Infrared (IR) Spectroscopy (Edexcel A Level Chemistry): Revision Note
Interpreting an IR Spectrum
Infrared (IR) spectroscopy is a technique used to identify compounds based on changes in vibrations of atoms when they absorb IR of certain frequencies
A spectrophotometer irradiates the sample with electromagnetic waves in the infrared region and then detects the intensity of the wavelength of IR radiation which goes through the sample
All organic molecules absorb IR radiation and depending on which energies of radiation are absorbed, bonds between atoms will vibrate by stretching, bending and twisting
The molecules will only vibrate at a specific frequency
The resonance frequency is the specific frequency at which the molecules will vibrate to stimulate larger vibrations
Depending on the rest of the molecule, each vibration will absorb specific wavelengths of IR radiation which are also shown as the reciprocal of the wavelength
This unit is called the wavenumber (cm-1)
Particular absorbance have characteristic widths (broad or sharp) and intensities (strong or weak)
For example, hydrogen bonds cause the O-H bonds in alcohols and carboxylic acids to be broad whereas the C-O bond in carbonyl (C=O) groups have a strong, sharp absorbance peak
The energies absorbed by different functional groups are given as a range and an unknown compound can be identified by comparing its IR spectrum to the IR spectrum of a known compound
Bond | Functional groups containing the bond | Characteristic infrared absorption range Wavenumber (cm-1) |
---|---|---|
C–H (stretching) | Alkane Alkene Alkyne Arene Aldehyde | 2962 - 2853 3095 - 3010 3300 3030 2900-2820 and 2775 - 2700 |
C–H (bending) | Alkane Arene (5 adjacent H) Arene (4 adjacent H) Arene (3 adjacent H) Arene (2 adjacent H) Arene (1 adjacent H) | 1485 - 1365 750 and 700 750 780 830 880 |
N–H (stretching) | Amine Amide | 3500 - 3300 3500 - 3140 |
O–H (stretching) | Alcohols and phenols Carboxylic acids | 3750 - 3200 3300 - 2500 |
C=C (stretching) | Isolated alkene Arene | 1669 - 1645 1600, 1580, 1500, 1450 |
C=O (stretching) | Aldehydes, saturated alkyl Ketones, alkyl Ketones, aryl Carboxylic acids, alkyl Carboxylic acids, aryl Carboxylic acids, anhydrides Acyl halides, chlorides Acyl halides, bromides Esters, saturated Amides | 1740 - 1720 1720 - 1700 1700 - 1680 1725 - 1700 1700 - 1680 1850 - 1800 and 1790 - 1740 1795 1810 1750 - 1735 1700 - 1630 |
C | Nitrile | 2260 - 2215 |
C | Alkyne | 2260 - 2100 |
Worked Example
Analysing IR Spectra
Look at the two infrared spectra below and determine which one corresponds to propanone and which one to propan-2-ol

Answer
IR spectrum A is propanone and spectrum B is propan-2-ol.
In IR spectrum A the presence of a strong, sharp absorption around 1710 cm-1 corresponds to the characteristic C=O, carbonyl, group in a ketone.
In spectrum B the presence of a strong, broad absorption around 3200-3500 cm-1 suggests that there is an alcohol group present, which corresponds to the -OH group in propan-2-ol.
You've read 0 of your 5 free revision notes this week
Sign up now. It’s free!
Did this page help you?