Effect of Temperature on the Rate Constant
- At higher temperatures, a greater proportion of molecules have energy greater than the activation energy
- Since the rate constant and rate of reaction are directly proportional to the fraction of molecules with energy equal or greater than the activation energy, then at higher temperatures:
- The rate constant increases
- The rate of reaction increases
- The relationship between the rate constant and the temperature is given by the following equation:
-
- Where:
- ln k = natural logarithm of the rate constant
- A = constant related to the collision frequency and orientation of the molecules
- Ea = activation energy (joules, J)
- R = gas constant (8.31 J K-1 mol-1)
- T = temperature (kelvin, K)
- Where:
- A varies only a little bit with temperature, it can be considered a constant
- Ea and R are also constants
- A graph of ln k against gives a line with an equation of the form y = mx + c
-
- Where:
- y = ln k
- x =
- m = (the gradient)
- c = ln A (the y-intercept)
- Where:
- The equation shows that an increase in temperature (higher value of T) gives a greater value of ln k (and therefore a higher value of k)
- Since the rate of the reaction depends on the rate constant (k) an increase in k also means an increased rate of reaction
Example graph of ln k over 1/T
The graph of ln k over 1/T is a straight line with gradient -Ea/R
Examiner Tip
You are not required to learn this equation however it is helpful in understanding the effects of temperature on the rate constant.