Half-Life (CIE A Level Chemistry)

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First Order Reaction Half-life

  • The half-life of a first-order reaction is independent of the concentration of reactants
    • This means that despite the concentrations of the reactants decreasing during the reaction
    • The amount of time taken for the concentrations of the reactants to halve will remain the same throughout the reaction
    • The graph is a straight line going downwards
  • The rearrangement of the methyl group (CH3) in ethanenitrile (CH3CN) is an example of a first-order reaction with rate equation rate = k [CH3CN]

Rearrangement of the CH3 group in CH3CN

Reaction Kinetics - Rearrangement of Methyl Group, downloadable AS & A Level Chemistry revision notes

CH3CN (g) → CH3NC (g)

  • Experimental data on the changes in concentration over time suggests that the half-life is constant
    • Even if the half-lives are slightly different from each other, they can still be considered to remain constant
  • This means that no matter what the original concentration of the CH3CN is, the half-life will always be around 10.0 minutes

Half-life table

Change in [CH3CN] (mol dm-3) Half-life (minutes)
8.00 - 4.00 10.0
4.00 - 2.00 9.50
2.00 - 1.00 9.25

Graph of  [CH3CN] over time

Reaction Kinetics - Half-Life First-Order, downloadable AS & A Level Chemistry revision notes

Since this is a first-order reaction, the time taken for the concentration to halve remains constant

Worked example

Using the half-life of first-order reactions in calculations

The change in concentration of a reactant over time is recorded in the following table:

Time 
(s)
0 200 400 600 800 1000 1200 1400 1600

[reactant] x10-4
(mol dm-3)

5.8 4.4 3.2 2.5 1.7 1.2 0.8 0.5 0.3
  1. Draw a graph of concentration against time for these results.
  2. Determine the first and second half-lives and hence determine the order of the reaction.

Answer

  1. Draw a graph of concentration against time for these results.
  2. Determine the first and second half-lives and hence determine the order of the reaction.
    • Find the first and second half-lives by determining when the concentrations halve using the graph:
  Change in [reactant]
(x10-4 mol dm-3)
Half-life
(s)
First half-life 5.80 - 2.90 470 - 0 = 470
Second half-life 2.90 - 1.45 920 - 470 = 450

 

    • Determine the reaction order
      • It is a first-order reaction
      • The successive half-lives remain reasonably constant (around 450 seconds) throughout the reaction

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Richard

Author: Richard

Expertise: Chemistry

Richard has taught Chemistry for over 15 years as well as working as a science tutor, examiner, content creator and author. He wasn’t the greatest at exams and only discovered how to revise in his final year at university. That knowledge made him want to help students learn how to revise, challenge them to think about what they actually know and hopefully succeed; so here he is, happily, at SME.