylhydrazine
  • A condensation reaction is a reaction in which two molecules join together and a small molecule (such as H₂O or HCl) is eliminated

• The product formed when 2,4-DNPH is added to a solution that contains an aldehyde or ketone is a deep-orange precipitate which can be purified by recrystallisation
• The melting point of the formed precipitate can then be measured and compared to literature values to find out which specific aldehyde or ketone had reacted with 2,4-DNPH

Ketones and aldehydes react with 2,4-DNPH in a condensation reaction

The test tube on the left shows a negative 2,4-DNPH test and the tube on the right shows a positive test

Iodoform test

• Tri-iodomethane (also called iodoform) forms a yellow precipitate with methyl ketones
  • Methyl ketones are compounds that have a CH₃CO-group
  • Ethanal also contains a CH₃CO- group and therefore also forms a yellow precipitate with iodoform

• The reagent is heated with an alkaline solution of iodine
• This reaction involves a halogenation and hydrolysis step
  • In the halogenation step, all three H-atoms in the -CH₃ (methyl) group are replaced with iodine atoms, forming a -CI₃ group
  • The intermediate compound is hydrolysed by an alkaline solution to form a sodium salt (RCO₂^- Na⁺) and a yellow precipitate of CHI₃

The reaction of ethanal with iodoform results in the formation of a yellow CHI₃ precipitate

Alcohols and the iodoform test

• If an alcohol contains a R-CH(OH)-CH₃ group it will also produce a yellow precipitate in this test
  • These include all methyl secondary alcohols (such as hexan-2-ol) and the primary alcohol ethanol 
• Iodine in sodium hydroxide reacts to form iodate(I) ions which will oxidise the secondary alcohols to ketones