Copper(II) chloride can be produced by the reaction of hydrochloric acid with different copper(II) compounds.
i) Suggest why the reaction of copper with hydrochloric acid is not used to form copper(II) chloride.
[1]
ii) Complete Table 1.1 by writing the chemical equation for the formation of copper(II) chloride using hydrochloric acid and the copper(II) compounds.
Table 1.1
Copper(II) compound | Chemical equation |
Copper(II) oxide, | .................................................................................................... |
Copper(II) hydroxide, | .................................................................................................... |
Copper(II) carbonate, | .................................................................................................... |
[3]
11.93 g of copper(II) oxide is reacted with 50 cm3 of 2.0 mol dm-3 hydrochloric acid.
i) Calculate the number of moles of copper(II) oxide and hydrochloric acid.
[2]
ii) Explain which chemical is the limiting reagent.
[1]
22.43 g of copper(II) hydroxide reacts with hydrochloric acid to form 23.63 g of copper(II) chloride.
Complete Table 4.2 to calculate the percentage yield of this reaction.
Table 4.2
Relative formula mass of copper(II) hydroxide | ........................................ |
Moles of copper(II) hydroxide | ........................................ |
Relative formula mass of copper(II) chloride | ........................................ |
Theoretical yield of copper(II) chloride | ........................................ |
Percentage yield of copper(II) chloride | ........................................ |
22.23 g of copper(II) carbonate reacts with hydrochloric acid at room temperature and pressure. One of the products is a gas.
You should use your answer to part (a)(ii) to help answer this question.
Calculate the volume, in cm3, of the gas produced.
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